Insert data from forms inside a while loop php - php

Good day. I just wanna ask how can I insert the data from the forms generated from a while loop. This is what I tried so far. I added a loop where they will have different id or names but when I tried on clicking the button the first form is the only one working. Thank you so much in advance.
<?php
include "../config/dbconfig.php";
$data['productCode'] = "1"; // sample data
$stmt = $conn->prepare("SELECT * FROM tbl_category");
//$stmt->bind_param("i", $data['productCode']);
$stmt->execute();
$result = $stmt->get_result();
$i = 1;
while ($stuff = $result->fetch_assoc()) {
?>
<div class="col-sm-6" style="margin-top:20px;">
<div class="card">
<div class="card-header"><?php echo $stuff['categoryname']; ?>
</div>
<div class="card-body outermydiv">
<div class="myDIV">
<form method="POST" name="itemform" action="">
<div class="form-row">
<div class="col-5">
<input type="text" class="form-control" name="name[<?php echo $i; ?>]" id="itemname[<?php echo $i; ?>]" placeholder="Item name" required autocomplete="off">
</div>
<div class="col">
<input type="number" class="form-control" name="cost[<?php echo $i; ?>]" id="itemcost[<?php echo $i; ?>]" placeholder="Cost" required>
</div>
<div class="col">
<input type="number" class="form-control" name="price[<?php echo $i; ?>]" id="itemprice[<?php echo $i; ?>]" placeholder="Price" required>
<input type="hidden" class="form-control" name="code[<?php echo $i; ?>]" id="forcatcode[<?php echo $i; ?>]" value="<?php echo $stuff['categorycode'] ?>">
</div>
<div class="col">
<button type="submit" class="btn btn-success" name="btnsaveitem" id="btnsaveitem">Save</button>
</div>
<?php $i++; ?>
<input type="hidden" name="count" value="<?php echo $i; ?>" />
</div>
</form>
</div>
<br>
</div>
</div>
</div>
<?php
}
?>
and here is my insert code
<?php
if (isset($_POST['btnsaveitem'])) {
$count = $_POST['count'];
for ($i = 1; $i < $count; $i++) {
//$code = $_POST['code'][$i]; // check empty and check if interger
$foritemname = $_POST['name'][$i]; // check empty and strip tags
//$qty = $_POST['qty'][$i]; // check empty and check if interger
$stmt = $conn->prepare("INSERT INTO tbl_items(`itemname`) VALUES ('".$foritemname."')");
//$stmt->bind_param("iss",$name);
$stmt->execute();
}
}
?>

Starting by rewriting your form...
You don't need $i for anything, but I'll leave the declaration in case you want it for something else.
Don't submit array type data, each form will submit its own set of fields.
It probably makes more sense to add $stuff['categorycode'] as the value of each submit to avoid needing the hidden field. I'll leave it your way for now.
Form:
foreach ($stmt->get_result() as $i => $stuff) { ?>
<div class="col-sm-6" style="margin-top:20px;">
<div class="card">
<div class="card-header"><?php echo $stuff['categoryname']; ?></div>
<div class="card-body outermydiv">
<div class="myDIV">
<form method="POST">
<div class="form-row">
<div class="col-5">
<input type="text" class="form-control" name="name" placeholder="Item name" required autocomplete="off">
</div>
<div class="col">
<input type="number" class="form-control" name="cost" placeholder="Cost" required>
</div>
<div class="col">
<input type="number" class="form-control" name="price" placeholder="Price" required>
</div>
<div class="col">
<button type="submit" class="btn btn-success" name="btnsaveitem">Save</button>
</div>
</div>
<input type="hidden" class="form-control" name="code" value="<?php echo $stuff['categorycode']; ?>">
</form>
</div>
<br>
</div>
</div>
</div>
<?php
}
Receiving script: (extend with additional fields as desired)
if (isset($_POST['btnsaveitem'])) {
$stmt = $conn->prepare("INSERT INTO tbl_items(`itemname`) VALUES (?)");
$stmt->bind_param("s",$_POST['name']);
$stmt->execute();
}
This is all untested code.

Related

Update Table Row Value with Post Button

I have some data in my mysql database which I am displaying in table using PHP like below
$requirement_qry="SELECT t1.*, t2.id as unit_id, t2.name as unit_name FROM `tbl_requirements`
t1 INNER JOIN tbl_units AS t2 on unit_type = t2.id AND project_id='".$_GET['project_id']."' AND user_id='".$userid."'";
$requirement_result=mysqli_query($mysqli,$requirement_qry);
<form action="" name="addeditcategory" method="post" class="form form-horizontal" enctype="multipart/form-data">
<input type="hidden" name="project_id" value="<?php echo $_GET['project_id'];?>" />
<div class="section">
<div class="section-body">
<div class="form-group">
<label class="col-md-3 control-label" >Project Name :-</label>
<div class="col-md-6">
<input type="text" name="name" id="name" value="<?php if(isset($_GET['project_id'])){echo $row['name'];}?> " class="form-control" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-3 control-label" >Location :-</label>
<div class="col-md-6">
<input type="text" name="location" id="location" value="<?php if(isset($_GET['project_id'])){echo $row['location'];}?> " class="form-control" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-3 control-label">Project Status :-</label>
<div class="col-md-6">
<select name="status" id="status" class="select2" disabled>
<?php if (!isset($_GET['project_id'])) { ?>
<option value="1">--Project Status--</option>
<?php } ?>
<option value="1" <?php echo $row['status'] == '1' ? 'selected' : ''; ?> >Open</option>
<option value="2" <?php echo $row['status'] == '2' ? 'selected' : ''; ?> >Closed</option>
</select>
</div>
</div>
<div class="form-group">
<div class="col-md-3">
<label class="control-label">Project Details :-</label>
</div>
<div class="col-md-6">
<textarea name="details" id="details" rows="4" class="form-control" disabled><?php echo stripslashes($row['details']);?></textarea>
</div>
</div>
<div class="form-group">
<div class="col-md-3">
<label class="control-label">Project Requirements :-</label>
</div>
<div class="col-md-6">
<table id="t01">
<thead>
<tr>
<th>#</th>
<th>Requirements</th>
<th>Required</th>
<th>Sent</th>
<th>Action</th>
</tr>
</thead>
<tbody>
<?php
$no = 1;
while ($row1 = mysqli_fetch_array($requirement_result))
{
$id = $row1['id'];
$unit_name = $row1['unit_name'];
echo '<input type="hidden" name="reqId" id= "reqId" value="'.$id.'" />';
echo '<tr>
<td>'.$no.'</td>
<td>'.$row1['name'].'</td>
<td>'.$row1['unit_required']." ".$unit_name.'</td>
<td><input type="number" id = "received" name = "received" value ="'.$row1['unit_received'].'"/></td>
<td><button type="submit" name="submit" class="btn btn-primary" style="padding:5px 10px;">Submit</button></td>
</tr>';
$no++;
}?>
</tbody>
</table>
</div>
</div>
</div>
</form>
Above code is properly displaying my data. I have one field value from row need to update using submit button. Its working fine if there only one row...if there multiple row, its not updating data of it except last row.
My submit code is like below
if(isset($_POST['submit']) and isset($_POST['project_id']))
{
$projectId = $_GET['project_id'];
$data = array(
'unit_received' => $_POST['received']
);
$unit_edit=Update('tbl_requirements', $data, " WHERE id = '".$_POST['reqId']."'");
print_r($unit_edit);
echo $unit_edit;
if ($unit_edit > 0)
{
$_SESSION['msg']="11";
header( "Location:view_open_project.php?project_id=".$_POST['project_id']);
exit;
}
}
I am little new in PHP, Let me know if someone can help me for solve the bug.
Thanks a lot :)
As #Saji has already stated, you are replicating your name through the loop.You should rather use
echo '<input type="hidden" name="reqId[]" id= "reqId" value="'.$id.'" />';
Note the [] brackets that were appended so that you create an array of names.
To update, you need a loop like
for($i=0;$i<count($_POST['reqId']);$i++){
$unit_edit=Update('tbl_requirements', $data, " WHERE id = '".$_POST['reqId'][$i]."'");
}
What you can do is just create a hidden form where you will keep original elements. When the save button click you just find the actual value and set this to the elements inside hidden form, then trigger the submit button inside hidden form.
Note the changes I have done on your code.
1.Removed the hidden element reqId from inside loop.
2.Given a class name to the button inside loop and changed the button type from submit to button. Added data attribute data-id="'.$id.'".
3.The input received inside the loop has given unique id and name by concatenated the $id.
4.Created hidden form with hidden input in it. It has your actual input names.
5.Created a jquery function to attach click event to the button inside loop.
6.Moved the hidden element project_id to inside hidden form.
Now see the below code for more details. Hope this will help you..
<form action="" name="addeditcategory" method="post" class="form form-horizontal" enctype="multipart/form-data">
<input type="hidden" name="project_id" value="<?php echo $_GET['project_id']; ?>"/>
<div class="section">
<div class="section-body">
<div class="form-group">
<label class="col-md-3 control-label">Project Name :-</label>
<div class="col-md-6">
<input type="text" name="name" id="name" value="<?php if (isset($_GET['project_id'])) {
echo $row['name'];
} ?> " class="form-control" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-3 control-label">Location :-</label>
<div class="col-md-6">
<input type="text" name="location" id="location" value="<?php if (isset($_GET['project_id'])) {
echo $row['location'];
} ?> " class="form-control" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-3 control-label">Project Status :-</label>
<div class="col-md-6">
<select name="status" id="status" class="select2" disabled>
<?php if (!isset($_GET['project_id'])) { ?>
<option value="1">--Project Status--</option>
<?php } ?>
<option value="1" <?php echo $row['status'] == '1' ? 'selected' : ''; ?> >Open</option>
<option value="2" <?php echo $row['status'] == '2' ? 'selected' : ''; ?> >Closed</option>
</select>
</div>
</div>
<div class="form-group">
<div class="col-md-3">
<label class="control-label">Project Details :-</label>
</div>
<div class="col-md-6">
<textarea name="details" id="details" rows="4" class="form-control"
disabled><?php echo stripslashes($row['details']); ?></textarea>
</div>
</div>
<div class="form-group">
<div class="col-md-3">
<label class="control-label">Project Requirements :-</label>
</div>
<div class="col-md-6">
<table id="t01">
<thead>
<tr>
<th>#</th>
<th>Requirements</th>
<th>Required</th>
<th>Sent</th>
<th>Action</th>
</tr>
</thead>
<tbody>
<?php
$no = 1;
while ($row1 = mysqli_fetch_array($requirement_result)) {
$id = $row1['id'];
$unit_name = $row1['unit_name'];
echo '<tr>
<td>' . $no . '</td>
<td>' . $row1['name'] . '</td>
<td>' . $row1['unit_required'] . " " . $unit_name . '</td>
<td><input type="number" id = "received' . $id . '" name = "received' . $id . '" value ="' . $row1['unit_received'] . '"/></td>
<td><button type="button" name="submit" class="btn btn-primary submit-click" data-id="' . $id . '" style="padding:5px 10px;">Submit</button></td>
</tr>';
$no++;
} ?>
</tbody>
</table>
</div>
</div>
</div>
</form>
<form action="" id="addeditcategory_temp" name="addeditcategory_temp" method="post" class="form form-horizontal" enctype="multipart/form-data" style="display:none;>
<input type="hidden" name="project_id" value="<?php echo $_GET['project_id']; ?>"/>
<input type="hidden" name="reqId" id= "reqId" value="" />
<input type="number" id = "received" name = "received" value ="">
<button id="submitButton" type="submit" name="submit" class="btn btn-primary" style="padding:5px 10px;">
</form>
<script>
$(document).ready(function(e){
$('.submit-click').off('click').on('click', function(e){
var reqId = $(this).data('id');
var received = $('#received'+reqId).val();
var form = $('#addeditcategory_temp');
form.find('#reqId').val(reqId);
form.find('#received').val(received);
form.find('#submitButton').trigger('click');
})
});
</script>

Update code wont work in php and mysql

Hi Guys could please check my code I have written, the problem is it won't update the data in DB, it just reloading and not giving any error.
Here is my update.php
if (isset($_POST['update']) && isset($_POST['update']) != "") {
$name = $_POST['c_name'];
$mobile = $_POST['c_mob'];
$dDate = $_POST['d_date'];
$frame = $_POST['frame'];
$size = $_POST['size'];
$lense = $_POST['lense'];
$descr = $_POST['descr'];
$paid = $_POST['paid'];
$remains = $_POST['remains'];
$refer = $_POST['c_refer'];
}
$setquery = "UPDATE `dep_sale` SET c_name='$name', c_mob='$mobile', d_date='$dDate', frame='$frame', size='$size', lense='$lense', descr='$descr',c_refer='$refer', paid='$paid', remains='$remains' WHERE id='".$_POST["id"]."'";
mysqli_query($link, $setquery);
header("location: reports.php");
And here is the HTML
<form method="POST" action="update.php">
<div class="row">
<div class="col-lg-4 col-md-4">
<input type="hidden" name="id" />
<input type="text" class="form-control" value="<?php echo $row['c_name']; ?>" required id="c_name" name="c_name" placeholder="Name..."/>
</div>
<div class="col-lg-4 col-md-4">
<input type="phone" class="form-control" value="<?php echo $row['c_mob']; ?>" required id="c_mob" name="c_mob" placeholder="Mobile..."/>
</div>
<div class="col-lg-4 col-md-4">
<input type="text" class="form-control" value="<?php echo $row['d_date']; ?>" required id="d_date" name="d_date" onfocus="(this.type='date')" placeholder="Delivery Date..."/>
</div>
</div>
<br>
<div class="row">
<div class="col-lg-4 col-md-4">
<input type="text" class="form-control" value="<?php echo $row['frame']; ?>" required id="frame" name="frame" placeholder="Frame..."/>
</div>
<div class="col-lg-4 col-md-4">
<input type="text" class="form-control" value="<?php echo $row['size']; ?>" required id="size" name="size" placeholder="Size..."/>
</div>
<div class="col-lg-4 col-md-4">
<input type="text" class="form-control" value="<?php echo $row['lense']; ?>" required id="lense" name="lense" placeholder="Lense..."/>
</div>
</div>
<br>
</form>
There is no problem in connection because i am fetching and inserting data perfectly.Please help me guys.Thanks
To see the errors set the following at first lines:
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
Your if is wrong. Try this:
if (isset($_POST['update']) && $_POST['update'] != "") {
Or more shorter version
if (!empty($_POST['update'])) {
Hope this helped you!

How to insert data once for two input has same name

Please have a look
Website interface
I only can insert these data with click both of the submit <button>.
I wish to use only one submit <button> to submit these data twice.
Here is my code.
As u can see, I for loop this <form>
<?php
for($x=1; $x<=2; $x++)
{
?>
<div class="col-lg-6">
<label>Passenger <?php echo $x ?> </label>
<form role="form" method='post'>
<div class="form-group">
<label>Title</label>
<label class="radio-inline">
<input type="radio" name="gander" value="Mr" checked>Mr
</label>
<label class="radio-inline">
<input type="radio" name="gander" value="Ms">Ms
</label>
</div>
<div class="form-group">
<label>Enter name of Passenger</label>
<input class="form-control" name='name'>
</div>
<div class="form-group">
<label>Enter Passenger Id <?php echo $x ?></label>
<input class="form-control" placeholder="960529-01-6925" name='ic'>
</div>
<button type="submit" class="btn btn-default" name="addbtn" method="post">Submit Button</button>
</form>
</div>
<?php
}
?>
Here is the isset button code
<?php
if(isset($_POST["addbtn"]))
{
$ganderphp = $_POST["gander"];
$namephp = $_POST["name"];
$icphp = $_POST["ic"];
$sql = "INSERT INTO `passenger_data`(`pass_gender`,`pass_name`,`pass_ic`,`Username`) VALUES ('$ganderphp','$namephp','$icphp','$username')";
if (mysqli_query($conn, $sql)) {
echo $sql;
}else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
}
?>
Its not user friendly because user only can submit data on one of the form first.
I did try to take the submit button out of the looping, but its not working.
I need a solution to make user can submit only once for all these data.
Base on some research, maybe array[] and for each can done this but i just don know how to use it.
Appreciate for any answer.
First of all, take the <form> and submit <button> element outside of the for loop, and then change the name attributes like this:
name="gander[<?php echo $x; ?>]"
name='name[<?php echo $x; ?>]'
and
name='ic[<?php echo $x; ?>]'
So your HTML form would be like this:
<div class="col-lg-6">
<form role="form" method='post'>
<?php
for($x=1; $x<=2; $x++){
?>
<label>Passenger <?php echo $x ?> </label>
<div class="form-group">
<label>Title</label>
<label class="radio-inline">
<input type="radio" name="gander[<?php echo $x; ?>]" value="Mr" checked>Mr
</label>
<label class="radio-inline">
<input type="radio" name="gander[<?php echo $x; ?>]" value="Ms">Ms
</label>
</div>
<div class="form-group">
<label>Enter name of Passenger</label>
<input class="form-control" name='name[<?php echo $x; ?>]'>
</div>
<div class="form-group">
<label>Enter Passenger Id <?php echo $x ?></label>
<input class="form-control" placeholder="960529-01-6925" name='ic[<?php echo $x; ?>]'>
</div>
<?php
}
?>
<button type="submit" class="btn btn-default" name="addbtn" method="post">Submit Button</button>
</form>
</div>
And after submitting, process your form like this:
if(isset($_POST["addbtn"])){
for($x = 1; $x <= 2; ++$x){
$ganderphp = $_POST["gander"][$x];
$namephp = $_POST["name"][$x];
$icphp = $_POST["ic"][$x];
// construct the query and execute it
}
}
Sidenote: Learn about prepared statements because right now your query is susceptible to SQL injection. Also see how you can prevent SQL injection in PHP.

Adding outputted table row to another table using codeigniter

Outputted a row from a table ,am now trying to add some of the contents to another table using a form which is inside the outputted row but its not inserted to the database. am not getting an error.
Here is my view
<?php
foreach ($h->result() as $row)
{?>
<div class="row invoice-info">
<div class="col-sm-1 invoice-col">
</div>
<div class="col-sm-3 invoice-col">
<img src="<?php echo base_url()?>/res/images/goods/1.png">
</div>
<div class="col-sm-4 invoice-col">
<address>
Description: <?php echo $row->description;?><br>
Location Address: <?php echo $row->l_area;?><br>
Destination Address: <?php echo $row->d_area;?><br>
Date: <?php echo $row->dom;?><br>
Time: <?php echo $row->tom;?>
</address>
</div>
<div class="col-sm-2 invoice-col">
<address>
</address>
</div><!-- /.col -->
<div class="col-sm-2 invoice-col">
<form action="<?php echo site_url('truckeraccount_ctrl/bid'); ?>" method="post">
<input type="hidden" class="form-control" name="truckerid" value="<?php
$truckerid = $this->session->userdata('truckerid');
echo $truckerid; ?>" required>
<input type="hidden" class="form-control" name="luggage_id" value="<?php echo $row->luggage_id;?>" placeholder="Bid">
<input type="text" class="form-control" name="bid_amount" placeholder="Bid">
<button type="submit" class="btn bg-orange btn-flat margin">Place Bid</button>
</div>
</div>
My model
function bid($data){
$query=$this->db->update('bids',$data);
return $query;
}
My controller
public function bid(){
$this->load->database();
$this->load->model('Truckeraccount_model');
$data['a']=$this->Truckeraccount_model->accepted_bid();
$data['b']=$this->Truckeraccount_model->picked_loads();
$data['h']=$this->Truckeraccount_model->loads();
$data['g']=$this->Truckeraccount_model->notification();
$data['i']=$this->Truckeraccount_model->return_loads();
$data['accepted_return_loads']=$this->Truckeraccount_model->accepted_return_loads();
$data['bid_amount']=$this->Truckeraccount_model->bid_amount(); $this->load->library('form_validation');
$this->form_validation->set_error_delimiters('<div class="error">', '</div>');
$this->form_validation->set_rules('bid_amount', 'bid_amount', 'required|min_length[1]|max_length[50]');
if ($this->form_validation->run() == FALSE) {
$this->load->view('header');
$this->load->view('truckeraccount_view',$data);
$this->load->view('footer');
} else {
$data = array(
'truckerid' => $this->input->post('truckerid'),
'luggage_id' => $this->input->post('luggage_id'),
'bid_amount' => $this->input->post('bid_amount'),
);
$this->Truckeraccount_model->bid($data);
$data['message'] = '';
redirect('truckeraccount_ctrl/');
}
}
<form action="<?php echo site_url('truckeraccount_ctrl/bid'); ?>" method="post">
<input type="hidden" class="form-control" name="truckerid" value="<?php
$truckerid = $this->session->userdata('truckerid');
echo $truckerid; ?>" required>
<input type="hidden" class="form-control" name="luggage_id" value="<?php echo $row->luggage_id;?>" placeholder="Bid">
<input type="text" class="form-control" name="bid_amount" placeholder="Bid">
<button type="submit" class="btn bg-orange btn-flat margin">Place Bid</button>
</form>

wrong <select> value when editing php form

I really hope you can help me.
I've done a form, where I can opt if a client I'm adding to the database is "Active or "Inactive", using a dropdown select box.
My code saves all the data correctly to the datbase, but when I want to edit the client, the option displays always as "Active", ignoring the value from the database.
I have 2 files:
edita_clientes.php - the form where I can edit the clients values
salvar_edicao.php - the file that saves the edition.
Here are the codes:
edita_clientes.php:
<?php
#ini_set('display_errors', '1');
error_reporting(E_ALL);
$id = $_GET["id_cliente"];
settype($id, "integer");
mysql_connect("localhost", "root", "");
mysql_select_db("sistema");
$resultado = mysql_query("select * from tabela where id_cliente = $id");
$dados = mysql_fetch_array($resultado);
mysql_close();
?>
<form id="edita_pj" name="edita_pj" method="post" action="salvar_edicao.php">
<input type="hidden" name="id_cliente" id="id_cliente" value="<?php echo $id;?>" />
<div class="box-body">
<div class="form-group">
<label>Razão Social</label>
<input type="text" name="razao" id="razao" class="form-control" value="<?php echo $dados["razao"];?>" />
</div>
<div class="form-group">
<label>Nome Fantasia</label>
<input type="text" name="fantasia" id="fantasia" class="form-control" value="<?php echo $dados["fantasia"];?>" />
</div>
</div>
<div class="box-body">
<div class="form-group">
<label>CNPJ</label>
<input type="text" name="cnpj" id="cnpj" class="form-control" data-inputmask='"mask": "999.999.999-99"' data-mask value="<?php echo $dados["cnpj"];?>">
</div>
</div>
<div class="box-body">
<div class="row">
<div class="col-xs-9">
<label>Logradouro</label>
<input type="text" name="logradouro" id="logradouro" class="form-control" value="<?php echo $dados["logradouro"];?>">
</div>
<div class="col-xs-3">
<label>Número</label>
<input type="text" name="numero" id="numero" class="form-control" value="<?php echo $dados["numero"];?>">
</div>
</div>
</div>
<div class="box-body">
<div class="row">
<div class="col-xs-9">
<label>Bairro</label>
<input type="text" name="bairro" id="bairro" class="form-control" value="<?php echo $dados["bairro"];?>">
</div>
<div class="col-xs-3">
<label>CEP</label>
<input type="text" name="cep" id="cep" class="form-control" data-inputmask='"mask": "99999-999"' data-mask value="<?php echo $dados["cep"];?>">
</div>
</div>
</div>
<div class="box-body">
<div class="row">
<div class="col-xs-10">
<label>Cidade</label>
<input type="text" name="cidade" id="cidade" class="form-control" value="<?php echo $dados["cidade"];?>">
</div>
<div class="col-xs-2">
<label>UF</label>
<input type="text" name="uf" id="uf" class="form-control" value="<?php echo $dados["uf"];?>">
</div>
</div>
</div>
<div class="box-body">
<div class="row">
<div class="col-xs-9">
<label>E-mail</label>
<input type="text" name="email" id="email" class="form-control" value="<?php echo $dados["email"];?>">
</div>
<div class="col-xs-3">
<label>Telefone</label>
<input type="text" name="telefone" id="telefone" class="form-control" data-inputmask='"mask": "(99) 9999.9999"' data-mask value="<?php echo $dados["telefone"];?>"/>
</div>
</div>
</div>
<div class="box-body">
<div class="row">
<div class="col-xs-9">
<label>Contato</label>
<input type="text" name="contato" id="contato" class="form-control" value="<?php echo $dados["contato"];?>">
</div>
<div class="col-xs-3">
<label>Estado</label>
<select class="form-control" name="estado" id="estado" value=""><?php echo $dados["estado"];?>
<option>Ativo</option>
<option>Inativo</option>
</select>
</div>
</div>
<div class="form-group">
<label>Observações</label>
<textarea class="form-control" name="obs" id="obs" rows="6" ><?php echo $dados["obs"];?>
</textarea>
</div>
</div>
<div class="box-footer">
<button type="submit" name="Submit" class="btn btn-primary">Salvar</button>
</div>
</form>
salvar_edicao.php:
<?php
#ini_set('display_errors', '1');
error_reporting(E_ALL);
$razao = $_POST["razao"];
$fantasia = $_POST["fantasia"];
$cnpj = $_POST["cnpj"];
$logradouro = $_POST["logradouro"];
$numero = $_POST["numero"];
$bairro = $_POST["bairro"];
$cep = $_POST["cep"];
$cidade = $_POST["cidade"];
$uf = $_POST["uf"];
$email = $_POST["email"];
$telefone = $_POST["telefone"];
$contato = $_POST["contato"];
$estado = $_POST["estado"];
$obs = $_POST["obs"];
$id = $_POST["id_cliente"];
mysql_connect("localhost", "root", "");
mysql_select_db("sistema");
mysql_query("UPDATE tabela SET razao = '$razao', fantasia = '$fantasia', cnpj = '$cnpj', logradouro = '$logradouro', numero='$numero', bairro='$bairro', cep='$cep', cidade = '$cidade', uf='$uf', email = '$email', telefone = '$telefone', contato = '$contato', estado = '$estado', obs = '$obs' WHERE tabela.id_cliente = $id");
mysql_close();
header("Location: consulta.php");
?>
You need to add 'selected' to the option that you want to be selected, based on a value from the form/db. Here is an example using $value as the option value that you want selected.
<select class="form-control" name="estado" id="estado">
<option <?php echo $value == 'Ativo' ? selected : '' ?>>Ativo</option>
<option <?php echo $value == 'Inativo' ? selected : '' ?>>Inativo</option>
</select>
Also, your <select> tag does not require a 'value' element..
The HTML select element does not have a value attribute. For the select to do what you want you need to add the selected attribute to the option you want selected. It's always showing as 'Active' because that's the first option and it is the default.
The resulting post-php HTML will need to look something like this stripped back example for 'Inactive' to be selected.
<select>
<option>Active</option>
<option selected>Inactive</option>
</select>
Thank's for all the help!
The solution I've found was:
<?php
$resultado = mysql_query("select * from tabela where id_cliente = $id");
$dados = mysql_fetch_array($resultado);
$query = mysql_query("SELECT * FROM estado");
?>
And the html part:
<select class="form-control" name="estado" id="estado">
<option selected="selected"><?php echo $dados["estado"];?></option>
<option value="Ativo">Ativo</option>
<option value="Inativo">Inativo</option>
</select>

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