Fetch last row first in displayed array without using SELECT command? - php

Question

I have used foreach loop to display the rows in myphp database, however I would now like to display this in DESC order (display last row first) however research tells me not to use the SELECT command in arrays? is there another way? Many thanks.
index.php:
<?php
include("app/database/db.php");
$posts = selectAll('posts', ['published' => 1]);
?>
<?php foreach ($posts as $post): ?>
<div class="post">
<div class="col-lg-6">
<!-- HEADLINE -->
<h1><strong><?php echo $post['title']; ?></strong></h1>
<!-- TEXT BODY -->
<!-- <h4></?php echo $post['body']; ?></h4> displays the full body -->
<h4 class="mainbody"><?php echo html_entity_decode(substr($post['body'], 0, 100) . '...'); ?></h4>
<!-- IMAGE -->
<div class="col-lg-6">
<img src="<?php echo '/assets/images/' , $post['image']; ?>" style="width: 550px; height: 350px; object-fit: cover;">
</div>
</div>
<?php endforeach; ?>
db.php file:
<?php
function selectAll($table, $conditions = []) {
global $conn;
$sql = "SELECT * FROM $table";
if (empty($conditions)) {
$stmt = $conn->prepare($sql);
$stmt->execute();
$records = $stmt->get_result()->fetch_all(MYSQLI_ASSOC);
return $records;
} else {
$i = 0;
foreach ($conditions as $key => $value) {
if ($i === 0) {
$sql = $sql . " WHERE $key=?";
} else {
$sql = $sql . " AND $key=?";
}
$i++;
}
$stmt = executeQuery($sql, $conditions);
$records = $stmt->get_result()->fetch_all(MYSQLI_ASSOC);
return $records;
}
}
?>