Illegal string offset 'name' CodeIgniter 4 - php

Question

I'm a new user of CodeIgniter 4. I got this error when I want to show 'prodi_name' of table 'prodi' on a form.
This is my ProdiModel
protected $table = 'prodi';
protected $primaryKey = 'id_prodi';
public function getProdi($id = false)
{
if ($id == false) {
return $this->findAll();
}
return $this->where('prodi_code', $id)->first();
}
I have setting my BaseController with
$this->prodiModel = new \App\Models\ProdiModel();
so my Controller is
public function add()
{
$data = [
'title' => 'Admin',
'prodi' => $this->prodiModel->getProdi(),
'validation' => \Config\Services::validation()
];
return view('admin/add', $data);
}
And this is my form, I want to show the prodi_name on a multiple select field
<div class="form-group">
<label>Prodi</label>
<select class="form-control select2 multiple" id="prodi" name="prodi[]" multiple="multiple" data-placeholder="Select prodi">
<?php
foreach ($prodi as $prodi) :
echo "<option value='" . $prodi["prodi_name"] . "'";
if (old('prodi')) {
if (in_array($prodi['prodi_name'], old('prodi'))) echo "selected";
}
echo ">" . $prodi['prodi_name'] . "</option>";
endforeach; ?>
</select>
</div>
Please help me to solve this problem. Thanks

Answer 1

first of all in CI 4 there is no first() method,
use
public function getProdi($id = false)
{
if ($id == false) {
return $this->findAll();
}
return $this->where('prodi_code', $id)->getFirstRow(‘array’);
}
On the second thought you are returning two types of data here, if id is false you return multidimensional array and if id is there code returns single row.
Again in the same method, you have called findAll(), if it returns and associative array, your code should run, but if that returns a object then you should change to,
<?php
foreach ($prodi as $prodi) :
echo "<option value='" . $prodi->prodi_name . "'";
if (old('prodi')) {
if (in_array($prodi->prodi_name, old('prodi'))) echo "selected";
}
echo ">" . $prodi->prodi_name . "</option>";
endforeach; ?>