This question already has answers here:
How to join two tables mysql?
(4 answers)
Closed 2 years ago.
I have two tables that looks something like this (made as example):
Table sales:
| ID | date | displayname | status |
| 1 | 2020/08/03 16:25:26 | Angel | OK |
| 2 | 2020/08/03 16:25:26 | Angel | OK |
| 3 | 2020/08/03 16:25:26 | Cabil | X |
| 4 | 2020/08/03 16:25:26 | Syed | OK |
...
Table users (all of the columns has value, but removed for GDPR reasons):
| ID | displayname | fullname | email |
| 1 | Angel | | |
| 2 | Nico | | |
| 3 | Raquie | | |
| 4 | Cabil | | |
| 5 | Syed | | |
...
I have a PHP script that looks like this:
<?php
$query = "SELECT * FROM sales WHERE status='OK' ORDER BY STR_TO_DATE(`date`, '%Y/%m/%d %H:%i:%s') DESC LIMIT 5";
if ($result = $link->query($query)) {
$num_rows = 0;
while ($row = $result->fetch_assoc()) {
$num_rows++;
echo '<div class="my-box">';
echo "{$row['id']}";
echo "{$row['date']}";
echo "{$row['dbirth']}";
echo "{$row['email']}";
echo "{$row['displayname']}";
echo '</div>';
}
$result->free();
}
?>
Now it currently displays each displayname for each sale in echo "{$row['displayname']}";, but insted of the displayname, I want to show the fullname for the user that has the current display name. How can I accomplish this?
You seem to be looking for a join:
select s.*, u.fullname
from sales s
inner join users u on u.displayname = u.displayname
Related
This question already has answers here:
SQL Join Differences
(5 answers)
Closed 7 years ago.
can please someone help me? I do the work at school and I dont know how connect these two tables.
I have two tables :
|Analyze | | Data
+-------------------------+ +-------------------------+
| id_analyze | Name | | id_analyze | Standard |
--------------------------- -------------------------
| 1 | One | 1 | A.11 |
| 2 | two | 1 | A.12 |
| 3 | tree | 1 | A.13 |
| 4 | four | 2 | A.21 |
| 5 | five | 2 | A.22 |
| id_analyze | Name | 3 | A.31 |
All, what I need is get output on web page from these two tables like:
| One | A.11 |
| | A.12 |
| | A.13 |
---------------
| Two | A.21 |
| | A.22 |
I tried a lots of listing but nothing work. For example:
$choose = mysql_query("select * FROM Analyze", $connection);
$choose2 = mysql_query("select * FROM Data,Analyze WHERE Data.id_analyze = Analyze.id_analyze", $connection);
while ($row = mysql_fetch_array( $choose ) ){
while ($row2 = mysql_fetch_array( $choose2 )) {
$Name = $row['Name'];
$Standard = $row2['Standard'];
}
}
Simple JOIN query:-
SELECT Analyze.Name, Data.Standard
FROM Analyze
INNER JOIN Data
ON Data.id_analyze = Analyze.id_analyze
ORDER BY Analyze.Name, Data.Standard
Note that you can do joins how you have done them but the newer way is explicitly using INNER JOIN / LEFT OUTER JOIN / etc.
You can then just loop around the results of this once
This is the bookings table I'm using for my query
+----------------------+
| event_id | person_id |
+----------------------+
| 5 | 7 |
| 4 | 7 |
| 3 | 7 |
| 4 | 5 |
| 3 | 5 |
| 5 | 3 |
+----------------------+
This table shows that person_id 7 has 3 bookings, 5 has 2 bookings and 3 has 6 bookings.
Currently, I'm using this query to get the total number of bookings per person.
$query='
SELECT
bookings.person_id,
COUNT(bookings.person_id) AS total,
bookings.event_id,
users.display_name
FROM bookings
INNER JOIN users ON bookings.person_id=users.id
WHERE users.id=bookings.person_id
GROUP BY bookings.person_id';
$result = mysql_query($query);
if($result) {
while($row = mysql_fetch_array($result))
{
/* total bookings per user */
$value = $row['total'];
$sum += $value;
/* events booked per user */
$events....
/* Displaying results */
echo "<tr width='500'>";
echo "<td>".$row['person_id']."</td>";
echo "<td>".$row['display_name']."</td>";
echo "<td>".$row['total']."</td>";
echo "<td>".$events."</td>";
echo "</tr>";
}
This works okay and gives me:
+-----------------------------------+
| ID | NAME | Total Bookings |
+-----------------------------------+
| 7 | Bob | 3 |
| 5 | Jane | 2 |
| 3 | Joe | 1 |
+-----------------------------------+
I'm seeking help to get this to display the events booked by each person (like the 4th columns below):
+------------------------------------------------+
| ID | NAME | Total Bookings | Event IDs |
+------------------------------------------------+
| 7 | Bob | 3 | 5,4,3 |
| 5 | Jane | 2 | 4,3 |
| 3 | Joe | 1 | 5 |
+------------------------------------------------+
Could you please help me getting there.
Thanks.
GROUP_CONCAT https://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat
$query='
SELECT
bookings.person_id,
COUNT(bookings.person_id) AS total,
GROUP_CONCAT(bookings.event_id) as event_ids,
users.display_name
FROM bookings
INNER JOIN users ON bookings.person_id=users.id
WHERE users.id=bookings.person_id
GROUP BY bookings.person_id';
A bit different query but same result:
SELECT
bookings.person_id,
COUNT(
bookings.person_id
) AS total,
users.display_name,
GROUP_CONCAT(
bookings.event_id
ORDER BY
bookings.event_id
) AS events_list
FROM
bookings,
users
WHERE
bookings.person_id=users.id
GROUP BY
bookings.person_id
ORDER BY
bookings.person_id
I don't know if for a large data, the execution time is less, more or equal.
I have the following table and I want to select all (via php query) but only the rows that matches course1, I tried the following but it doesn't work.
$comments = array();
$result = mysql_query("select * from comments where course1='$post_id' order by id ASC");
what's the right query?
+----+-----------+----------+-----+-------------------------+---------------+-------------
| id | post_id | name | url | email | body | dt |
+----+-----------+----------+-----+-------------------------+---------------+-------------
| 1 | course2 | john | | john#john.com | comments by john | 2012-11-16 |
| 2 | course1 | wiki | | wiki#wiki.com | comments by wiki | 2012-11-16 |
| 3 | course2 | daniel | | daniel#gmail.com | comments by daniel | 2012-11-16 |
| 4 | course2 | ram | | ram#ram.com | comments by ram | 2012-11-16 |
| 5 | course1 | velu | | velu#velu.com | comments by velu | 2012-11-16 |
+----+-----------+----------+-----+-------------------------+---------------+-------------
Try this: SELECT * FROM comments WHERE post_id='course1' order by id ASC
I think you'd muddled your column names and search values in your sql
try this:
$result = mysql_query("select * from comments where post_id='$post_id' order by id ASC");
You need to reference the field name you're searching on:
$result = mysql_query("select * from comments where post_id='$post_id' order by id ASC");
Where your $post_id string variable contains value "course1".
I'm having a hard time organizing the data that I get from mysql_fetch_array().
I have a DB table with that looks something like this:
+---------------------+------------------+---------------+--------+---------+
| date | name | indexed_pages | nameID | entryID |
+---------------------+------------------+---------------+--------+---------+
| 2012-06-15 21:18:06 | site1.com | 200 | 1 | 1 |
| 2012-06-15 21:18:10 | site2.com | 25 | 2 | 1 |
| 2012-06-15 21:18:13 | site3.com | 12 | 3 | 1 |
| 2012-06-15 21:18:16 | site4.com | 8 | 4 | 1 |
| 2012-06-15 21:18:19 | site5.com | 2 | 5 | 1 |
| 2012-06-16 00:11:12 | site1.com | 191 | 1 | 2 |
| 2012-06-16 00:11:21 | site2.com | 25 | 2 | 2 |
| 2012-06-16 00:11:30 | site3.com | 12 | 3 | 2 |
| 2012-06-16 00:11:44 | site4.com | 8 | 4 | 2 |
| 2012-06-16 00:11:51 | site5.com | 2 | 5 | 2 |
| 2012-06-18 10:20:47 | site1.com | 191 | 1 | 3 |
| 2012-06-18 10:20:52 | site2.com | 25 | 2 | 3 |
| 2012-06-18 10:20:56 | site3.com | 12 | 3 | 3 |
| 2012-06-18 10:21:00 | site4.com | 8 | 4 | 3 |
| 2012-06-18 10:21:04 | site5.com | 2 | 5 | 3 |
+---------------------+------------------+---------------+--------+---------+
I need to order the results in a Google Line Graph in the following manner:
['date', 'site1_entryID=1', 'site2_entryID=2', 'site3_entryID=3', (...)],";
The thing is that I'm having trouble managing the arrays that I generate. I'm using the following code:
mysql_connect("host_here", "username_here", "pass_here") or die(mysql_error());
mysql_select_db("my_database") or die(mysql_error());
$query = "SELECT * FROM pages";
$result = mysql_query($query);
$row = mysql_fetch_array($result);
After this I need to echo the number of indexed_pages for each site where entryID = 1.
I don't know if this description is confusing or not, but I've tried pretty much everything and can't get the organize the data from the arrays to serve what I need to do. Help, please!
Thanks in advance!
Don't use select *, that's lazy, and you're stuck accepting the fields in the order the DB decides to produce them in.
Specify the fields you want, in the order you want:
SELECT date, name, indexed_pages, etc...
I think the simplest query is :
$result= mysql_query("SELECT name, index_pages, entryID from table_name WHERE entryID =
1");
while($row=mysql_fetch_array($result)){
echo "$row[name]";
echo "$row[index_pages]";
echo "$row[entryID]";
}
Try this. There might be some mistakes. Because i developed it fast. And replace table_name with yours.
Or you can display it in a table:
echo "<table>";
echo "<tr><td>Sit Name</td>";
echo "<td>Page Name</td>";
echo "<td>EntryID</td>";
echo "</tr>";
while($row=mysql_fetch_array($result)){
echo "<tr>";
echo "<td>$row[name]</td>";
echo "<td>$row[index_pages]</td>";
echo "<td>$row[entryID]</td>";
echo "</tr>";
}
echo "</table>";
SELECT date, name, indexed_pages
FROM pages
where entryID=1
order by date asc ,name asc
Not sure if this will help
mysql_connect("host_here", "username_here", "pass_here") or die(mysql_error());
mysql_select_db("my_database") or die(mysql_error());
$query = "SELECT * FROM pages";
$result = mysql_query($query);
$data[]='date';
while($row = mysql_fetch_assoc($result)){
$name=substr($row['name'], -4);
$data[]= $name."_entryID=".$row['entryID'];
}
A little of a brute force method.
I have tables illustrated below
//reference type table
+---+-----------+---------+
|ID |Article_ID |Ref_Types|
+---+-----------+---------+
| 1 | 1 | article |
| 2 | 1 | book |
| 3 | 1 | article |
| 4 | 1 | article |
| 5 | 2 | book |
+---+-----------+---------+
//book references table
+---+-----------+--------+
|ID |Article_ID |Title |
+---+-----------+--------+
| 1 | 1 | book1 |
| 2 | 1 | book2 |
| 3 | 2 | book3 |
| 4 | 2 | book4 |
| 5 | 2 | book5 |
+---+-----------+--------+
//article references table
+---+-----------+-----------+
|ID |Article_ID |Title |
+---+-----------+-----------+
| 1 | 1 | article1 |
| 2 | 1 | article2 |
| 3 | 2 | article3 |
| 4 | 2 | article4 |
| 5 | 2 | article5 |
+---+-----------+-----------+
I have to look into first table and check the reference, of which type it is;
for each reference type, I have get reference table from related table
I have to output in order, as shown in table one.
1:
$data=array();
$sql=mysql_query("SELECT * FROM reftypes
WHERE Article_ID=1 ORDER BY ID ASC");
while($row = mysql_fetch_array($sql)){
$data[]=$row[2]; // i store in an array so that i can use later..
}
2:
foreach ($data as $ref) {
$counter=1;
switch ($ref) {
case "article":
$sqlarticle= mysql_query("SELECT Title
FROM book WHERE Article_ID=1 ORDER BY ID ASC");
echo mysql_result($sqlarticle, $counter); //i want to get only one out of book table
$counter++;
break;
...
...
But $sqlarticle does not seem to work.
I want to display as:
+-----------+----------+
|Article_ID |Reference |
+-----------+----------+
| 1 | article1 |
| 1 | book1 |
| 1 | article2 |
| 1 | article3 |
+-----------+----------+
I know it is a long question and for experts or experienced people it is very trivial, but that is where I'm stuck.
SELECT
*
FROM
reftypes R
WHERE
Article_ID=your_id
LEFT JOIN books B ON (B.Article_ID = R.Article_ID AND R.Ref_Types = 'book')
LEFT JOIN articles A ON (A.Article_ID = R.Article_ID AND R.Ref_Types = 'article')
ORDER BY
R.id ASC;
Even if the database is wrongly modeled, I think.
What about the followin model instead?
""although especially question owners should respect any kind of effort and input, -i am thankful- i can not understand why some people try to think of question's holder as well-informed or experienced as themselves, or worse comment from higher level. ""
anyway, my question was about to get values one by one, here is how i did it;
$data=array();
$sql=mysql_query("SELECT * FROM reftypes
WHERE Article_ID=1 ORDER BY ID ASC");
while($row = mysql_fetch_array($sql)){
$data[]=$row[2]; // i store in an array so that i can use later..
}
$articlecount=0;
$bookcount=0;
foreach ($data as $value) {
switch ($value) {
case "article":
$sqlarticle=mysql_query("SELECT RefArticleTitle
FROM ref_article
WHERE $article_ID=Article_ID
ORDER BY ID ASC");
$articles= mysql_result($sqlarticle, $articlecount);
echo $articles;
echo "\n";
$articlecount++;
break;
case "book":
$sqlbook=mysql_query("SELECT RefBookName
FROM ref_book
WHERE $article_ID=Article_ID
ORDER BY ID ASC");
$books= mysql_result($sqlbook, $bookcount);
echo $books;
echo "\n";
$bookcount++;
break;
...
...
as a result, i got what i required..
+-----------+----------+
|Article_ID |Reference |
+-----------+----------+
| 1 | article1 |
| 1 | book1 |
| 1 | article2 |
| 1 | article3 |
+-----------+----------+
thanks to whoever interested in the topic..
$result=mysqli_query("select ref_types from reference type");
while($row=mysqli_fetch_array($result))
{
$table=$row[0];
$result1=mysqli_query("select * from $table");
while($row1=mysqli_fetch_array($result1))
{
var_dump($row1);
}
}