i've got little problem here. I recieve reg_time from database in this format: Y-m-d H:i:s (2020-08-26 13:50:11)
and i want to compare it with current time: $today = date("Y-m-d H:i:s");
Is there any function for it? THX
The DateTime and DateInterval classes are intended for this:
<?php
$timeInput = '2020-08-26 13:50:11';
$origin = new DateTime($timeInput);
$target = new DateTime();
$interval = $origin->diff($target);
echo $interval->format('Registered %y years, %m months, %d days, %h hours, %i minutes, %s seconds ago').PHP_EOL;
There's a package called Carbon, it's very useful for date manipulation. For your use case looks like it could be solved using a method called diffForHumans()
So, the full example would be:
Carbon::parse('2020-08-26 13:50:11')->diffForHumans();
The output would be 1 day ago
Edit:
The question was fully rewritten
Related
I am trying to find the time difference between an expiry date and today's date, but my code doesn't work.
$time_one=DateTime::createFromFormat('d/m/Y', get_field('expirydate'));
$time_two=new DateTime();
$timeleft = $time_one->diff($time_two);
echo $timeleft;
Try:
echo $timeleft->format('%a days');
So when you apply diff function to DateTime object -> you receive a DateInterval object. To access its properties about total difference between dates you should apply method called format.
The diff method returns you an DateInterval object. You must format the output in order to see how many days, hours, minutes, seconds remained:
$dateTimeInTheFuture = DateTime::createFromFormat('d/m/Y', get_field('expirydate'));
$dateInterval = $dateTimeInTheFuture->diff(new DateTime());
echo 'Time remained until expire: ' . $dateInterval->format('%d days, %h hours, %i minutes, %s seconds');
Read more about DateInterval.format method
i've got 2 time stamps: $start_time = 1312346227; and $end_time = 1312346466;
and i am trying to substract them to see the time inbetween $end_time = $end_time - $start_time;
and i get 239.
What is the proper way of converting this to a human readable date?
if i try echo date("h:i:s A",$end_time); i get 04:03:59 and it should be 00:03:59
any ideas?
Thanks
If you have PHP 5.3, use the DateInterval class.
Example stolen from the manual page on DateInterval::format():
<?php
$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);
// %a will output the total number of days.
echo $interval->format('%a total days')."\n";
// While %d will only output the number of days not already covered by the
// month.
echo $interval->format('%m month, %d days');
?>
You get addiionl four hours, because of your timezone. Remember that unix timestamp is the number of seconds since 1970-01-01 00:00:00 UTC. If you (or your server) are in UTC+4 TZ, then date() will implicitly do a timezone conversion to your local time.
Solution? Use gmdate() instead
You need to set your timezone correctly. http://www.php.net/manual/en/function.date-default-timezone-set.php
Assume the date is:
$date = "2011-08-28";
It need to calculate 3 months previous to $date - how can that be done?
$new_timestamp = strtotime('-3 months', strtotime($date));
You can then use the new timestamp with the php date() function to display the new date how you wish, for example:
echo date("Y-m-d",$new_timestamp);
For me this way is much better because the code is more readable.
$datetime = Datetime::createFromFormat('Y-m-d', "2011-08-28");
$datetime->modify('-3 months');
echo $datetime->format('Y-m-d');
edit: I'm an idiot. You could do the above as follows
$datetime = new Datetime("2011-08-28");
$datetime->modify('-3 months');
echo $datetime->format('Y-m-d');
edit: As pointed out by calumbrodie, you can use the sub method instead of inverting the interval and adding it to the date object
I was trying to do something similar to the original question. I needed to subtract 1 day from a DateTime object. I know the other solutions work, but here's another way I liked better. I used this function:
function getPreviousDay($dateObject){
$interval = new DateInterval('P1D');
$dateObject->sub($interval);
return $dateObject;
}
$dateObject is a DateTime object that can have any date you wan't, but as I wanted the current date, I wrote:
$dateObject = new DateTime('now');
What my function does, is subtract 1 day from the date it receives, but you can modify it so it subtracts 3 months modifying the DateInterval constructor like this:
$interval = new DateInterval('P3M');
$dateObject->sub($interval);
return $dateObject;
You can find the explanation on the string format used in the DateInterval constructor here
DateInterval constructor documentation
There you'll se that letter 'P' (period) is mandatory, the you use an int to specify period length and then specify the period type, in the case of months 'M'. It looks as if there was an error in the documentation, it says that "M" is used for months and minutes, but it actually works for months. If you need to use minutes, you must specify "PTM", for example "PT3M" for 3 minutes, outside the table it says you must use the "T" identifier for time intervals.
edit:
To give a complete example, you have to use this format for a full date time interval:
$format = 'P1Y2M4DT2H1M40S';
This will represent an interval of 1 year, 2 months, 4 days, 2 hours,1 minute and 40 seconds
Hope this helps someone
<?php
$threemonthsago = mktime(0, 0, 0, date("m")-3, date("d"), date("Y"));
?>
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The server that I have my sited hosted is on PHP5.12.14, and I have an error when I run the DateTime object from PHP5.3
# DateTime::add — Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
$date = new DateTime($item_user['mem_updated']);
# add a day to the object
$date -> add(new DateInterval('P1D'));
the error,
Fatal error: Call to undefined method DateTime::add() in /homepages/xxx.php on line xx
So, I have look for the other solutions rather than sticking to PHP5.3's DateTime object. How can I write the code to replace the code above?
basically I have this date and time data (for instance - 2011-01-21 02:08:39) from the mysql database, and I just need to add 1 day or 24 hours to that date/time, then passing it into a function below,
$time_togo = time_togo($date -> format('Y-m-d H:i:s'));
thanks.
strtotime would work
$timestamp = strtotime($item_user['mem_updated']);
$time_togo = date("Y-m=d H:i:s", strtotime("+1 Day", $timestamp));
Here's an example:
$date = date('Y-m-d H:i:s');
$new_tstamp = strtotime($date.'+1WEEK');
$new_date = date('Y-m-d H:i:s', $new_tstamp);
In other words, strtotime lets you use date expressions like +1DAY, +1MONTH and so on.
The above will work for date string (e.g.: 2010-01-01). If your original date is a Unix timestamp, you can still use strtotime, although a bit differently:
$new_tstamp = strtotime('+1WEEK', $timestamp);
I want to get the absolute days away a datetime is from today. For example, i would like to know if a date is 2 days away, or 78 days away, or even 5,239 days away (not likely, but you get the idea). I am using an MS SQL database which is returning datetimes where the time components are all 00:00:00.
date_diff returns relative values that you then have to do some crazy math with to get absolute dates do to calculating months, years, etc.
Also, i am having issues getting the date component only of today's date in php.
Edit:
Thanks to mr. w. This is what i ended up with:
$date = $row['AirdateDateTime'];
$today = date_create(date("Y-m-d"));
$away = date_diff($today, $date);
$d = $away->format("%R%a");
The date_create() part was the part i was originally missing to convert to an actual datetime. Also, the format needs to be %R%a. Using %R%d only works for dates in this month.
The date_diff() function (really, the DateTime::diff() method) is what you want, and it's actually not hard. In fact, I think the example in the docs is exactly what you're after:
<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%d days');
?>
or
<?php
$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2009-10-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%d days');
?>
What's returned is a DateInterval object, which you can format any way you want with its format() method. Above, it's being formatted to days, but you have a ton of options; see http://us.php.net/manual/en/dateinterval.format.php.
You shouldn't need to do any math yourself.
[EDIT - forgot this part]
As for getting the date component of today's date, you can do something like this:
<?php
echo date('Y-m-d');
?>
See http://us.php.net/manual/en/function.date.php.
Try this
$date1 = new DateTime('2012-10-28 00:00:00',new DateTimeZone('Europe/London'));
$date2 = new DateTime('2012-10-28 03:00:00',new DateTimeZone('Europe/London'));
$interval = date_diff($date1, $date2);
$format = '%y years, %m months, %d days, %h hours, %i minutes, %s seconds, %a total days %R';
echo $interval->format($format);
if want to change the format try this
http://www.w3schools.com/php/func_date_date.asp
It's probably easiest to convert to unix timestamps (seconds since 1970) and then get the difference.
strtotime() and time() are your friends.
An alternative to what has already been suggested is the DateTime library:
$today = date("Y-m-d");
$today = new DateTime($today);
$future = new DateTime('2010-10-25');
$interval = $today->diff($future);
echo $interval->format('%d days away'); //outputs 17 days away
It sounds like what you want is
<?php
$yourDate = '2010-10-05';
echo ciel((strtotime($yourDate) - time()) / 60 / 60 / 24);