I have four tables technologies(id, name), tasks(id, name), requests(id, status_id, comment, task_id, created_at), technology_task(id, task_id, technology_id)
I want to get the requests whose status_id is 2 and join the tasks table which has specific technologies inserted in the technology_task pivot table. I want to group the result based on the date column created_at. Is this possible through Lravel model eloquent? I have tried the below method.
$this->model
->with('task', 'task.technologies')
->where('status_id', 2)->get()
->groupBy(function ($val) {
return Carbon::parse($val->created_at)->format('d-m-Y')
This is the Request model and this will return all the requests whose status_id is 2 along with the related task and technologies. But I only want the requests whose task have specific technologies, and I want to check that using something like ->whereIn('id', [1, 2, 3])->get()
How to achieve this using model? or do I need to use a custom query
Assuming $this->model is your Request model, and all your relationships are set correclty, you can use whereHas:
$technologyIds = [1, 2, 3];
$collection = $this->model
->with(['task', 'task.technologies'])
->whereHas('task.technologies', function($query) use ($technologyIds)
{
// here you can check using whereIn
$query->whereIn('technologies.id', $technologyIds);
})
->where('requests.status_id', 2)
->get();
If you want to use the groupBy inside the MySQL query, you will need to define what data should MySQL select when grouping. You can achieve that using aggregation functions. You weren't clear about the data you want to select, the code bellow should return:
the greatest id of the grouped rows,
unique comments concatenated with space
created_at
$technologyIds = [1, 2, 3];
$collection = $this->model
->with('task', 'task.technologies')
->whereHas('task.technologies', function($query) use ($technologyIds)
{
$query->whereIn('technologies.id', $technologyIds);
})
->where('requests.status_id', 2)
->groupBy('requests.created_at')
->selectRaw('
MAX(requests.id) AS id,
GROUP_CONCAT(DISTINCT requests.comment
ORDER BY requests.comment ASC SEPARATOR ' ') AS comments,
requests.created_at
')
->get();
Check out the docs to see how each aggregation functions works.
Related
I have a table (A) that has a One to Many relation with another table (B).
I want to query Table A and eager load Table B with the Table A results - but I also want to sort Table A by a value in Table B.
I have tried using OrderBy in the query and also trying SortBy on the resultant collection but cannot get the Table A data to be sorted by the value found in Table B.
Example of what I have tried:
$query = ModelA::with("ModelB"])->get()->sortByDesc('ModelB.sortValue');
Keep in mind, I am only interested in the LATEST record from Table B. So I need to query Table A and sort by a value in the LATEST records of Table B.
How can I achieve this?
EDIT:
The below (as suggested by #ljubadr) works pretty close, but the issue is that there are many record in Table B which means that it doesn't reliably sort as it doesn't seem to sortby the latest records in Table B. Can I have the join return ONLY the latest record for each ID?
$query = ModelA::select('TableA.*')
->join('TableB', 'TableA.id', '=', 'TableB.col_id')
->groupBy('TableA.id')->orderBy('TableB.sortCol', 'desc')
->with(['x'])
->get();
EDIT 2:
#Neku80 answer has gotten me closest but it seems to not sort the column with the greatest accuracy.. I'm sorting a Decimal column and for the most part it is in order but in some places the items are out of order..
$latestTableB = ModelB::select(['TableA_id', 'sortByColumnName'], DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.sortByColumnName')
->get();
For example, the ordering is like:
0.0437
0.0389
0.0247 <-- -1
0.025 <-- +1
0.0127
When I delete all rows except for the 'latest' rows, then it orders correctly, so it still must be ordering with old data...
I have found a solution:
ModelA::select('TableA.*', 'TableB.sortByCol as sortByCol')
->leftJoin('TableB', function ($query) {
$query->on('TableB.TableA_id', '=', 'TableA.id')
->whereRaw('TableB.id IN (select MAX(a2.id) from TableB as a2 join TableA as u2 on u2.id = a2.TableA_id group by u2.id)');
})
->orderBy('TableB.sortByCol')
->get();
Another alternative to order is like this:
$users = User::orderBy(
Company::select('name')
->whereColumn('companies.user_id', 'users.id'),
'asc'
)->get();
Here we are ordering in asc order by company name field.
In this article it is explained in detail.
You can simply execute a left join query:
ModelA::query()->leftJoin('model_b_table', 'model_a_table.primary_key', '=', 'model_b_table.foreign_key')->orderBy('model_a_table.target_column')->get();
This should work if you only need TableB's ID and created_at columns:
$latestTableB = ModelB::select('TableA_id', DB::raw('MAX(created_at) as created_at'))
->groupBy('TableA_id');
$query = ModelA::select('TableA.*')
->joinSub($latestTableB, 'latest_TableB', function ($join) {
$join->on('TableA.id', '=', 'latest_TableB.TableA_id');
})
->orderBy('latest_TableB.created_at')
->get();
This is my controller code:
if ($request->genre && !$request->search) {
$genres = explode(',', $request->genre);
return Movie::with('genres')->whereHas('genres', function ($q) use ($genres) {
return $q->whereIn('id', $genres);
})->paginate(10);
}
My pivot table contains movie_id and genre_id. Both movies and genres tables do not contain reference of ID of each other.
I would need to select all movies from the table which have genres selected by the user.
For example, an array of id's = [1, 4, 9] and to select from pivot table movies that contain those genre ids.
Thanks in advance!
EDIT:
General problem was return inside callback and the way I handled data later on. Thanks for your answers, I appreciate it! :)
You did a wrong query, try the given query.
return Movie::with(['genres'])->whereHas('genres' ,function ($query) use ($genres){
$query->whereIn('id', $genres);
})->paginate(10);
I'm trying to get all the data from the parent that only has a child. Please see my code below.
$customers = Customer::with(['items' => function($query){
return $query->where('status', 2);
}])->get();
dd($customers);
But the code above returns all the customer. By the way, I'm using laravel 4.2.
Items Table:
Customer Table:
with() is for eager loading. That basically means, along the main model, Laravel will preload the relationship(s) you specify. This is especially helpful if you have a collection of models and you want to load a relation for all of them. Because with eager loading you run only one additional DB query instead of one for every model in the collection.
has() is to filter the selecting model based on a relationship. So it acts very similarly to a normal WHERE condition. If you just use has('relation') that means you only want to get the models that have at least one related model in this relation.
e.g :
$users = Customer::has('items')->get();
// only Customer that have at least one item are contained in the collection
whereHas() works basically the same as has() but allows you to specify additional filters for the related model to check.
e.g
$users = Customer::whereHas('items', function($q){
$q->where('status', 2);
})->get();
// only customer that have item status 2
Adding group by to calculating sum
this is another example from my code :
Customer::select(['customer.name', DB::raw('sum(sale.amount_to_pay) AS total_amount'), 'customer.id'])
->where('customer.store_id', User::storeId())
->join('sale', 'sale.customer_id', '=', 'customer.id')
->groupBy('customer.id', 'customer.name')
->orderBy('total_amount', 'desc')
->take($i)
->get()
in your case :
Customer::select(['customer_id', DB::raw('sum(quantity) AS total')])
->whereHas('items', function ($q) {
$q->where('status', 2);
})
->groupBy('customer_id')
->get();
whereHas() allow you to filter data or query for the related model in your case
those customer that have items and it status is 2
afetr getting data we are perform ->groupBy('customer_id')
The GROUP BY statement is often used with aggregate functions (COUNT, MAX, MIN, SUM, AVG) to group the result-set by one or more columns.
select(['customer_id', DB::raw('sum(quantity) AS total')]) this will select customer id and calculate the sum of quantity column
You should use whereHas not with to check child existence.
$customers = Customer::whereHas('items', function($query){
return $query->where('status', 2);
})->get();
dd($customers);
I assume you already defined proper relationship between Customer and Item.
You should try this:
$customers = Customer::whereHas('items', function($query){
$query->where('status', 2);
})->get();
dd($customers);
Customer::select(['items.customer_id',DB::raw('count(items.id) AS total_qty')])
->join('items', 'items.user_id', '=', 'customer.customer_id')
->groupBy('items.customer_id')
->havingRaw('total_qty > 2')
->get();
OR
$data=DB::select("select `items`.`customer_id`, count(items.id) AS total_qty
from `customers`
inner join `items`
on `items`.`customer_id` = `customers`.`customer_id`
group by `items`.`customer_id` having total_qty >= 2");
correct table name and column name.
In my mySQL database I have 3 tables:
cocktails
ingredients
cocktail_ingredient
I can choose multiple ingredients ID, ex. [1,50,60,7,3]
I need to find the cocktails that I can prepare with ONLY this list of ingredients. It is possible to have less ingredients but they ALL must be presents in my ingredients list [1,50,60,7,3].
I declared my ManyToMany relationship, i created my Models, everything works, now I try to create my query with the ORM:
$ids = [1,50,60,7,3];
$coktails = Cocktail::has('ingredients','<=',count($ids))
->whereHas('ingredients',function($q) use ($ids){
$q->whereIn('ingredients.id',$ids);
})
->get();
I tried also:
$coktails = Cocktail::has('ingredients','<=',count($ids))
->whereHas('ingredients',function($q) use ($ids){
foreach ($ids as $id){
$q->where('ingredients.id',$id);
}
})
->get();
It's always a wrong count, i know my problem is in my whereHas Closure, but i can't find it.
Thank you
In your example, your target list of ingredients is [1,50,60,7,3]. Imagine you have a cocktail that requires ingredients [1, 2].
Based on your current logic:
has('ingredients', '<=', count($ids)) will match, because 2 <= 5, and
whereHas('ingredients', function($q) use ($ids) { $q->whereIn('ingredients.id', $ids); }) will match, because the subquery will return a record for id 1, and, by default, whereHas is only looking for at least one record.
So, based on that logic, cocktail with ingredients [1, 2] will be returned, and that is not what you want.
What you're really looking for is to make sure that you only get cocktails that don't have any ingredients that are not in your target list of ids. [1, 50] should match, since it is a subset, but [1, 2] should not, because ingredient 2 is not in the original set.
To handle this, you'll want to use a combination of the whereDoesntHave method and the whereNotIn method.
$ids = [1,50,60,7,3];
$cocktails = Cocktail::whereDoesntHave('ingredients', function($q) use ($ids) {
$q->whereNotIn('ingredients.id', $ids);
})
->get();
This statement is saying "get all the cocktails that don't have an ingredient that is not in this list of ingredients." [1, 50] will match, because it doesn't have any ingredients that are not in the list. However, [1, 2] will not match, because it does have an ingredient that is not in the list (2).
I have two tables, say "users" and "users_actions", where "users_actions" has an hasMany relation with users:
users
id | name | surname | email...
actions
id | id_action | id_user | log | created_at
Model Users.php
class Users {
public function action()
{
return $this->hasMany('Action', 'user_id')->orderBy('created_at', 'desc');
}
}
Now, I want to retrieve a list of all users with their LAST action.
I saw that doing Users::with('action')->get();
can easily give me the last action by simply fetching only the first result of the relation:
foreach ($users as $user) {
echo $user->action[0]->description;
}
but I wanted to avoid this of course, and just pick ONLY THE LAST action for EACH user.
I tried using a constraint, like
Users::with(['action' => function ($query) {
$query->orderBy('created_at', 'desc')
->limit(1);
}])
->get();
but that gives me an incorrect result since Laravel executes this query:
SELECT * FROM users_actions WHERE user_id IN (1,2,3,4,5)
ORDER BY created_at
LIMIT 1
which is of course wrong. Is there any possibility to get this without executing a query for each record using Eloquent?
Am I making some obvious mistake I'm not seeing? I'm quite new to using Eloquent and sometimes relationship troubles me.
Edit:
A part from the representational purpose, I also need this feature for searching inside a relation, say for example I want to search users where LAST ACTION = 'something'
I tried using
$actions->whereHas('action', function($query) {
$query->where('id_action', 1);
});
but this gives me ALL the users which had had an action = 1, and since it's a log everyone passed that step.
Edit 2:
Thanks to #berkayk looks like I solved the first part of my problem, but still I can't search within the relation.
Actions::whereHas('latestAction', function($query) {
$query->where('id_action', 1);
});
still doesn't perform the right query, it generates something like:
select * from `users` where
(select count(*)
from `users_action`
where `users_action`.`user_id` = `users`.`id`
and `id_action` in ('1')
) >= 1
order by `created_at` desc
I need to get the record where the latest action is 1
I think the solution you are asking for is explained here http://softonsofa.com/tweaking-eloquent-relations-how-to-get-latest-related-model/
Define this relation in User model,
public function latestAction()
{
return $this->hasOne('Action')->latest();
}
And get the results with
User::with('latestAction')->get();
I created a package for this: https://github.com/staudenmeir/eloquent-eager-limit
Use the HasEagerLimit trait in both the parent and the related model.
class User extends Model {
use \Staudenmeir\EloquentEagerLimit\HasEagerLimit;
}
class Action extends Model {
use \Staudenmeir\EloquentEagerLimit\HasEagerLimit;
}
Then simply chain ->limit(1) call in your eager-load query (which seems you already do), and you will get the latest action per user.
My solution linked by #berbayk is cool if you want to easily get latest hasMany related model.
However, it couldn't solve the other part of what you're asking for, since querying this relation with where clause would result in pretty much the same what you already experienced - all rows would be returned, only latest wouldn't be latest in fact (but latest matching the where constraint).
So here you go:
the easy way - get all and filter collection:
User::has('actions')->with('latestAction')->get()->filter(function ($user) {
return $user->latestAction->id_action == 1;
});
or the hard way - do it in sql (assuming MySQL):
User::whereHas('actions', function ($q) {
// where id = (..subquery..)
$q->where('id', function ($q) {
$q->from('actions as sub')
->selectRaw('max(id)')
->whereRaw('actions.user_id = sub.user_id');
})->where('id_action', 1);
})->with('latestAction')->get();
Choose one of these solutions by comparing performance - the first will return all rows and filter possibly big collection.
The latter will run subquery (whereHas) with nested subquery (where('id', function () {..}), so both ways might be potentially slow on big table.
Let change a bit the #berkayk's code.
Define this relation in Users model,
public function latestAction()
{
return $this->hasOne('Action')->latest();
}
And
Users::with(['latestAction' => function ($query) {
$query->where('id_action', 1);
}])->get();
To load latest related data for each user you could get it using self join approach on actions table something like
select u.*, a.*
from users u
join actions a on u.id = a.user_id
left join actions a1 on a.user_id = a1.user_id
and a.created_at < a1.created_at
where a1.user_id is null
a.id_action = 1 // id_action filter on related latest record
To do it via query builder way you can write it as
DB::table('users as u')
->select('u.*', 'a.*')
->join('actions as a', 'u.id', '=', 'a.user_id')
->leftJoin('actions as a1', function ($join) {
$join->on('a.user_id', '=', 'a1.user_id')
->whereRaw(DB::raw('a.created_at < a1.created_at'));
})
->whereNull('a1.user_id')
->where('aid_action', 1) // id_action filter on related latest record
->get();
To eager to the latest relation for a user you can define it as a hasOne relation on your model like
namespace App\Models;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Support\Facades\DB;
class User extends Model
{
public function latest_action()
{
return $this->hasOne(\App\Models\Action::class, 'user_id')
->leftJoin('actions as a1', function ($join) {
$join->on('actions.user_id', '=', 'a1.user_id')
->whereRaw(DB::raw('actions.created_at < a1.created_at'));
})->whereNull('a1.user_id')
->select('actions.*');
}
}
There is no need for dependent sub query just apply regular filter inside whereHas
User::with('latest_action')
->whereHas('latest_action', function ($query) {
$query->where('id_action', 1);
})
->get();
Migrating Raw SQL to Eloquent
Laravel Eloquent select all rows with max created_at
Laravel - Get the last entry of each UID type
Laravel Eloquent group by most recent record
Laravel Uses take() function not Limit
Try the below Code i hope it's working fine for u
Users::with(['action' => function ($query) {
$query->orderBy('created_at', 'desc')->take(1);
}])->get();
or simply add a take method to your relationship like below
return $this->hasMany('Action', 'user_id')->orderBy('created_at', 'desc')->take(1);