I created a instagram feed for opencart and when i wrote the code in normal php file it worked perfectly but when i transformed to opencart controller view it returns when
json_last_error();
int(4) syntax error
and here is my code in controller
$response= utf8_encode(file_get_contents("https://www.instagram.com/user/?__a=1"));
$response= str_replace(array('ï',''), '',$response);
$response= json_decode($response);
$data['orgimages'] = json_last_error();
i tried so many solutions or filtering out methods and that is my final code as it was changed so many times from stackoverflow answer solution for other questions but nothing seems to be worked out and even their forums didn't worked out with my issue.
Your error indicates that your json is wrongly formatted so try to echo it and validate it. I am suspecting that your json is not a valid json.
Use this : https://jsonlint.com/ validator for json.
After this line :
$response= str_replace(array('ï',''), '',$response);
echo your $response variable and see how your json looks like
Related
Stack Overflow is full with questions like this, I'm aware of that. But none of the questions and accepted answers have solved it for me.
I'm getting a SOAP response like this:
string(402482) "ZSDSD1BKA00_DE_02DE00010000001083212550JVBERi0xLjUNJeLjz9MNCjExNCAwIG9iag08PC9MaW5lYXJpemVkIDEvTCAxMDgzMjEvTyAxMTYv RSAxODY2Mi9OIDEyL1QgMTA3Nzk3L0ggWyA1MDMgMjc2XT4+DWVuZG9iag0gICAgICAgICAgICAg DQoxMzQgMCBvYmoNPDwvRGVjb2RlUGFybXM8PC9Db2x1bW5zIDQvUHJlZGljdG9yIDEyPj4vRmls dGVyL0ZsYXRlRGVjb2RlL0lEWzwxREZGRkVGMUM4Q0E0NTI4QjBBMUYxOUEyNTMwREQ2OD48RURD QTlGRDBFNTE4N0M0N0JGRUZCOEM0MjlCRTUwMjE+XS9JbmRleFsxMTQgMzZdL0luZm8gMTEzIDAg Ui9MZW5ndGggOTMvUHJldiAxMDc3OTgvUm9vdCAxMTUgMCBSL1NpemUgMTUwL1R5cGUvWFJlZi9X WzEgMiAxXT4+c3RyZWFtDQpo3mJiZBBgYGJg/g0kGEKABONRIMHiCiSYNEASK0DEG5AEP4i4CZKI ABHiQEJIDyTWDiL+AwmuVhCLDaTDCsQtBHHZgcReIMHIwAiyg4GRIuI/Y9NngAADAOlxDEINCmVu ZHN0cmVhbQ1lbmRvYmoNc3RhcnR4cmVmDQowDQolJUVPRg0KICAgICAgICAgDQoxNDkgMCBvYmoN PDwvRmlsdGVyL0ZsYXRlRGVjb2RlL0kgMjE3L0wgMjAxL0xlbmd0aCAxODcvUyAxNDM+PnN0cmVh bQ0KaN5iYGBgZmBg8mZgZWDg38PAx4AAfEAZVgYWBo6qZQyMDAwCDNf1/NQ/HVzCrMDAO79pAssO rrZJjgW7zB7nbQCqZvMMlpJUbfRmmsaqwzPpwFIQCyjGNI2BvaIBhBoqgIipAkyzAzFW04AG+TMw TgYZKATEwmCHtDPwMn543+ykJGjUpMDleJGnJfMAA3vLf8Y/YRmvWBhtGksgDg5gYJzyEUgDHcvQ A8TBDIxLGCF8RlGAAAMA2bs1zA0KZW5kc3RyZWFtDWVuZG9iag0xMTUgMCBvYmoNPDwvTWV0YWRh dGEgODEgMCBSL1BhZ2VMYWJlbHMgMTA4IDAgUi9QYWdlcyAxMTAgMCBSL1R5cGUvQ2F0YWxvZz4+ DWVuZG9iag0xMTYgMCBvYmoNPDwvQ29udGVudHNbMTE4IDAgUiAxMTkgMCBSIDEyMCAwIFIgMTIx IDAgUiAxMjIgMCBSIDEyMyAwIFIgMTI0IDAgUiAxMjcgMCBSXS9Dcm9wQm94WzAgMCA1OTUuMjIg ODQyXS9NZWRpYUJveFswIDAgNTk1LjIyIDg0Ml0vUGFyZW50IDExMSAwIFIvUmVzb3VyY2VzIDEz NSAwIFIvUm90YXRlIDAvVHlwZS9QYWdlPj4NZW5kb2JqDTExNyAwIG9iag08PC9GaWx0ZXIvRmxh dGVEZWNvZGUvRmlyc3QgMTE3L0xlbmd0aCA5OTUvTiAxNC9UeXBlL09ialN0bT4+c3RyZWFtDQpo 3rxX227bOBD9FT5uHxxeJFISUBhw3LproEmDStgWCPyg2lxHC10MWUHTv+8MKcqSYze+AAuC4MyQ HB6O5owk7knCCPcUETKCMSAiCGEMicdwjIinYPQZkZGEkZMogHW+IJxHOOHBIg8Fn3CJW31JhCfB 7BufaAmI53m4C7xKML9/T6dVXtXxJl1qVLbKQGDkK8ihgQHyeEw/vjSf4iZtcNWnmBtgdmZWlQ0Y k4QzAw/3Jokw0KzsG1BWVgaOlUMDxHp5qKtlrJtH+vBhRhP90tB5ka71dEG/f/nxn17iEfMCzhXS 7J4XSkIYhOo08CyiTgsAIXeaQryi0wRGyp47Hj/S+XR6m271CvYbNAswlSv9ghYbCyJ89GfutgAg Xx7Iv2m+1SDcEU7jSavGd4TdMEGTXxu9ixitNnZ+PIa9k+1Slw0JI06n6eZvna2fGsIZY/SDtlMj wRWd5el6SzzfhPf2tnp5HEl4/iOPQWLAatwSLMzsLC2y/NdfSVboLbnXP8nXqkjLd2buPi00NTMw YewP8V1ipuKm1s3yid5XdZHmxvTNovEBzLxJ82w5Kde5JozGjS7+IWF7M1yKYOts01Q1/d67hLki RhPXHDj4Y7msVlm5pt+yclJus06fZfW2mT6lNfHE3gEm+fHZfU7bJVwIGj//aBBMUj9rg6qDBr5X
... but much longer.
Then I use simplexml_load_string to convert it, resulting in an apparently empty object. Now I've learned that this object is not empty though. print_r and var_dump are of no help and I used simplexml_tree.php for help. But I'm now stuck on how I can access a property within the result. I tried a bunch of different variations, most of them left me either a blank page, or an error 500.
This is the response I expect:
Trying to access property ORBLK, like I wrote, with many variations, has not been successful. Thats my current try (resulting a blank page):
$resultRow = (string)$xml->children('soap-env', true)->Body->children('n0', true)->Z_SDB_GET_SDB_FOR_MATERIALResponse->T_SDB->item->DOKAR;
How would I be able to access the property ORBLK?
There's an extremely simple example of using Youtube API in php that somehow fails to work in my case, and I couldn't find a definitive solution for.
I desire to use the Youtube API without any wrapper, by myself, to get data of videos. The following search:list query works perfectly when I try accessing it from within by browser (as a link), but in php, I get that error when I try the same.
$apikey_YT = <my API key>;
$ytrequrl = "https://www.googleapis.com/youtube/v3/search?".
"part=snippet".
"&maxResults=50".
"&q=doom".
"&relatedToVideoId=h8j2zj-A5tE".
"&type=video".
"&key=${apikey_YT}";
$result = file_get_contents($ytrequrl);
var_dump($result);
The potential issues were URL encoding, or allowing allow-url-fopen, but neither seemed to help in my case: the former actually gave a new error message: No such file or directory.
What can I do?
Try it like this. Might be your formatting.
This works for me.
$ytrequrl = 'https://www.googleapis.com/youtube/v3/search?part=snippet&maxResults=50&q=doom&relatedToVideoId=h8j2zj-A5tE&type=video&key='.$apikey_YT;
$info= file_get_contents($ytrequrl);
$info= json_decode($info, true);
print("<pre>".print_r($info,true)."</pre>");
I'm trying to return a Json object from an outside form with Cakephp 2.1. I have all my data, and I've looked at the responses, and the problem is I get a massive error text before my JSON!
Heres the code I use to print the json:
if (!$validationPassed) {
if ($ExternalRequest) {
if ($shouldEchoErrors){
Configure::write('debug',0); // Disabled so theoretically it can't even print errors
$this->RequestHandler->setContent('json', 'application/json' );
$json = json_encode($this->Customer->validationErrors);
echo $json;
$this->autoRender = false ;
}
The JSON it prints is correct, {"Email":["EmailUnique"]}. However I get a huge preformatted error message before that, stack trace and everything.
It was a dumb moment, but the answer in case anyone else finds this:
Theres an error far earlier in the code, with debug on, cake will print it immediately. This will get wrapped into the json output.
The specific error turns out to not be relevant for this question, its just in the view.
I am trying to find the game someone is playing on twitch by using the api. I have setup the json_decode and it shows all of the content from the api. However whenever I try to print_r the game I get an error.
The error:
Notice: Undefined property: stdClass::$game in C:\Program Files (x86)\EasyPHP-DevServer-14.1VC11\data\localweb\projects\Portfolio -- Website\twitchstreaminfo\streaminfo.php on line31
PHP code:
$streamer = $_POST['username'];
$apiurl = "https://api.twitch.tv/kraken/streams/" . $streamer;
$apicontent = file_get_contents($apiurl);
$streamerinfo = json_decode($apicontent);
print_r($streamerinfo->game);
Try just doing the following first and verify the result:
print_r( $streamerinfo );
From what I can see with the API, the following should work:
print_r( $streamerinfo->stream->game );
Your error is saying that the propery of "$game" does not exist on the object "$streamerinfo". As suggested above, try priting the "$streamerinfo" to varify that it is valid. Another thing you can do to prevent this is to add the following :
if (isset($streamerinfo->game) {
print_r($streamerinfo->game);
}
That code will prevent this error, but not fix the problem. I suggest this as a final solution to help you solve the problem
if (isset($streamerinfo->game) {
print_r($streamerinfo->game);
} else {
print_r($streamerinfo);
}
This will keep your code from breaking in the way that it is now. But, it will also print "$streamerinfo" if it fails. This way you can see why it failed.
I'm getting the json data from the twitter using the wordpress function wp_remote_get as below:
$response = wp_remote_get('http://api.twitter.com/1/statuses/user_timeline.json?screen_name=twitter');
$json = json_decode($response['body']);
and it works fine. However, it totally creates the problem on my page if the twitter returns some error. In that case the content on my page does not load after that error part. So how can I catch the error and continue, only if there is no error.
For example if the twitter limit exceeds, it returns following response:
{"request":"\/1\/statuses\/user_timeline.json?screen_name=twitter","error":"Rate limit exceeded. Clients may not make more than 150 requests per hour."}
From the above responsive, how can i get the error.
I'm trying following, but it does not work (my page does not load at all)
if (!isset($json['error']){
//continue
}
It doesn't work because you are trying to access $json as an array, which it is not. It's an object, so use:
if (!isset($json->error){
//continue
}
Your page doesn't load because it's causing a fatal error, which in turn produces a 500 internal server error. If you check your error log you'll find:
Fatal error: Cannot use object of type stdClass as array in ....
You need to use json_decode to "transform" your "json string" in an object.
$j = json_decode($json);
echo $j->{'error'}
Here you will find everything what you need to know about json_decode: http://php.net/manual/en/function.json-decode.php