The problem is with this line:
if $var LIKE '1800%';
and I'm not sure how to fix it. Thanks.
<?php
//check to see if account number is like 1800*
if (isset($_POST['acct_number'])) {
$var = $_POST['acct_number'];
if $var LIKE '1800%'; {
//stop the code
exit;
} else {
echo 'normal account number';
}
}
?>
You need PHP not MySQL. For 1800% just check that it is found at position 0:
if(strpos($var, '1800') === 0) {
//stop the code
exit;
} else {
echo 'normal account number';
}
If it can occur anywhere like %1800% then:
if(strpos($var, '1800') !== false) {
//stop the code
exit;
} else {
echo 'normal account number';
}
Use substr function to get first 4 characters and compare it with 1800.
if(substr($var, 0, 4) == '1800')
{
// your code goes here.
}
``
Another way could be to use strpos()
if (strpos($var, '1800') === 0) {
// var starts with '1800'
}
I would use a regular expression for this preg_match('/^1800.+/', $search, $matches);
Related
I need help.
As I do?
String same other string with different number.
Example
if ($current_server == "Lobby-01") {
echo "visiting in Lobby"
} elif ($current_server == "Lobby-02"){
echo "visiting in Lobby"
} and more..
I thought about trying
if ($current_server == "Lobby-/[0-99]+/"){
echo "visiting in Lobby"
} else {
//is false, then it will not show the message
}
is correct?
How do I do it?
Can you help me?
Use preg_match:
if (preg_match("/\bLobby-[0-9]{2}\b/i", $current_server)) {
echo "visiting in Lobby";
}
else {
// no message
}
Demo
How to compare 2 variable using php like this ?
$aaa = "1234567890qwertyuiopsdflkjwerouioiuweewjkee";
$bbb = "1234567890qwertyuiop";
How to check
if(first char to twenty char of $aaa == $bbb)
{ echo "same"; }
else
{ echo "not same"; }
I assume you are searching for strncmp:
This function is similar to strcmp(), with the difference that you can specify the (upper limit of the) number of characters from each string to be used in the comparison.
if(strncmp($aaa, $bbb, 20) == 0) {
# First twenty characters match.
} else {
# First twenty characters don't match.
}
$aaafirst20 = $small = substr($aaa, 0, 20);
if(strcmp($aaafirst20 , $bbb){
}
else{
}
Try this :
You can use strcmp function for the same.
PHP docs # strcmp
if(strcmp($aaa,$bbb)){
echo "same";
} else {
echo "not same";
}
You can use strpos() to check if $bbb is found in $aaa, and starts at position 0.
if (strpos($aaa, $bbb) === 0) {
echo 'Same';
}
else echo 'Not same';
See demo
Your exact solution would be
// first reduce a to its first 20 characters
$trimmed = substr($aaa, 0, 20);
// now compare with b
if($trimmed == $bbb){
// same
}
Or, all in one line
if(substr($aaa, 0, 20) == $bbb){
// same
}
my problem is, i have a form which i fill blabla and after i submit i need to check if the var '$number' contains only 9 numbers. which means that if it contains at least 1 letter or has less or more than 9 length it should return false, else it should return true;
this is what i got so far:
if (!is_numeric ($number) {
//do
} else {
}
1st problem: This code should take care of the only numbers part but it doesnt, it always returns false.
2nd: do you guys know of any way to take care of the 9 digits only verification?
thanks and sorry for my bad english, not my native language :P
Your number may contain unwanted whitespaces which cause the is_numeric() test not to work properly
So do the following: $number = trim($number); to remove them.
Then indeed this snippet is good to check if your variable is a number:
if (!is_numeric ($number)) {
//do
} else {
}
And for the number digits do a if statement to see if your number is between 100000000 and 999999999
So the full code will be:
$number = trim($number);
if (!is_numeric ($number)) {
//do
} else {
if ($number >= 100000000 && $number <= 999999999) {
// Everything is ok
} else {
}
}
Didn't understood your complete question coz of you native language :p, but i think you want this:
if (is_numeric($number) {
if(strlen($number) == 9){
return true;
} else {
return false;
}
} else {
echo 'Not a number';
}
Check if it contains digits and check whether its exactly contains 9.
$number = '123456789';
if(!preg_match('/^\d{9}$/', $number)) {
echo 'not ok';
} else {
echo 'ok';
}
I have submitted some code to the redirected url and now trying to use this to echo some information out but can't figure out where I am going wrong.
I have the following code:
<?php $login_attempt = mysql_real_escape_string($_GET['login_attempt']);
if ($login_attempt) == '1'{
return 'failed';
}
?>
all I want to do is if the url has $login_attempt=1 I want to return the message 'failed' to the page.
There is no point of escaping anything if it doesn't enter anywhere important (like a database).
<?php
if ($_GET['login_attempt'] == '1') {
echo 'failed';
}
?>
Also, you have a problem in your if statement, that's corrected in the code above. Be sure to include all of the condition inside of parenthesis, and not just one side of the equality check.
Also, if you wish to display something on the screen, you should echo it, not return.
how about:
if ($login_attempt == '1'){
echo 'failed';
}
Try this one. Your error in $login_attempt == '1':
<?php $login_attempt = mysql_real_escape_string($_GET['login_attempt']);
if ($login_attempt == '1'){
echo 'failed';
return false;
}
?>
As others already mentioned you have several problems but the syntax error comes from this:
if ($login_attempt) == '1'{
it should be
if ($login_attempt == '1') {
Dont u think if ($login_attempt) == '1' should be something like this ($login_attempt == '1') Sorry...many others also suggested this :P
At the first, I must tell you that you have a mistake in your IF condition. You typed == outside of ().
In addition, you have to be aware of status of setting your variable through your URL. Check the code below. In this code, I made a function to check the status. Default status is true, and we will check it just for a negative condition. I hope it could be useful for you:
<?php
function check() {
if (isset($_GET['login_attempt'])) {
$login_attempt = mysql_real_escape_string($_GET['login_attempt']);
if ($login_attempt == '1') {
return false;
} else {
return true;
}
} else {
return true;
}
}
if (!check()) echo('Error Message');
?>
I've some problems with handling Boolean values in PHP. It is a validation script before storing data into database. I wrote a global validator that will validate and return a Boolean value whether the validation was successful .
Here is my code.
//VALIDATE
$isValid = true;
foreach($team as $key=>$val) {
if(!is_array($val)){
$isValid = $isValid && validate($val, $key);
}
}
for($it=0;$it<count($team['members']);$it++){
foreach($team['members'][$it] as $key=>$val) {
$isValid = $isValid && validate($val, $key);
}
}
if(!$isValid) { // EDITED: if(!isValid)
echo "validation error";
exit(1);
}
//END OF VALIDATE
The validate function is working properly but sometimes I end up getting $isValid = true or the other way, when I try with some test cases.
Hmm.. What am I doing wrong here ?
Please check, if this form does the trick:
if( false === $isValid) {
echo "validation error";
exit(1);
}
Note, that ( ! $isValid ) or (false == $isValid ) in some cases return results, which are at first look wrong. See for example the hint in the strpos() documentation.
In fact, the results are fine, since operations line ! or == try to cast operands in a 'useful' way.
That said, it's always better to user the === operator, since it checks values and types of operands. Please see operator overview.
if(!isValid) { falls back to if (!"isValid"), if there is no constant isValid. You probably meant if (!$isValid) {.
if(!isValid) {
isValid has no dolar, (you need to give variables in PHP some cash) so:
if(!$isValid) {
Source : http://bit.ly/1hxDmVR
Here is sample code for working with logical operators in PHP. Hope it will helpful:
<html>
<head>
<title>Logical</title>
</head>
<body>
<?php
$a=10;
$b=20;
if($a>$b)
{
echo " A is Greater";
}
elseif($a<$b)
{
echo " A is lesser";
}
else
{
echo "A and B are equal";
}
?>
<?php
$c=30;
$d=40;
//if(($a<$c)AND($b<$d))
if(($a<$c)&&($b<$d))
{
echo "A and B are larger";
}
if(isset($d))
$d=100;
echo $d;
unset($d);
?>
<?php
$var1=2;
switch($var1)
{
case 1:echo "var1 is 1";
break;
case 2:echo "var1 is 2";
break;
case 3:echo "var1 is 3";
break;
default:echo "var1 is unknown";
}
?>
</body>
</html>
I think the problem is that your $isValid variable can be changed many times in the loops and by the end of your code simply applies to the last value in your final loop.
You should set it to true initially and then only set it to false IF your validity check fails - not simply assign its value based on every single validity check.