NGINX with slashes after index.php - php

Question

I am trying to get URLs that looks like https://my.site.com/index.php/user/login to work on nginx.
From what I understand about server blocks, nginx thinks that index.php/user/login are either a path or a directory, so it doesn't process them correctly and dies with a 404.
My server block's try file looks like this:
location / {
# First attempt to serve request as file, then
# as directory, then fall back to displaying a 404.
#try_files $uri $uri/ =404;
try_files $uri $uri/ /index.php$is_args$args;
# Enable CORS
add_header 'Access-Control-Allow-Origin' '*' always;
add_header 'Access-Control-Expose-Headers' 'Content-Length';
}
What am I missing? All I need nginx to do is "aha! index.php is right there; my job is done", then the framework will realize that "ha! the whole URL is https://my.site.com/index.php/user/login; that means they want me to run the user controller, then load the login action" and that's it

Answer 1

I use Laravel which defaults to similar rewrites (no index.php in the url)
Here is a final structure that works well,
Explained here
server {
listen 80 default_server;
listen [::]:80 default_server ipv6only=on;
root /var/www/laravel/public;
index index.php index.html index.htm;
server_name server_domain_or_IP;
location / {
try_files $uri $uri/ /index.php?$query_string;
}
location ~ \.php$ {
try_files $uri /index.php =404;
fastcgi_split_path_info ^(.+\.php)(/.+)$;
fastcgi_pass unix:/var/run/php5-fpm.sock;
fastcgi_index index.php;
fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
include fastcgi_params;
}
}