PHP Problem Array to string conversion using FetchAll - php

Question

I have recently started studying PHP and I'm using Zend Framework v1.12.
I can't print the elements obtained by using FetchAll().
$stmt = $db->query('SELECT * FROM team');
$obj = $stmt->fetchAll();
foreach ($obj as $value) {
echo $value;
}
This is the notice (repeated x7):
Notice: Array to string conversion
Using var_dump I have this:
array(7) {
[0]=> array(2) {["id_team"]=> string(1) "1" ["nameteam"]=> string(10) "Ac Picchia" }
[1]=> array(2) { ["id_team"]=> string(1) "2" ["nameteam"]=> string(4) "test" }
[2]=> array(2) { ["id_team"]=> string(1) "3" ["nameteam"]=> string(4) "ciao" }
[3]=> array(2) { ["id_team"]=> string(1) "4" ["nameteam"]=> string(2) "oi" }
[4]=> array(2) { ["id_team"]=> string(1) "5" ["nameteam"]=> string(3) "xtz" }
[5]=> array(2) { ["id_team"]=> string(1) "6" ["nameteam"]=> string(3) "123" }
[6]=> array(2) { ["id_team"]=> string(1) "7" ["nameteam"]=> string(1) "x" } }

Answer 1

Teh object returned by the FetchAll is a Array of Arrays. So when you do the foreach and try to print every object in the array you got that error.
To fix it you should do something like:
$stmt = $db->query('SELECT * FROM team');
//I renamed this variable to make the code more readable.
$teams = $stmt->fetchAll();
foreach ($teams as $team) {
print_r($team); //This will print the array
}

Answer 2

I found the solution, even if it was a trivial problem, I write my solution to the problem maybe it will help someone.
$stmt = $db->query('SELECT * FROM team');
$obj = $stmt->fetchAll();
foreach ($obj as $value) {
echo $value['id_team'] , $value['nometeam'];
}

Answer 3

use loop like this :
$stmt = $db->query('SELECT * FROM team');
$obj = $stmt->fetchAll();
foreach ($obj as $key => $value) {
echo $value['id_team'].','. $value['nometeam'];
}