Laravel complicated filter query - php

Question

I need to write API query which consists of "status", "category_id", "city_id" fields, and there are a lot of cases:
1) status is an array => ['OPEN','CLOSED'] OR category_id is an array => [1,2,4] AND city_id = 7 (could be any integer)
2) status is an array => ['OPEN','CLOSED'] OR category_id is an integer => 2 AND city_id = 7 (could be any integer)
3) status is a string => 'OPEN' OR category_id is an array => [1,2,4] AND city_id = 7 (could be any integer)
4) status is an array => ['OPEN','CLOSED'] AND city_id = 7 (could be any integer)
5) category_id is an array => [1,2,4] AND city_id = 7 (could be any integer)
6) status is a string => 'OPEN' AND city_id = 7 (could be any integer)
7) category_id is an integer => 1 AND city_id = 7 (could be any integer)
I have already tried to write this query, however, confused in the number of statements (the code is not working correctly, there is also district_id, but for simplicity of example I did not mention it):
$cat = cleanString(request()->get('category_id'));
$status = cleanString(request()->get('status'));
$city = cleanString(request()->get('city_id'));
$dist = cleanString(request()->get('district_id'));
if ($cat != null && $status != null) {
if (is_array($cat) && is_array($status)) {
$issues = $issues->whereIn('category_id', $cat)->orWhereIn('status', $status)->where('city_id', $city)->where('district_id', $dist);
} elseif (is_array($cat)) {
$issues = $issues->whereIn('category_id', $cat)->where('status', $status)->where('city_id', $city)->where('district_id', $dist);
} elseif (is_array($status)) {
$issues = $issues->whereIn('status', $status)->where('category_id', $cat)->where('city_id', $city)->where('district_id', $dist);
} elseif (is_string($cat) && is_string($status)) {
$issues = $issues->where('category_id', $cat)->where('status', $status)->where('city_id', $city)->where('district_id', $dist);
}
} elseif ($cat == "" || $cat == []) {
$issues = $issues->where('status', $status)->where('city_id', $city)->where('district_id', $dist);
} elseif ($status == "" || $status == []) {
$issues = $issues->where('category_id', (int)$cat)->where('city_id', $city)->where('district_id', $dist);
}
$issues = $issues->get();
Is there any way not to use so many if-else cases and make code looks cleaner and work properly?
Thanks everyone for answers in advance!

Answer 1

I wrote better version of query, however the disadvantage is I have to pass status or category_id as an array like this + if city_id AND/OR district_id is null, then no data returns:
{
"city_id" : 5,
"district_id" : 9,
"category_id" : [5,4],
"status" : ["REJECTED"]
}
And here is code:
if ($cat != null && $status != null) {
$issues = $issues->where('city_id', $city)->where('district_id', $dist)
->where(function ($q) {
$q->whereIn('category_id', cleanString(request()->get('category_id')))
->orWhereIn('status', cleanString(request()->get('status')));
});
} elseif ($cat == "" || $cat == []) {
$issues = $issues->where('city_id', $city)->where('district_id', $dist)
->where(function ($q) {
$q->whereIn('status', cleanString(request()->get('status')));
});
} elseif ($status == "" || $status == []) {
$issues = $issues->where('city_id', $city)->where('district_id', $dist)
->where(function ($q) {
$q->whereIn('category_id', cleanString(request()->get('category_id')));
});
}

Answer 2

Force convert to array
$filters = [
'category_id' => (array) cleanString(request()->get('category_id', [])),
'status' => (array) cleanString(request()->get('status', [])),
];
$filters = array_filter($filters);
foreach($filters as $key => $val) {
$issues->orWhereIn($key, $val);
}