PDO pagination with LIKE - php

Question

The following PHP SQL code shows error
Recoverable fatal error: Object of class PDOStatement could not be converted to string in /home/customer/xxxx/fetch_data.php on line 28
I was trying to display products information from the table filter
There are two $statement->execute();, one is to count total search results and another one is to display products for the current page.
I new to PDO method and not an expert in overall coding.
The $filter_query = $stmt . 'LIMIT '.$start.', '.$limit.''; is causing issues.
With that and related functions, the code works and displays data. But if I enable it, the error shows up.
$limit = '5';
$page = 1;
if($_POST['page'] > 1)
{
$start = (($_POST['page'] - 1) * $limit);
$page = $_POST['page'];
}
else
{
$start = 0;
}
$search = "%samsung%";
$stmt = $connect->prepare("SELECT * FROM filter WHERE product_name LIKE :needle");
$stmt->bindParam(':needle', $search, PDO::PARAM_STR);
##
##
$filter_query = $stmt . 'LIMIT '.$start.', '.$limit.'';
$statement->execute();
$total_data = $stmt->rowCount();
$stmt = $connect->prepare($filter_query);
$stmt->execute();
$result = $stmt->fetchAll();
$total_filter_data = $stmt->rowCount();
$output = '
<h3> '.$total_data.' results found </h3>
and display each product
I tried the following code as suggested by Your Common Sense and the pagination and total search result count is working fine, but no products are getting displayed.
$limit = '5';
$page = 1;
if($_POST['page'] > 1)
{
$start = (($_POST['page'] - 1) * $limit);
$page = $_POST['page'];
}
else
{
$start = 0;
}
$name=str_replace(' ', '%', $_POST['query']);
$search = "%$name%";
$base_sql = "SELECT %s FROM filter WHERE product_name LIKE ?";
##
##
####
$count_sql = sprintf($base_sql, "count(*)");
$stmt = $connect->prepare($count_sql);
$stmt->execute([$search]);
$total_data = $stmt->fetchColumn();
####
$data_sql = $count_sql = sprintf($base_sql, "*")." LIMIT ?,?";
$stmt = $connect->prepare($data_sql);
$stmt->execute([$search, $start, $limit]);
$result = $stmt->fetchAll();
##
$output = '
<h3> '.$total_data.' results found </h3> ';
if($total_data > 0)
{
foreach($result as $row)
{
and display each product
Using the following line makes the code show some data, but the pagination is not working.
$data_sql = sprintf($base_sql, "*");
$stmt = $connect->prepare($data_sql);
$stmt->execute([$search]);
$result = $stmt->fetchAll();

Answer 1

That's a not a trivial task as we need to run the same query twice but with minor differences. The first query will use count(*) SQL function to get the total number of records matching the search criteria. The second query will select actual fields with LIMIT clause to get the data for the single page.
$base_sql = "SELECT %s FROM filter WHERE product_name LIKE ?";
$count_sql = sprintf($base_sql, "count(*)");
$stmt = $connect->prepare($count_sql);
$stmt->execute([$search]);
$total = $stmt->fetchColumn();
$data_sql = $count_sql = sprintf($base_sql, "*")." LIMIT ?,?";
$stmt = $connect->prepare($data_sql);
$stmt->execute([$search, $start, $limit]);
$data = $stmt->fetchAll();
Important: In order for this code to work, make sure you are connecting to mysql properly. the proper connection will let a LIMIT clause to accept placeholders and also will warn you in case of any problems.