function results dont match query results php - php

Question

EDIT: the responses work well but not quite what i was after i dont think i explained it very well, i just want to return 1 result per function so count how many odd numbers are in the result and count how many even numbers are in the result?
sql fiddle for the data
http://sqlfiddle.com/#!9/dfbfa7/1
Im trying to count even and odd numbers by splitting the the results using 2 functions but my results dont match up to the results in the mysql table.
data
select number from table group by number
results
1,4,6,7,8,9,11,12
function to return odd number count
SELECT
COUNT(CASE WHEN (number% 2) > 0 THEN number ELSE NULL END) as odd
FROM test.table
WHERE date = CURDATE() and time > now() - interval 60 second group by number
LIMIT 1
and the function to return even number count
SELECT
COUNT(CASE WHEN (number% 2) = 0 THEN number ELSE NULL END) as even
FROM test.table
WHERE date = CURDATE() and time > now() - interval 60 second group by number
LIMIT 1
i was hoping the results would be
odd = 4
even = 4
but instead im getting
odd = 8
even = 0
where am i going wrong?

Answer 1

Maybe try something like thise.
For even numbers:
COUNT(SELECT * FROM `table` WHERE mod(number, 2)=0);
For odd numbers:
COUNT(SELECT * FROM `table` WHERE mod(number, 2)>0);
This will return the only number of odd and even numbers, then collect those numbers with php.

Answer 2

COUNT will add up all the lines it traverses
In your case you must use SUM:
SUM(CASE WHEN (number% 2) > 0 THEN 1 ELSE 0 END) as odd
SUM(CASE WHEN (number% 2) = 0 THEN 1 ELSE 0 END) as even
for simple operations the IF is much cleaner than the CASE:
SUM(IF(number % 2 > 0, 1, 0)) as odd
SUM(IF(number% 2 = 0, 1, 0)) as even

Answer 3

The reason your query is returning wrong result is probably because you are using limit 1 try removing it also if you have to use group by use group by number in before you do calculations for this query, i have altered the query here for example.
SELECT
count(CASE WHEN (a.number% 2) = 0 THEN a.number ELSE NULL END) as even,
count(CASE WHEN (a.number% 2) <> 0 THEN a.number ELSE NULL END) as odd
FROM (select number from test group by number) a;
http://sqlfiddle.com/#!9/dfbfa7/22
for the set up you have created im getting 5 even and 5 odd in results, may be you have to recheck the condition you have in where clause if your results are different with actual data.