this is my input
<input type="text" name="quantity" id="quantity" value="1" />
this is my href link
<a href="UserOrderProduct.php?id=<?php echo $Pid; ?>
&price=<?php echo $Price; ?>&quantity=">add</a>
how to write it in the href and please ignore the
<?php echo $Pid; ?>&price=<?php echo $Price; ?>
this is because i get the id already from the database but only the quantity not really how to get it, can teach me?
If you have a form where you get the "quantity" value as it looks from your code:
<input type="text" name="quantity" id="quantity" value="1" />
if you use the "GET" method
<FORM method='get' action='next_script.php'>
all the values will be in the address, otherwise, if you POST the values you'll get them in the next script via $_POST array.
If you need to pass one or more couples variable=value between different scripts the best solution is to use PHP sessions.
You just need to add at the beginning of each script:
session_start();
and put your_variable and your_value as:
$_SESSION['your_variable'] = your_value;
or
$_SESSION['session_variable'] = $your_variable;
In such a way data are not visible on the link and you can access them anywhere you like provided that you keep the session_start() command at the beginning of each php page.
If you have html...
<form method="post" action="phpfile.php">
<input type="text" name="quantity" id="quantity" value="1" />
<input type="submit" value="send">
</form>
...in your phpfile.php you can retrieve the value of quantity like this:
<?php
$qty = $_POST['quantity'];
?>
<a href="UserOrderProduct.php?id=<?php echo $Pid; ?>
&price=<?php echo $Price; ?>&quantity=<?php echo $qty;?>">add</a>
Related
html:
<form method="GET">
<input type="text" name="k" id="header-search" value="<?=$_GET["k"];?>"/>
<input type="submit" id="header-submit" value="" />
</form>
When current url is:
https://example.com/search/cats?b=5
After click on submit button it remove b query and show like this:
https://example.com/search/cats?k=sometext
But i want this result:
https://example.com/search/cats?b=5&k=sometext
I have other query like b, d and also c maybe add more in future, so this is not a static, maybe url have b maybe d or maybe c or maybe all together or maybe no one.
I tried this but looks like no changes:
action="<?=$_SERVER['REQUEST_URI'];?>"
You can add the variables inside hidden inputs:
<form method="GET">
<?php if(isset($_GET['b']){ ?>
<input type="hidden" name="b" value="<?=$_GET["b"];?>"/>
<?php } ?>
<input type="text" name="k" id="header-search" value="<?php echo isset($_GET["k"]) ? $_GET["k"] : '';?>"/>
<input type="submit" id="header-submit" value="" />
</form>
However this solution will not work very well if you have many different types of variables that may or may not exist all the time. If you add all the variables as hidden, they will all be visible when you submit the form. To prevent this, you will need to check if the variables are isset() and only print them if they are.
Here is a solution that uses hidden fields and handles any amount of get parameters:
<form method="GET">
<?php
foreach($_GET as $key => $value){
// do not make a hidden input for k, there is already a text input for k
if($key != 'k'){
echo '<input type="hidden" name="'.$key.'" value="'.$value.'"/>';
}
}
?>
<input type="text" name="k" id="header-search" value="<?php echo isset($_GET["k"]) ? $_GET["k"] : '';?>"/>
<input type="submit" id="header-submit" value="" />
</form>
I was wondering if it was possible to take HTML user input using PHP (preferably the ID or something I can use numbers in) and to save confusion just echo it back.
So I have some example code here:
<input type="number" maxlength="3" name="test" id="1">
<input type="number" maxlength="3" name="test" id="2">
<input type="number" maxlength="3" name="test" id="2">
What I was looking for is a way where I could use their input and well.... echo it back for now.
if you already know how to submit a form you can use php on the other side like this to echo it out
<form method="POST" action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']); ?>">
<input type="text" name="name"><br>
<input type="submit" name="submit" value="Submit Form"><br>
</form>
<?php
if (isset($_POST['name'])){
$userinput = $_POST['name'];
echo $userinput;}
?>
in your example all three inputs are named "test" so youll need a different name for each one. My example above uses the "name" of the input to capture it. If your using "GET" change my $_POST['name'] to $_GET['name']
Which method did you use for these inputs? Name them differently, then retrieve the data with:
<?php echo $_GET['test1']; ?>
<?php echo $_GET['test2']; ?>
<?php echo $_GET['test3']; ?>
If you used POST type in the input method, then switch for:
<?php echo $_POST['test1']; ?>
<?php echo $_POST['test2']; ?>
<?php echo $_post['test3']; ?>
When a user takes a quiz, their score is captured in the value $grade, which displays fine on the quiz's home page. But if I change the form action to forward the user to a new page (grade.php), $grade loses its value.
How can I capture the value and display it on the next page? The values for PreviousURL and user_token display...
<form action="grade.php" method="post" id="quiz">
<input type="hidden" name="PreviousURL" id="url" />
<input type="hidden" name="user_token" value="<?php echo $_SESSION['user_token']; ?>" />
<input type="submit" value="Submit Quiz" />
</form>
So I tried this, but it doesn't work...
<input type="hidden" name="grade" value="<?php echo $_SESSION['grade'] ?>" />
on grade.php make sure to start the file with
session_start();
Based on your question, I assume that you did not start the session on grade.php. There is not much information about the file
If you don't start the session the values of $_SESSION get destroyed
You should not save form values in $_SESSION as form values are already in $_POST superglobal.
You can do it like
<form action="grade.php" method="post" id="quiz">
<input type="hidden" name="PreviousURL" id="url" />
<input type="hidden" name="user_token" value="<?php echo isset($_POST['user_token']) ? $_POST['user_token'] : '' ; ?>" />
<input type="submit" value="Submit Quiz" />
</form>
So basically it test if there is a value in user_token field it will apply that value other wise it will set to '' (nothing). If you are not familiar with the ternary operator syntax please refer to http://php.net/manual/en/language.operators.comparison.php
Updated Part:
// Your form page goes like
<?php session_start();
print_r($_SESSION); // If there is a session your form should show the value of user_token
// Rest of the script + html
?>
// grade.php
<?php session_start();
// do a print_r to see if you are receving session variables by
print_r($_SESSION);
Well, I have 2 php files. The first one user form.php has an html form to collect user inputs and send those data to other php file mysql_insert.php via POST method.
The problem is that along with 6 user inputs, I also have to transfer one more variable count(as discussed in code below) which is not input from user.
I tired following approach:
user form.php--->
<?php
$count=file_get_contents("cnt.txt","r");
$count=$count+1;
echo"Welcome!<br/>You are student number $count.<br/>";
?>
<html>
<p>Fill in the following information to save your marksheet to the database:</p><br/>
<form action="mysql_insert.php" method="POST">
Name:<input type="text" name="name" value=""/><br/><br/>
Marks(out of 100)<br/>
Subject 1:<input type="text" name="sub1" value=""/><br/>
Subject 2:<input type="text" name="sub2" value=""/><br/>
Subject 3:<input type="text" name="sub3" value=""/><br/>
Subject 4:<input type="text" name="sub4" value=""/><br/>
Subject 5:<input type="text" name="sub5" value=""/><br/><br/>
<p name="count" value="$count"></p>
<input type="submit" value="Submit"/>
</form>
</html>
I simply named an empty P element as count and set its value as $count to send it along with input variables(correct me if there is something wrong here, I am very novice to php).
And on the receiving end I used following code:
mysql_insert.php--->
<?php
require("connect.php");
$name=$_POST['name'];
$s1=$_POST['sub1'];
$s2=$_POST['sub2'];
$s3=$_POST['sub3'];
$s4=$_POST['sub4'];
$s5=$_POST['sub5'];
$count=$_POST['count'];
.
.
.
?>
Now on the line $count=$_POST['count']; the browser is throwing the error:
Notice: Undefined index: count in C:\xampp\htdocs\Vikas-117-PHP\level 3\mysql_insert.php on line 10
It seems the count is not being posted to this file.
Please guide me where I am wrong.
P.S.: I can of course use the file_get_contents() in the mysql_insert.php and get the count value directly in this file, but I am considering that way as my last option.
So please help if the non user-input variable can be posted via forms???
Thanks a million!!!
you have to put your $count variable in a hidden field in your form.. The data which are put in form inputs only get posted in form submit..
<input type="hidden" name="count" value="<?php echo $count ?>">
<p name="count" value="$count"></p>
you can not use directly any html tag for post data only use html form fields for posting data.
for use html tag values post you need to use js/ajax/php
<p name="count"><?php echo $count;?></p>
or better you use
<textarea name="count"><?php echo $count;?></textarea>
or for data not showing use hidden field
and get by name this p value or use class or id for get and post data using ajax
<p name="count" value="$count"></p>
This is not an input element so you cant post directly. You can however use jquery to get the value and POST using js.
You need to have the value inside input type text or hidden if you want to do the way you are doing now.
Change this line : <p name="count" value="$count"></p>
to the : <input type="hidden" name="count" value="<?=$count?>" />
You can use hidden elements like the following
use
<input type="hidden" value="<?php echo $count; ?>" name="count"/>
instead of
<p name="count" value="$count"></p>
Instead of
<p name="count" value="$count"></p>
Use
<input type="hidden" name="count" value="<?php echo $count;?>">
this line will not work : <p name="count" value="$count"></p>
you can use <input type="hidden" name="count" value="<?php echo $count; ?>" />
I am creating a faq panel for there can be multiple answers for question and i want to take the answer id .because i am storing comment by answer id
the problem is that how to sent the $answer_id to the comment_submit_process.php and how to recognize the answer ?
$selected_ques= mysql_prep($_GET['ques']);
$query = "SELECT * FROM formanswer where question_id = {$selected_ques}";
$ans= mysql_query($query);
if($ans){
while($answer = mysql_fetch_array($ans))
//here is the form
<form id="add-comment" action="comment_submit_process.php" >
<textarea class="comment-submit-textarea" cols="78" name="comment" style="height: 64px;"></textarea>
<input type="submit" name="submitbutton" value="Add Comment" class="comment-submit-button" >
<br> <?php
$ans_id= $answer['id']; //i am fatching the $answer['id'] from database
?>
<input type="hidden" name="ques" value="<?php echo $_GET['$ans_id'] ?>" />
<span class="counter ">enter at least 15 characters</span>
<span class="form-error"></span>
</form>
<?php }} ?>
You might have typo here !! it should be..
<input type="hidden" name="ques" value="<?php echo $ans_id; ?>" />
Other thing, you can add get param to action link it self.
<form id="add-comment" action="comment_submit_process.php?<?php echo $answer['id']; ?>" >
Instead of setting the ans_id, every time to the hidden field .
Generate a string of ans_id seperated with "," until while loop ends append the string and assign that value to the hidden field and in form action page you can get that value and generate van array from that string with delimiter ",".Now you can have the array of ans_id in your form action page
$answer_array = "nothing";
while($answer = mysql_fetch_array($ans))
{
if( $answer_array == "nothing")
$answer_array = $answer;
else
$answer_array .= ",".$answer;
}
<input type="hidden" name="answer_arr" value="<?=$answer_array?>">
In Form action page you can get that hidden value
$ans_array= explode(",",$_GET['answer_arr']);
You can echo answer_id in form action tag as additional parameter like this:
<form id="add-comment" action="comment_submit_process.php?ans_id=$ans_id" >
//Your stuff here
</form>
in comment_submit_process.php you can identify answer by
$ans_id=$_GET['ans_id'];
You can do further processing by using $ans_id
Edit:
change this line:
<input type="hidden" name="ques" value="<?php echo $_GET['$ans_id'] ?>"
to:
<input type="hidden" name="ques" value="<?php echo $ans_id; ?>" />
so that value of that field would be $ans_id fetched from DB.