This question already has answers here:
PHP multidimensional array search by value
(23 answers)
json_decode to array
(12 answers)
Closed 2 years ago.
So, I'm new to php and while testing some services, I have a JSON object:
{
"entry": [
{
"authorId": "#me",
"type": "USER"
},
{
"authorId": "514",
"type": "USER"
},
{
"authorId": "516",
"type": "USER"
}
],
"count": 3,
"totalResults": 3
}
and I need to assert that '#me' is part of this object. I tried something like:
$Obj->assertTrue(array_key_exists('#me', $response['entry']));
but it won't just work. Can someone give me a hint regarding this? Thank you
EDIT:
'#me' can be anywhere in the array, not on the first position and I'm asking this for a a test in codecept, so I need to an assert directly
You can loop through your result set to check it for each entry.
function checkEntries($object, $search) {
$object = json_decode($object, true);
foreach($object['entry'] as $entry) {
if ($entry['authorId'] == $search) {
return true;
}
}
return false;
}
Or you can use this:
PHP multidimensional array search by value
Related
This question already has answers here:
PHP multidimensional array search by value
(23 answers)
Closed 14 days ago.
I'm trying to filter array from DB and I've got this postman response:
{
"1": {
"id": "3",
"key": "emails_html_body_start",
"value": "value"
}}
How I can access to id, key, value?
My code here:
$start = array_filter($array, function ($var) {
return ($var['key'] == 'emails_html_body_start');
});
echo json_encode($start);
Your question is a bit unclear ... So the upper code is what is sent by the lower code snippet? So the cho json_encode($start); is what produces the upper json data?
If so, then you obviously need to json decode that data again to be able to access a property inside that structure:
<?php
$input = <<<JSON
{
"1": {
"id": "3",
"key": "emails_html_body_start",
"value": "value"
}
}
JSON;
$data = json_decode($input, true);
$output = $data[1]['id'];
print_r($output);
The output obviously is:
3
This question already has answers here:
How to find entry by object property from an array of objects?
(13 answers)
Closed 1 year ago.
I wonder how to access objects' values without a loop in a JSON file like this:
{
"adresse": "",
"longitude": "12.352",
"latitude": "61.2191",
"precision": "",
"Stats": [
{
"id": "300",
"carte_stat": "1154€",
},
{
"id": "301",
"carte_stat": "1172€",
},
{
"id": "302",
"carte_stat": "2293€",
},
],
}
I'd like to target for example the object with id '301'.
Using a loop I do like this:
foreach($result_json['Stats'] as $v) {
if ($v['id'] == "301") {
...
}
};
But How can I do without loop?
I tried things like this but in vain:
$result_json['Stats'][id='301']['carte_stat'];
$result_json['Stats']['id']->{'301'};
An alternative with array_filter.
Get the first occurence of id 301:
$json = json_decode($json, true);
$result = current(array_filter($json['Stats'], function($e) {
return $e['id'] == 301;
}));
print_r($result);
For/foreach will probably be faster. You shouldn't aim for "ligther code" when it will be a problem for readability or performance. Sometimes, more is less (problems).
You could index the Stats using array_column() to convert it. It's less efficient than a loop as it will first convert the entire array before you can access it by the id...
$stats = array_column($result_json['Stats'], "carte_stat", "id");
echo $stats['301'];
Note that I have to fix your JSON, but I assume this was due to chopping out data not needed for the question.
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 2 years ago.
Hi I am trying to get everything in within the [] brackets. I have tried everything I could find but no luck
{
"Items": [
{
"UID": "XXX-XXX",
"Code": "USD",
"CurrencyName": "US Dollar",
"CurrencyRate": 0.71428000,
"URI": "https://ar2.api.myob.com/accountright/XXX-XXX/GeneralLedger/Currency/XXX-XXX",
"RowVersion": "-6496407278109851648"
}
],
"NextPageLink": null,
"Count": 1
}
EDIT
My Code
$getsbCurrencyDetailsclass = new myobsbfunctions($_SESSION['access_token'],api_key);
$getsbCurrencyDetails = $getsbCurrencyDetailsclass->getResponsenew($cf_uri. "/GeneralLedger/Currency/?" .'$filter' ."=Code%20eq%20'{$docCurrencyType}'");
$getsbCurrencyDetails = json_decode($getsbCurrencyDetails);
$result=$getsbCurrencyDetails['Items'];
//print("<pre>".print_r($result,true)."</pre>");
echo $getsbCurrencyDetails
You need to convert the JSON into an array, then manipulate this array. Assuming the text is in $json:
$array=json_decode($json, true);
$result=$array['Items'];
EDIT
I forgot the second parameter to json_decode
This question already has answers here:
How to extract and access data from JSON with PHP?
(1 answer)
How can I get useful error messages in PHP?
(41 answers)
Closed 3 years ago.
I have a json that I need to filter a specific key and value from
the following json
{
"5": {
"Owner": "94EAC",
"Record":"0121ln"
},
"15": {
"Owner": "009AC",
"Record":"0120Pc"
},
"1": {
"Owner": "00G11A",
"Record":"000lPcn"
},
"199": {
"Owner": "00G1y9",
"Record":"01211cn"
},
"33": {
"Owner": "001AC",
"Record":"0121n"
}
}
I would like to be able to pass the first int and get back array for that number.
For example if I pass 15 I get
{
"Owner": "009AC",
"Record":"0120Pc"
}
I tried foreach loop but cannot set specific value for the first int
If I assign $data = json
then $date[15] didn't work
$data->15 also didn't work
I did also use the json decode and was able to print an array but wasn't able to get a single value
Any help would be great, I did spend all day and still cannot get an answer.
Thank you
Using Array:
$arr = json_decode($json, true);
print_r( $arr['15']);
Using Object:
$obj = json_decode($json);
print_r( $obj['15']);
Reference: json_decode
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 6 years ago.
I have the following code:
$json = ' {
"HTML":
[
{
"id": 1,
"name": "HTML",
"match": false
},
{
"id": 2,
"name": "HTML 5",
"match": false
},
{
"id": 3,
"name": "XHTML",
"match": false
}
]
}';
$obj = json_decode($json);
$obj[0][0]->name; // JavaScript: The Definitive Guide
Why do I get the following error?
use object of type stdClass as array
I decode the json correctly, than I say that I want to pick the first object from the array (in this case HTML) and than I want to pick the name of the first one in the array.
What is going wrong?
Your first JSON is object (HTML), which contains an array of another objects. You must call ->HTML[0] (which is first object in your array) and then ->name, which is parameter of your HTML object.
$obj->HTML[0]->name;