Check if the second image image exists in gallery - php

Question

I am trying to make an image hover on a list of galleries, showing the second image of each gallery if it exists.
Some galleries only have one image which is shown as a thumbnail.
The first image is $slider -> url[0] and the second one is $slider -> url[1].
Without using the if statement a problem is aroused: if the second image does not exist it shows a small error image.
I am trying to use an if statement with the required result as follows:
If the second image exists -> show the second image css style (imageexists).
Else (the second image doesn't exist-> show the alternative css style (plusbutton).
Here is the code I used:
<?php $imageexist=url[1]; ?>
<?php if(is_file( $imageexist))
{?>
<div class="image_gallery" style="hover- image: url('<?php echo $slider -> url[0];?>');">
<a href="<?php echo $item->link; ?>">
<div class="imageexists">
<img src="<?php echo $slider -> url[1]; ?>"
itemprop="thumbnailUrl"/>
</div></a>
</div>
<?php }
else { ?> <div class="image_gallery" style="hover- image: url('<?php echo $slider -> url[0];?>');">
<a href="<?php echo $item->link; ?>">
<div class="plusButton">
</div></a>
</div>
<?php }?>
This code does not show any error but it doesn't recognize if the image exists or not, so it shows the alternative (class plusbutton).
How could I make the code check if the second image exists or not?
Thank you very much in advance!

Answer 1

Check paths - this function looks where is directed. Frequently it is not desired directory, but something else.
If directory exists - no errors appears, but your images aren't there.
Check any variable right before is used, start with
<?php
$imageexist=url[1];
print_r($imageexist);
it should be an array with 'path/img_name.ext';
It produces links properly?
/* this is wrong */
<div class="image_gallery" style="hover- image: url('<?php echo $slider -> url[0];?>');">
I'm not sure what effect you wanted, but this style won't work;