Im new to laravel, i am trying to query a specific table in my DB. I only have 1 data table and the standard user auth tables. I am getting a error: BadMethodCallException
Call to undefined method App\Figures::table().
Model
namespace App;
use Illuminate\Database\Eloquent\Model;
class Figures extends Model
{
}
controller
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Figures;
class figuresController extends Controller
public function figurespag2() {
$dummyDetails = Figures::table('figures')->where('name', 'batman');
return view ( 'pagination2.index' )->withUsers($dummyDetails);
}
route
Route::get ( '/pagination2', 'figuresController#figurespag2' );
I know it's going to be something obvious, but I am new to this.
this is wrong
$dummyDetails = Figures::table('figures')->where('name', 'batman');
Method 1---------- laravel eloquent
Model
namespace App;
use Illuminate\Database\Eloquent\Model;
class Figures extends Model
{
protected $table = 'figures';
}
Controller
$dummyDetails = Figures::where('name', 'batman')->get();
and
Method 2 ---------- laravel Query Builder
$dummyDetails = \DB::table('figures')->where('name', 'batman')->get();
Use this you not need to define table name
public function figurespag2() {
$dummyDetails = Figures::where('name', 'batman')->get();
return view ( 'pagination2.index' )->withUsers($dummyDetails);
}
First you may need to know laravel model rules.
If you create a table name like "figures" (plural) you need to create its model by Figure (singular).
if you create a table other then this rule then you have to mentioned table name in model like this.
protected $table = "table_name";
you can access table with where condition in controller like this.
public function figurespag2() {
$dummyDetails = Figure::where('name', 'batman')->get();
return view ( 'pagination2.index' )->withUsers($dummyDetails);
}
Hope this may help you.
Related
I have a navigation model that can have many items associated with it:
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\Relations\HasMany;
use JetBrains\PhpStorm\ArrayShape;
use Laravel\Scout\Searchable;
class Navigation extends Model
{
use HasFactory;
use Searchable;
protected $guarded = [];
public function navigation_items(): HasMany
{
return $this->hasMany(NavigationItem::class);
}
}
The navigation item model looks like this
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\Relations\BelongsTo;
use Illuminate\Database\Eloquent\Relations\MorphTo;
class NavigationItem extends Model
{
use HasFactory;
protected $guarded = [];
public function navigation(): BelongsTo
{
return $this->belongsTo(Navigation::class);
}
public function navigatable(): MorphTo
{
return $this->morphTo();
}
}
Now an item can either be of type Page or Blog, in this case the Page model looks like this:
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Collection;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\Relations\MorphOne;
use JetBrains\PhpStorm\ArrayShape;
use Laravel\Scout\Searchable;
class Page extends Model
{
protected $guarded = [];
public function navigatable(): MorphOne
{
return $this->morphOne(NavigationItem::class, 'navigatable');
}
}
When I try to save a navigation model and associate it with a item, the following error appears:
SQLSTATE[HY000]: General error: 1364 Field 'navigatable_type' doesn't have a default value
I save the model like this:
foreach ($this->selected as $id) {
$this->navigation->navigation_items()->create([
'navigation_id' => $this->navigation->id,
]);
Where $this->selected is the navigation id, it should automatically get the correct navigatable_type and navigatable_id, but this doesn't seem to be working.
passing in the type and id manually works, but this kinda defeats the point of a polymorphic relationship.
any ideas?
On NavigationItem model, since you defined polymorphic relation as 'navigatable' it is expected that NavigationItem model's table contains navigatable_type and navigatable_id. First please ensure this checks out.
Creating records through relation's base function is not a valid method. It is not clear what you are trying to achieve there but when you want to set relation there is two standard way of achieving it:
1- Associate
When a relation is defined as belongsTo, you may use associate() function. Like so:
$account = Account::find(10);
$user->account()->associate($account);
2- Attach
Attach is used when relation is defined belongsToMany (pivot). It allows you to attach multiple records to a model instance/record.
$user = User::find(1);
$user->roles()->attach($roleId);
So if you want to set a 'navigatable' to a Navigation instance, you may:
$somePageInstance=Page::find(55);
$nagivation->navigatable()->associate($somePageInstance)
$nagivation->save();//remember to save, otherwise it won't be
Hello guys I am working on a laravel project for making api for passing the database value in json format but the problem is I have a users table in this table 2 ids 1 is primary key and second is business _id I want to get data according to business_id but it's getting data by id please help me how to solve this issue.
Here is my model code
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class user extends Model
{
protected $table = 'business';
}
Here is my Controller Code
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\user;
class GetController extends Controller
{
public function databybusinessid($business _id){
$users = new user();
$users = user::find($business _id);
return response()->json($users);
}
}
Thank you so much
You are using user::find($business _id)
find() method will automatically search by the primary key but none is defined in your model and Eloquent can't decide which one to pick from your table. Therefore, you should explicitly set your primary key in your model by adding the following line.
class user extends Model
{
protected $table = 'business';
protected $primaryKey = 'business_id';
}
If in doubt, you can also fetch database record by a specific column using where
$users = user::where('business_id', '=', $business _id)->get()
Laravel documentation about Eloquent ORM
https://laravel.com/docs/5.8/eloquent
find() Retrieve a model by its primary key..
So you have to use your code as:
$users = user::where('business_id',$business_id)->first();
// Notice first() Retrieve the first model matching the query constraints...
Or you can change your primary code in model
namespace App;
use Illuminate\Database\Eloquent\Model;
class user extends Model
{
protected $table = 'business';
protected $primaryKey = 'business_id';
}
find() works only on primary key. you need to use where instead.
or you can define business_id as primary key in your User model.
protected $primaryKey = 'business_id';
public function databybusinessid($business _id){
$users = new user();
$users = user::where('business_id',$business _id)->first();
return response()->json($users);
}
I am new to Laravel and also asked the question on Laracast without any success so far.
Here is my problem: I have a database layout something like this:
Table: categoryA_products
Table: categoryB_products
Table: categoryC_products
and per default the Laravel user table:
Table: user
I have create a two Laravel Eloquent models:
Product:
namespace App;
use Illuminate\Database\Eloquent\Model;
class Product extends Model
{
// protected $table = '';
public function users()
{
return $this->belongsTo( User::class );
}
}
User:
namespace App;
use Illuminate\Database\Eloquent\Model;
class User extends Model
{
public function products()
{
return $this->hasMany( Product::class );
}
}
As each product has a different table name I would normally create 1 model for each table but as they are all similar I would like to define the model table name at runtime.
I know I can do this with "$product->setTable()" but as I use the "newRelatedInstance" class from Laravel (hasMany and belongsTo) I cannot initiate the product class and set the table.
Is there a workaround for this?
Yes, I am aware that I could create a category table and link the products to each category but this is a fictional database model. There is a reason for this approach and I can explain it more in detail if needed. That said it make sense for this sample but I cannot use it for the live database.
I have a working solution with a model for each "category" but this is very messy.
Any help would be appreciated.
Since you're unable to load the relations, you could try referencing and re-initializing them like:
$relations = $product->getEagerLoads();
$attributes = $product->getOriginal();
table_name = 'categoryA_products'; // or categoryB_products or categoryC_products
$product->newQuery()
->newModelInstance($attributes)
->setTable($table_name)
->setEagerLoads($relations)
->...
I have the database structure that have a classes table, a users table and users_classes table that matches the other two, because a user can belong to multiple classes. I have a problem now. I have code like this:
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Support\Facades\DB;
class Classes extends Model
{
protected $table = 'classes';
public function students()
{
}
}
And I want to be able to access the students of the class by typing $class = Classes::find(1) and then $class->students to access the students. How do I define the relationship without using the query builder? I want to use eloquent. Im a noobie in Laravel pls dont downvote.
You use a belongsToMany relation.
If your users_classes table has the fields user_id and class_id you can do the following:
public function students()
{
return $this->belongsToMany(Student::class, 'users_classes', 'class_id', 'user_id');
}
I have a table named tasks and a model named Task. In my controller method when i run this piece of code
<?php
namespace App\Http\Controllers;
use DB;
//use app\Task;
use DateTime;
use Illuminate\Http\Request;
use Illuminate\Support\Facades\Input;
class Task_Controller extends Controller
{
//
public function decide()
{
if ($input=="show all task")
{
//$rows=DB::table('task')->get();
$rows=\App\Task::all();
foreach($rows as $values)
{
foreach($values as $key=>$val)
echo "$key : $val <br>";
echo "<br><br>";
}
}
}
It gives me following error:
SQLSTATE[HY000]: General error: 1 no such table: tasks (SQL: select * from "tasks")
That is the model should have linked to the task table instead it is linked to the tasks table Why??.
How to make model gets linked to a specific table.
My model class code goes like this
namespace App;
use Illuminate\Database\Eloquent\Model;
class Task extends Model
{
//
}
You should name your table tasks, this is the best option.
Another way to fix this is to use $table property:
protected $table = 'task';
Note that we did not tell Eloquent which table to use for our Flight model. By convention, the "snake case", plural name of the class will be used as the table name unless another name is explicitly specified. So, in this case, Eloquent will assume the Flight model stores records in the flights table. You may specify a custom table by defining a table property on your model
https://laravel.com/docs/5.4/eloquent#defining-models
By default, the table name is the plural of the class name. If you want it to point to a different table, then in your model, add
protected $table = 'task';
By default laravel pluralizes the model names to be be the table names unless stated otherwise in the model by.
protected $table = 'task';