I need to move a specific character in a string from a specific position to right by specific places. string, position, and places are inputs it can be any value.
(Maximum use less number of lines using PHP functions).
$string = 'Peacock';
$position = 2;
$places = 2;
move($string,$position,$places);
function move($string,$position,$places){
$string[($position-1)+$places] = $string[$position-1];
echo $string ;
}
Expected output is Paceock
with for loop will be a good solution.
NB: the $position must be start from 1.
<?php
$string = 'Peacock';
$position = 2;
$places = 2;
move($string,$position,$places);
function move($string,$position,$places){
$keep = $string[$position-1];
for($i=0; $i<=$places;$i++){
$string[($position-1)+$i] = $string[$position+$i];
}
$string[$position+$places-1] = $keep;
echo $string ;
}
If you do not mind you can modify the string as well.
$string = 'Peacock';
$position = 2;
$places = 2;
function move($string,$position,$places){
$char = $string[$position-1];
$string = substr_replace($string, '', $position-1, 1);
$string = substr_replace($string, $char, $position+$places-1, 0);
echo $string;
}
move($string,$position,$places);
Related
I want to parse and expand the given strings in PHP.
From
0605052&&-5&-7&-8
0605052&&-4&-7
0605050&&-2&-4&-6&-8
To
0605052, 0605053 ,0605054 ,0605055, 0605057, 0605058
0605052,0605053,0605054,0605057
0605050,0605051,0605052,0605054,0605056,0605058
can someone help me with that? thanks in advance!
Your question is not very clear, but I think you mean a solution like this:
Edited: Now the hole ranges were shown and not only the specified numbers.
<?php
$string = "0605052&&-5&-7&-8";
$test = '/^([0-9]+)\&+/';
preg_match($test, $string, $res);
if (isset($res[1]))
{
$nr = $res[1];
$test = '/\&\-([0-9])/';
preg_match_all($test, $string, $res);
$result[] = $nr;
$nrPart = substr($nr, 0, -1);
$firstPart = substr($nr, -1);
if (isset($res[1]))
{
foreach ($res[1] as &$value)
{
if ($firstPart !== false)
{
for ($i=$firstPart+1; $i<=$value; $i++)
{
$nr = $nrPart . $i;
$result[] = $nr;
}
$firstPart = false;
}
else
{
$nr = $nrPart . $value;
$result[] = $nr;
$firstPart = $value;
}
}
}
var_dump($result);
}
?>
This delivers:
result[0] = "0605052"
result[1] = "0605053"
result[2] = "0605054"
result[3] = "0605055"
result[4] = "0605057"
result[5] = "0605058"
I think a multi step approach is the best thing to do here.
E.g. take this as an example 0605052&&-5&-7&-8:
Split at -. The result will be 0605052&&, 5&, 7&, 8
The first result 0605052&& will help you create your base. Simply substring the numbers by finding first occurence of & and substring to the next to last number. Result will be 060505. You will also need the last number, so get it as well (which is 2 in this case).
Get the remaining ends now, all \d& are simple to get, simply take the first character of the string (or if those can be more than one number, use substring with first occurence of & approach again).
The last number is simple: it is 8.
Now you got all important values. You can generate your result:
The last number from 2., all numbers from 3. and the number from 4. together with your base are the first part. In addition, you need to generate all numbers from the last number of 2. and the first result of 3. in a loop by a step of 1 and append it to your base.
Example Code:
<?php
$str = '0605052&&-5&-7&-8';
$split = explode('-', $str);
$firstAmpBase = strpos($split[0], '&');
$base = substr($split[0], 0, $firstAmpBase - 1);
$firstEnd = substr($split[0], $firstAmpBase - 1, 1);
$ends = [];
$firstSingleNumber = substr($split[1], 0, strpos($split[1], '&'));
for ($i = $firstEnd; $i < $firstSingleNumber; $i++) {
array_push($ends, $i);
}
array_push($ends, $firstSingleNumber);
for ($i = 2; $i < count($split) - 1; $i++) {
array_push($ends, substr($split[$i], 0, strpos($split[$i], '&')));
}
array_push($ends, $split[count($split) - 1]);
foreach ($ends as $end) {
echo $base . $end . '<br>';
}
?>
Output:
0605052
0605053
0605054
0605055
0605057
0605058
$str = 'ABC300';
How I can get values like
$alphabets = "ABC";
$numbers = 333;
I have a idea , first remove numbers from the string and save in a variable. then remove alphabets from the $str variable and save. try the code
$str = 'ABC300';
$alf= trim(str_replace(range(0,9),'',$str));//removes number from the string
$number = preg_replace('/[A-Za-z]+/', '', $str);// removes alphabets from the string
echo $alf,$number;// your expected output
Try something like this (it's not that fast)...
$string = "ABCDE3883475";
$numbers = "";
$alphabets = "";
$strlen = strlen($string);
for($i = 0; $i <= $strlen; $i++) {
$char = substr($string, $i, 1);
if(is_numeric($char)) {
$numbers .= $char;
} else {
$alphabets .= $char;
}
}
Then all numbers should be in $numbers and all alphabetical characters should be in $alphabets ;)
https://3v4l.org/Xh4FR
A way to do that is to find all digits and use the array to replace original string with the digits inside.
For example
function extractDigits($string){
preg_match_all('/([\d]+)/', $string, $match);
return $match[0];
}
$str = 'abcd1234ab12';
$digitsArray = extractDigits($str);
$allAlphas = str_replace($digitsArray,'',$str);
$allDigits = '';
foreach($digitsArray as $digit){
$allDigits .= $digit;
}
This is my sample string (this one has five words; in practice, there may be more):
$str = "I want to filter it";
Output that I want:
$output[1] = array("I","want","to","filter","it");
$output[2] = array("I want","want to","to filter","filter it");
$output[3] = array("I want to","want to filter","to filter it");
$output[4] = array("I want to filter","want to filter it");
$output[5] = array("I want to filter it");
What I am trying:
$text = trim($str);
$text_exp = explode(' ',$str);
$len = count($text_exp);
$output[$len][] = $text; // last element
$output[1] = $text_exp; // first element
This gives me the first and the last arrays. How can I get all the middle arrays?
more generic solution that works with any length word:
$output = array();
$terms = explode(' ',$str);
for ($i = 1; $i <= count($terms); $i++ )
{
$round_output = array();
for ($j = 0; $j <= count($terms) - $i; $j++)
{
$round_output[] = implode(" ", array_slice($terms, $j, $i));
}
$output[] = $round_output;
}
You can do that easily with regular expressions that give you the most flexibility. See below for the way that supports dynamic string length and multiple white characters between words and also does only one loop which should make it more efficient for long strings..
<?php
$str = "I want to filter it";
$count = count(preg_split("/\s+/", $str));
$results = [];
for($i = 1; $i <= $count; ++$i) {
$expr = '/(?=((^|\s+)(' . implode('\s+', array_fill(0, $i, '[^\s]+')) . ')($|\s+)))/';
preg_match_all($expr, $str, $matches);
$results[$i] = $matches[3];
}
print_r($results);
You can use a single for loop and if conditions to do
$str = "I want to filter it";
$text = trim($str);
$text_exp = explode(' ',$str);
$len = count($text_exp);
$output1=$text_exp;
$output2=array();
$output3=array();
$output4=array();
$output5=array();
for($i=0;$i<count($text_exp);$i++)
{
if($i+1<count($text_exp) && $text_exp[$i+1]!='')
{
$output2[]=$text_exp[$i].' '.$text_exp[$i+1];
}
if($i+2<count($text_exp) && $text_exp[$i+2]!='')
{
$output3[]=$text_exp[$i].' '.$text_exp[$i+1].' '.$text_exp[$i+2];
}
if($i+3<count($text_exp) && $text_exp[$i+3]!='')
{
$output4[]=$text_exp[$i].' '.$text_exp[$i+1].' '.$text_exp[$i+2].' '.$text_exp[$i+3];
}
if($i+4<count($text_exp) && $text_exp[$i+4]!='')
{
$output5[]=$text_exp[$i].' '.$text_exp[$i+1].' '.$text_exp[$i+2].' '.$text_exp[$i+3].' '.$text_exp[$i+4];
}
}
Any reason why this code sometimes only generates 4 character strings?
function genID()
{
$id = '';
$values = '0123456789abcdefghijklmnopqrstuvwxyz';
for($i=0; $i < 5; $i++) :
$str = substr($values, rand(0, strlen($values)), 1);
if(!is_nan(acos($str)))
(mt_rand(0, 1)) ? $str = strtoupper($str) : '';
$id .= $str;
endfor;
return $id; // e.g: ifR8j
}
acos($str) accepts numbers not string.... if u remove the aphabets from the string
ie.
$values = '0123456789abcdefghijklmnopqrstuvwxyz';
to
$values = '0123456789';
you will get the length as 5... Hope this helps..
Try, something simple:
function genID() {
$id = '';
$i = $length = 4;
$possible = "0123456789bcdfghjkmnpqrstvwxyz";
$possibleChar = strlen($possible) - 1;
while ($i) {
$char = $possible[mt_rand(0, $possibleChar)];
while (!strstr($id, $char)) {
$id .= $char;
$i--;
}
}
return $id;
}
(mt_rand(0, 1)) ? $str = strtoupper($str) : '';
This condition is met so sometimes you get an empty char.
Fix the condition or do the loop in some other manner.
For example
while(strlen($id)<5) {
//do the loop
}
The loop iterates 5 times.
rand will also return strlen, so $str will sometimes be ""
$str = substr($values, rand(0, strlen($values))-1, 1);
This will generate 5 characters always.
I have a string like this:
$string = "1,4|2,64|3,0|4,18|";
Which is the easiest way to access a number after a comma?
For example, if I have:
$whichOne = 2;
If whichOne is equal to 2, then I want to put 64 in a string, and add a number to it, and then put it back again where it belongs (next to 2,)
Hope you understand!
genesis'es answer with modification
$search_for = 2;
$pairs = explode("|", $string);
foreach ($pairs as $index=>$pair)
{
$numbers = explode(',',$pair);
if ($numbers[0] == $search_for){
//do whatever you want here
//for example:
$numbers[1] += 100; // 100 + 64 = 164
$pairs[index] = implode(',',$numbers); //push them back
break;
}
}
$new_string = implode('|',$pairs);
$numbers = explode("|", $string);
foreach ($numbers as $number)
{
$int[] = intval($number);
}
print_r($int);
$string = "1,4|2,64|3,0|4,18|";
$coordinates = explode('|', $string);
foreach ($coordinates as $v) {
if ($v) {
$ex = explode(',', $v);
$values[$ex[0]] = $ex[1];
}
}
To find the value of say, 2, you can use $whichOne = $values[2];, which is 64
I think it is much better to use the foreach like everyone else has suggested, but you could do it like the below:
$string = "1,4|2,64|3,0|4,18|";
$whichOne = "2";
echo "Starting String: $string <br>";
$pos = strpos($string, $whichOne);
//Accomodates for the number 2 and the comma
$valuepos = substr($string, $pos + 2);
$tempstring = explode("|", $valuepos);
$value = $tempstring[0]; //This will ow be 64
$newValue = $value + 18;
//Ensures you only replace the index of 2, not any other values of 64
$replaceValue = "|".$whichOne.",".$value;
$newValue = "|".$whichOne.",".$newValue;
$string = str_replace($replaceValue, $newValue, $string);
echo "Ending String: $string";
This results in:
Starting String: 1,4|2,64|3,0|4,18|
Ending String: 1,4|2,82|3,0|4,18|
You could run into issues if there is more than one index of 2... this will only work with the first instance of 2.
Hope this helps!
I know this question is already answered, but I did one-line solution (and maybe it's faster, too):
$string = "1,4|2,64|3,0|4,18|";
$whichOne = 2;
$increment = 100;
echo preg_replace("/({$whichOne},)(\d+)/e", "'\\1'.(\\2+$increment)", $string);
Example run in a console:
noice-macbook:~/temp% php 6642400.php
1,4|2,164|3,0|4,18|
See http://us.php.net/manual/en/function.preg-replace.php