why do MySQL displays the same column twice? - php

Question

Hello every {body] !
I have a simple "members" table to which I normally add rows with the function bellow.
The problem is that when I call the read function, it returns each column to me twice. Like this:
The weirdest thing is that all the columns are correct except "phone", it returns me '1' instead of an empty string.
Can anybody help me please ?
Here is the read function:
function db_read($columnToRead, $table, $targetColumn, $targetValue) {
//connecting to database
include('dbConnection.php');
//reading data
$result = $tilelli->prepare('SELECT '.$columnToRead.' FROM '.$table.' WHERE '.$targetColumn.' = ? LIMIT 1');
if ($result->execute(array($targetValue))) {
return $result->fetch();
} else {
return "Accès à la base de données refusé!";
}
}
And here is the calling method:
//reading member
$member = db_read("*", "members", "link", $_SESSION["member"]["link"]);
print_r($member);
exit;

Answer 1

#BoykeFerdinandes
Yes, when I print_r($member), it displays the phone correctly, but look at the web page :
PHP code
HTML result
Here is the "info()" function:
//inserting a profile info
function info($svg, $text, $buttonHref, $buttonLabel, $rounded = false, $previewable = false, $notif = "") {
$style = "";
$class = "";
$notification = '<span class="notifCounter">'.$notif.'</span>';
if ($rounded)
$style = 'style="border-radius: 50%;"';
if ($previewable)
$class = ' previewable';
echo '<div class="info">
<p class="info_icon_container">
<img src="'.$svg.'" class="info_icon'.$class.'" '.$style.' />
</p>
<p class="info_text">
'.$text.'
</p>
<p class="info_alter" onclick="window.location=\''.$buttonHref.'\';">
'.$buttonLabel.$notification.'
</p>
</div>';
}

Answer 2

Sorry friends, this is a stupid typo. I put (=!) Instead of (!=) In the php code.
$phone = "Aucun numéro de téléphone";
if ($member["phone"] =! "")
$phone = $member["phone"];