In my symfony 5 project I would like when submitting a certain form, compare the entity before and after submission.
So keep a copy of the original entity in order to perform processing.
I've :
$parametresAdmin = $entrepriseService->getParametresAdmin();
$form = $this->createForm(ParametresAdminType::class, $parametresAdmin, [
'entreprise' => $this->getUser()->getEntreprise(),
]);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$entrepriseService->updateParametres($parametresAdmin);
return $this->redirectToRoute('admin_parametres');
}
In fact, I want to get a copie of $parametresAdmin->getTypesConges() (which is a collection on OneToMany).
So, when the form is submitted, I want compare the old $parametresAdmin->getTypesConges() and the new $parametresAdmin->getTypesConges().
The "$parametresAdmin->getTypesConges()" part looks like this:
I can add / modify leave types on the fly. Except that I do not want to authorize the possibility of modifying the "Balance type" field for the types of leave that already exist. There is just for those that I add that I leave the possibility in the ChoiceType. So on the front side, it's good. But on the back side, no.
But it doesn't work
What I do :
I change the "Solde initial" for the first line :
But when I submit, I've the same value (the new value : 10 )
EDIT : Currently, I've now :
$parametresAdmin = $entrepriseService->getParametresAdmin();
$typeConges = $parametresAdmin->getTypesConges();
$oldTypesConges = clone $typeConges;
$form = $this->createForm(ParametresAdminType::class, $parametresAdmin, [
'entreprise' => $this->getUser()->getEntreprise(),
]);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$typeConges = $parametresAdmin->getTypesConges(); // update with new data
dd($oldTypesConges, $parametresAdmin->getTypesConges());
$entrepriseService->updateParametres($parametresAdmin);
return $this->redirectToRoute('admin_parametres');
}
You should clone your data like this :
$typeConges = $parametresAdmin->getTypesConges();
$oldTypeConges = clone $typeConges;
// handleRequest(), isValid(), isSubmit() ...
$typeConges = $parametresAdmin->getTypesConges(); // update with new data
dd(oldTypeConges, $parametresAdmin->getTypesConges());
phpdoc says about :
When an object is cloned, PHP will perform a shallow copy of all of the object's properties. Any properties that are references to other variables will remain references.
Take a look at this question on stackoverflow.
Use session variables to store the old data:
To store your data before rendering the form in the controller, use:
$this->get('session')->set('oldTypesConges ', $typesConges );
And after submitting, read the data stored to compare it with the new one:
$oldTypesConges = $this->get('session')->get('oldTypesConges ');
Now, you can compare $typesConges and $oldTypesConges.
This solution was inspired from here: How to set session variables for all the controllers in Symfony2?
$versionsBeforeSubmit = [];
foreach($produit->getVersions()->getIterator() as $version) {
$versionsBeforeSubmit[] = clone $version;
}
$form->handleRequest($request);
if($form->isValid() && !$hasError) {
dump($versionsBeforeSubmit);
}
Related
Since 3 weeks i try to learn php with the symfony framework.
I want to build an application with which i can track my expanses.
I made good progress but since 2 days i have a little logic problem so maybe someone can help me here.
I want to make a dashboard.(the main side of the project) There the user can monitor the expenditures.
This works. Now i want also a form at the dashboard, so the user can add new expenditures. I already implement a form but with a extra route. So in my ExpenditureController i have the functions dashboard and the function addExpenditure which generate different twig.html templates.
So the user can monitor his expenditures with ...budgetapp/expenditure/dashboard
and he can add new Expenditure with ...budgetapp/expenditure/addexpenditure
My Dashboard-Function
#[Route('/dashboard/', name: 'dashboard')]
public function dashboard(ExpenditureRepository $ar)
{
$user = $this->getUser();
$expenditures = $ar-> findexpendituresOfUser($user);
return $this->render('expenditure/dashboard.html.twig', [
'expenditures' => $expenditures,
]);
}
The expenditure/dashboard.html.twig shows the Expentiures of the current user in a table
My addExpenditure-Function
public function addExpenditure (ManagerRegistry $doctrine, Request $request){
$em = $doctrine->getManager();
$expenditure = new Expenditure();
$form = $this->createForm(ExpenditureType::class, $Expenditure);
$form->handleRequest($request);
if($form->isSubmitted()){
$em->persist($expenditure);
$em->flush();
}
return $this->render('expenditure/addexpenditure.html.twig', [
'addexpenditureForm' => $form->createView()
]);
}
The expenditure/addexpenditure.html.twig looks like this:
{% block body %}
<div class="container">
{{form(eintragenForm)}}
</div>
{% endblock %}
My problem /mistake in thinking:
How can i implement the form to the dashboard? So of course i can take the code from the addexpenditure function and put it 1:1 in the dashboard-funciton. but i dont think this is the right way? I also tried to including template fragments with the offical Embedding Controllers Documentation of Symfony, but this also dont work.
So someone can help me with a suggestion how you would handle this in your project?
Best regards
Markus
There are two possible solutions: put both view and add logic inside one controller's action, or separate them. Since you probably have some validation, it's reasonable to have both add and view code inside one action (otherwise, you'll have to pass errors via sessions, which is not very pretty). So basically, your dashboard/add action will look like this:
#[Route('/dashboard/', name: 'dashboard')]
public function dashboard(Request $request, ExpenditureRepository $ar, ManagerRegistry $doctrine)
{
$expenditure = new Expenditure();
$form = $this->createForm(ExpenditureType::class, $expenditure);
if ($request->isMethod('POST')) {
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$em = $doctrine->getManager();
$em->persist($expenditure);
$em->flush();
return $this->redirectToRoute('dashboard');
}
}
$user = $this->getUser();
$expenditures = $ar-> findexpendituresOfUser($user);
return $this->render(
'expenditure/dashboard.html.twig',
[
'expenditures' => $expenditures,
'addexpenditureForm' => $form->createView(),
]
);
}
What's happening here:
First you check if POST http method was used, if it was - it means
that form has been submitted and you can handle it. There is an alternative solution without checking request method, see comments for more.
If this is a GET request, just show ordinary dashboard
If the form is submitted and it's valid - save data and redirect to
the same page. Otherwise, you'll need to empty all submitted data
from the form, etc. (it's not the right way to do it)
If the form is invalid, do not redirect, just render the page
normally, and all errors will be shown.
Finally, you of course have to render the form on your dashboard.html.twig like you did: {{form(eintragenForm)}}
I have an entity (about 20/25 fields) and i want to edit it with a form.
I just want to edit (and display) few form field.
The problem is, all fields displayed are correctly update, but fields that are not rendered are update with "null" value by default.
My controller :
$em = $this->getDoctrine()->getManager();
$LaboRequest= $em->getRepository('MyBundle:LaboRequest')->find($id);
$form = $this->createForm('MyBundle\Form\LaboRequestType', $LaboRequest);
if ($request->isMethod('POST') && $form->handleRequest($request)->isSubmitted() && $form->isValid()) {
$em->persist($LaboRequest);
$em->flush();
return $this->redirectToRoute(...);
}
return $this->render('...', array(
'LaboRequest' => $LaboRequest,
'form' => $form->createView(),
));
I only render few fields in my view, so i can understand, by default symfony use "null" for fields that are not render.
But is there a way to edit a part of an entity and not affect data of the entity with "null" value ?
I'm not sure you can do that.
But you can extend your original form and call
$builder->remove('xxx')
for each field you want to remove
I need to be able to loop through a list of laravel request variables and do something with them. I want to be able to use a variable when calling the request object so that I can run it in a loop instead of writing a line of code for every one.
For example, my text inputs may have names that look something like this
contact_main_name
contact_main_telephone
contact_main_email
contact_sub_name
contact_sub_telephone
contact_sub_email
contact_backup_name
contact_backup_telephone
contact_backup_email
In my request, I don't want to have to write
$request->contact_main_name
$request->contact_main_telephone
For each different type of contact I may have, I want to be able to loop through them like so
$contactTypes = [
'main',
'sub',
'backup',
'head'
];
foreach($contactTypes as $type){
//Start a new contact
$contact = new Contact;
$contact->type = $type;
$contact->name = $request->${"contact_".$type."_name"};
$contact->telephone = $request->${"contact_".$type."_telephone"};
$contact->email = $request->${"contact_".$type."_email"};
$contact->save();
}
How would i use a variable name when calling a laravel $request so that I can just build an array of possible types and loop through them all?
Note
I know i can edit the input fields themselves to look something like name="contact[type][name]" and then loop through them, but I cant be changing the input names, I have to do it via php in the controller itself.
As answered in comments, to do this, change the method of calling the input and use the actual input() function itself.
$contactTypes = [
'main',
'sub',
'backup',
'head'
];
foreach($contactTypes as $type){
//Start a new contact
$contact = new Contact;
$contact->type = $type;
$contact->name = $request->input("contact_".$type."_name");
$contact->telephone = $request->input("contact_".$type."_telephone");
$contact->email = $request->input("contact_".$type."_email");
$contact->save();
}
As an aside, you could also modify it slightly to use array indices matching the field names; this would allow you to add fields later by adding the appropriate field to the database and HTML without touching the code, and use array_keys() to retrieve the types submitted to allow seamless addition of types. As long as your validations are tight, this is probably the most automated way to allow future expansion...
Ex. Field Names:
contact[main][name]
contact[main][telephone]
...
contact[backup][email]
Ex. Code:
foreach(array_keys($request->input('contact')) as $type) {
$contact = Contact::create($request->input('contact.'.$type));
$contact->type = $type;
$contact->save();
}
Using Symfony, version 2.3 and more recent, I want the user to click on a link to go to the edition page of an already existing entity and that the form which is displayed to be already validated, with each error associated to its corresponding field, i.e. I want
the form to be validated before the form is submitted.
I followed this entry of the cookbook :
$form = $this->container->get('form.factory')->create(new MyEntityFormType, $myEntity, array('validation_groups' => 'my_validation_group'));
$form->submit($request->request->get($form->getName()));
if ($form->isValid()) {
...
}
But the form is not populated with the entity datas : all fields are empty. I tried to replace $request->request->get($form->getName()) with $myEntity, but it triggered an exception :
$myEntity cannot be used as an array in Symfony/Component/Form/Extension/Csrf/EventListener/CsrfValidationListener.php
Does anyone know a method to feed the submit method with properly formatted datas so I can achieve my goal ? Note : I don't want Javascript to be involved.
In place of:
$form->submit($request->request->get($form->getName()));
Try:
$form->submit(array(), false);
You need to bind the the request to the form in order to fill the form with the submitted values, by using: $form->bind($request);
Here is a detailed explanation of what your code should look like:
//Create the form (you can directly use the method createForm() in your controller, it's a shortcut to $this->get('form.factory')->create() )
$form = $this->createForm(new MyEntityFormType, $myEntity, array('validation_groups' => 'my_validation_group'));
// Perform validation if post has been submitted (i.e. detection of HTTP POST method)
if($request->isMethod('POST')){
// Bind the request to the form
$form->bind($request);
// Check if form is valid
if($form->isValid()){
// ... do your magic ...
}
}
// Generate your page with the form inside
return $this->render('YourBundle:yourview.html.twig', array('form' => $form->createView() ) );
I am working with Zend Framework 2. I have defined some validation rules within my Entity class. These work as expected without any problems.
However, when in 'edit' mode I don't want the two file upload fields to be required. I tried to do setRequired(false) for both file upload fields within my controller action but it doesn't seem to have any effect on validation, it still throws a 'file was not found' message. What do I need to so the user can submit the form successfully without uploading any files?
Appreciate any help.
for change form validation in controller, you must remove current validation and set new validation. i hope this help you:
$form = new YourForm();
$form->setData ( $yourPostedData () );
$formInputFilter = $form->getInputFilter ();
// change filter
$formInputFilter->remove ( 'your_field' );
$inputFactory = new \Zend\InputFilter\Factory();
$formInputFilter->add ( $inputFactory->createInput ( array (
'name' => 'your_field',
'required' => false
) ) );
if ($form->isValid ()) {
//...
}
You can use validation groups
The documentation states:
Zend\Form provides a proxy method to the underlying InputFilter‘s setValidationGroup() method, allowing us to perform this operation.
And all you need to do is name the fields you require validating (omit the upload element names)
$form->setValidationGroup(array('foo', 'bar'));
if ($form->isValid()) {
// $data contains just 'foo' and 'bar'
$data = $form->getData();
}
The error message I was getting 'file was not found' made me realise the issue I was having was deeper than setting the validators/filters.
The form is processed via an AJAX script using a FormData object. I added the files to the object using:
oAgencyFormData.append("cssFilename", document.getElementById('logoName').files[0]);
and the object is then passed to the AJAX call. I realised that in the case when a file is not uploaded 'undefined' is being passed to the script. So I separated it into a variable which is assigned "" if no file has been specified:
var oLogoFile = document.getElementById('logoName').files[0];
var oCssFile = document.getElementById('cssFilename').files[0];
// define defaults for file upload fields (used if nothing is uploaded)
if(typeof oLogoFile === 'undefined'){
oLogoFile = '';
};
if(typeof oCssFile === 'undefined'){
oCssFile = '';
};
Once I did this then file validators worked as expected.
I had the same problem and this is how I solved it:
$form->remove('your_field');
$center->getInputFilter()->remove('your_field');
Hope it helps!