Get all max values from array of objects in php - php

Question

I have this array of objects i'm getting from query in mysql, i need th
[
{
"id": "11",
"from_userid": "1996",
"contest_id": "29",
"to_userid": "8",
"vote_date": "2020-10-06 01:40:04",
"count_votes": "1"
},
{
"id": "1",
"from_userid": "82",
"contest_id": "29",
"to_userid": "94",
"vote_date": "2020-09-03 07:06:36",
"count_votes": "1"
},
{
"id": "2",
"from_userid": "82",
"contest_id": "29",
"to_userid": "98",
"vote_date": "2020-09-03 07:06:36",
"count_votes": "0"
}
]
I need the object which has highest 'count_votes ' for eg- id-11 and 1 have similar count votes. So the function should return those 2 objects.
The function i am using returns only one object. I need both of the objects whichever maybe but the highest(count_votes) objects.
Expected Output-
[
{
"id": "11",
"from_userid": "1996",
"contest_id": "29",
"to_userid": "8",
"vote_date": "2020-10-06 01:40:04",
"count_votes": "1"
},
{
"id": "1",
"from_userid": "82",
"contest_id": "29",
"to_userid": "94",
"vote_date": "2020-09-03 07:06:36",
"count_votes": "1"
}
]
Function used-
function max_attribute_in_array($array, $prop) {
return max(array_map(function($o) use($prop) {
return $o;
},
$array));
}
And tried this also-
function get_highest($arr) {
$max = $arr[0]; // set the highest object to the first one in the array
foreach($arr as $obj) { // loop through every object in the array
$num = $obj['count_votes']; // get the number from the current object
if($num > $max['count_votes']) { // If the number of the current object is greater than the maxs number:
$max = $obj; // set the max to the current object
}
}
return $max; // Loop is complete, so we have found our max and can return the max object
}

Answer 1

You can use array_column to extract all the count_votes values into an array, which you can then take the max of:
$max = max(array_column($arr, 'count_votes'));
You can then array_filter your array based on the count_votes value being equal to $max:
$out = array_filter($arr, function ($o) use ($max) {
return $o['count_votes'] == $max;
});
Output:
Array
(
[0] => Array
(
[id] => 11
[from_userid] => 1996
[contest_id] => 29
[to_userid] => 8
[vote_date] => 2020-10-06 01:40:04
[count_votes] => 1
)
[1] => Array
(
[id] => 1
[from_userid] => 82
[contest_id] => 29
[to_userid] => 94
[vote_date] => 2020-09-03 07:06:36
[count_votes] => 1
)
)
Demo on 3v4l.org

Answer 2

NOTE max works with single level arrays, so all your objects are converted to int's internally.
As #Nick has pointed out your get_highest can be done via PHP functions:
function get_highest($array, $prop) {
return max(array_column($array, $prop));
}
So all you have to do is filter your array by this get_highest:
$max = get_highest($myArray, 'count_votes');
$maxes = array_filter($myArray, fn($obj) => $obj['count_votes'] === $max);

Answer 3

function get_heighest($arr){
$newArray = array();
$voteCount = 0;
foreach($arr as $obj){
if($obj['count_votes'] >= $voteCount){
array_push($newArray, $obj)
$voteCount = $obj['count_votes'];
}else{
$i = 0;
foreach($newArray as $object){
if($object['count_votes'] < $voteCount){
unset($newArray[$i]);
}
$i++;
}
}
}
return $newArray;
}