PDO insert null instead of empty with dynamic statement - php

Question

I have a PDO with a dynamically created statement, I am running into errors when I try to insert empty data into decimal fields, I believe the issue is I need input null instead of empty. Here is my code:
try {
$options = [
\PDO::ATTR_ERRMODE => \PDO::ERRMODE_EXCEPTION,
\PDO::ATTR_DEFAULT_FETCH_MODE => \PDO::FETCH_ASSOC,
\PDO::ATTR_EMULATE_PREPARES => false,
];
$conn = new PDO("mysql:charset=utf8mb4;host=$servername;dbname=$dbname", $username, $password);
function escape_mysql_identifier($field){
return "`".str_replace("`", "``", $field)."`";
}
function prepared_insert($pdo, $table, $data) {
$keys = array_keys($data);
$keys = array_map('escape_mysql_identifier', $keys);
$fields = implode(",", $keys);
$table = escape_mysql_identifier($table);
$placeholders = str_repeat('?,', count($keys) - 1) . '?';
$sql = "INSERT INTO $table ($fields) VALUES ($placeholders)";
$pdo->prepare($sql)->execute(array_values($data));
}
prepared_insert($conn, 'products', $data);
$id = $conn->lastInsertId();
if ($id > 0) {
echo json_encode(array('response'=>'success'));
}else{
echo json_encode(array ('response'=>'error','errorMessage'=>'Row not created'));
}
}catch(PDOException $e){
echo json_encode(array ('response'=>'error','errorMessage'=>$e->getMessage()));
}
$conn = null;
How can I make this insert null instead of empty?

Answer 1

Change your table settings. Set it to accept null in that column:
ALTER TABLE `table` CHANGE `column` `column` VARCHAR(255) NULL DEFAULT NULL;