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I want to use a loop to iterate through my array, calling my function to print out all of these messages. I have to somehow keep track - I'm using PHP code.
This my code :
<? php
$count = 6;
$rp = 11000;
$amount = array(1000,1000,1500,500,2000,4000);
foreach ($amount as $v) {
echo $total = $rp-$v; ?>
my output should be:
10000
9000
7500
7000
5000
1000
Is this what you want?
<?php
$count = 6;
$rp = 11000;
$amount = array(1000,1000,1500,500,2000,4000);
foreach ($amount as $v) {
$rp = $rp - $v;
$count--;
//echo $count;
echo $rp."<br/>" ;
}
?>
Related
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I have
$div = 100
$value = 502
$sum = $val / $div
how can i get output like this
100
100
100
100
100
2
any reffrence to learn more?
Here's one way to do it:
$div = 100;
$value = 502;
while($value > $div) {
$value = $value - $div;
echo $div . "<br>";
}
echo $value
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I have this array`
<?php
$arr = [['name'=>'john','age'=>20,'sex'=>'m'],
['name'=>'maria','age'=>12,'sex'=>'f'],
['name'=>'nick','age'=>25,'sex'=>'m'],
['name'=>'jo','age'=>31,'sex'=>'f'],];
foreach ($arr as $persoana) {
foreach ($persoana as $id=>$value) {
if ($id == 'age') {
$sumvarsta = $sumvarsta + $value;
$n++;
}
}
}`?>
i need total average age (total average age seems to be working ok) , average age for women and average age for men.
How to calculate ?
thx.
<?php
$arr = [['name'=>'john','age'=>20,'sex'=>'m'],
['name'=>'maria','age'=>12,'sex'=>'f'],
['name'=>'nick','age'=>25,'sex'=>'m'],
['name'=>'jo','age'=>31,'sex'=>'f'],];
$womansum = 0;
$womancount = 0;
$mansum = 0;
$mancount = 0;
foreach ($arr as $persoana) {
if ($persoana['sex'] == 'm')
{
$mansum += $persoana['age'];
$mancount++;
} else {
$womansum += $persoana['age'];
$womancount++;
}
}
$manAverage = $mansum / $mancount;
$womanAverage = $womansum / $womancount;
$totalAverage = ($mansum + $womansum) / ($mancount + $womancount);
?>
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I am trying to get a number between 1 to 6 with more chances to be close to 1.
i have tried this:
<li>{{Faker\Factory::create()->biasedNumberBetween($min = 10, $max = 20, $function = 'unbiased')}}</li>
What i am trying to do is to generate a number from 1 to 6 rand(1,6); but make the numbers be closer to one as the lower numbers will have more weight than the others.
Something like this ?
<?php
function weightedRand($min, $max, $weightedMax) {
$arr = array();
for($i = 0; $i < 10; $i++) {
$arr[] = rand($min, $weightedMax);
}
$arr[] = rand($min, $max);
return $arr[rand(0,10)];
}
echo weightedRand(1,6, 3);
?>
numbers below 4 will now be more likely than numbers above :)
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Im trying to display 2 or more unique random results from a text file, How do I do that please?
But I need unique results and not 2 or more of the same.
Currently using this code, but it only returns 1 random result:
<?php
$text = file_get_contents('flatFileDB.txt');
$textArray = explode("\n", $text);
$randArrayIndexNum = array_rand($textArray);
$randPhrase = $textArray[$randArrayIndexNum];
?>
<?php echo $randPhrase ?>
I would use something like that
shuffle($textArray);
echo $textArray[0];
echo $textArray[1];
http://php.net/manual/tr/function.shuffle.php
You can give a shot to this also. Code is not tested. I am collecting the used into an array, and check, is that used before.
$text = file_get_contents('flatFileDB.txt');
$textArray = explode("\n", $text);
$used = array();
$countOfRandoms = 2;
$randoms = array();
$i = 1;
do {
if ($countOfRandoms == $i) {
break;
}
$randArrayIndexNum = array_rand($textArray);
if (in_array($randArrayIndexNum, $used)) {
continue;
}
$used[] = $randArrayIndexNum;
$random = $textArray[$randArrayIndexNum];
$i++;
} while (true);
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How do I print a series like this?
6,15,24,33,42.....1000
I have tried using a for loop like this, but can't work out how to get it to increment by 9 on each iteration.
for($i = 6; $i <= 1000; $i = 9)
{
echo $i . ', ';
}
Quite simple really:-
for($i = 6; $i <= 1000; $i += 9){
echo $i . ', ';
}
//If you have to finish the series with 1000, although it is not a part of the series:-
echo '1000';
See it working
just for fun:
echo implode(', ', range(6, 1000, 9));
echo ", 1000";
<?php
for($i=6; $i<1000; $i+=9)
echo $i."<br>";
?>
Seeing the question this can be an answer.