Creating dynamic tables in HTML using MySQL and PHP - php

I've seen many posts about how to build a table in HTML with PHP and MysSQL, but I often change the headers of MySQL columns after creating a table.
Is there any way for PHP to update the code automatically so that I can just put in the table name and it prints the table without me having to put in all the <th> tags?
<?php
$table = "user";
$database = "database";
$conn = mysqli_connect("localhost", "username", "password", "database", "3306");
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM $table";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
echo "<tr><td>" . $row["id"] . "</td><td>" . $row["first_name"] . "</td><td>" . $row["last_name"] . "</td><td>" . $row["birthday"] . "</td></tr>";
}
echo "</table>";
} else {
echo "0 result";
}
$conn->close();

If you want to display the full contents of the database table as an HTML table, I suggest you make a function that will do all of this dynamically for you. This function should check that the table exists, fetch all the data, and fetch output HTML table with headers.
MySQLi solution
Here is my suggestion using MySQLi. First of all, you must make sure that the table actually exists. Then you can fetch all the data from the table. The object returned by mysqli::query() will have all metadata information about column names which you can use to display the header row. You can use fetch_fields() to iterate over each column metadata. The data can be fetched using fetch_all() method.
<?php
// create global connection using mysqli
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = mysqli_connect("localhost", "username", "password", "database", "3306");
$mysqli->set_charset('utf8mb4'); // always set the charset
function outputMySQLToHTMLTable(mysqli $mysqli, string $table)
{
// Make sure that the table exists in the current database!
$tableNames = array_column($mysqli->query('SHOW TABLES')->fetch_all(), 0);
if (!in_array($table, $tableNames, true)) {
throw new UnexpectedValueException('Unknown table name provided!');
}
$res = $mysqli->query('SELECT * FROM '.$table);
$data = $res->fetch_all(MYSQLI_ASSOC);
echo '<table>';
// Display table header
echo '<thead>';
echo '<tr>';
foreach ($res->fetch_fields() as $column) {
echo '<th>'.htmlspecialchars($column->name).'</th>';
}
echo '</tr>';
echo '</thead>';
// If there is data then display each row
if ($data) {
foreach ($data as $row) {
echo '<tr>';
foreach ($row as $cell) {
echo '<td>'.htmlspecialchars($cell).'</td>';
}
echo '</tr>';
}
} else {
echo '<tr><td colspan="'.$res->field_count.'">No records in the table!</td></tr>';
}
echo '</table>';
}
outputMySQLToHTMLTable($mysqli, 'user');
PDO Solution
Using PDO is very similar but you have to pay attention to the differences in the APIs.
To get the table names, you can use fetchAll(PDO::FETCH_COLUMN) instead of array_column(). To get the column metadata, you need to use getColumnMeta() function.
<?php
$pdo = new PDO("mysql:host=localhost;dbname=test;charset=utf8mb4", 'username', 'password', [
\PDO::ATTR_ERRMODE => \PDO::ERRMODE_EXCEPTION,
\PDO::ATTR_EMULATE_PREPARES => false
]);
function outputMySQLToHTMLTable(pdo $pdo, string $table)
{
// Make sure that the table exists in the current database!
$tableNames = $pdo->query('SHOW TABLES')->fetchAll(PDO::FETCH_COLUMN);
if (!in_array($table, $tableNames, true)) {
throw new UnexpectedValueException('Unknown table name provided!');
}
$stmt = $pdo->query('SELECT * FROM '.$table);
$data = $stmt->fetchAll(PDO::FETCH_ASSOC);
$columnCount = $stmt->columnCount();
echo '<table>';
// Display table header
echo '<thead>';
echo '<tr>';
for ($i = 0; $i < $columnCount; $i++) {
echo '<th>'.htmlspecialchars($stmt->getColumnMeta($i)['name']).'</th>';
}
echo '</tr>';
echo '</thead>';
// If there is data then display each row
if ($data) {
foreach ($data as $row) {
echo '<tr>';
foreach ($row as $cell) {
echo '<td>'.htmlspecialchars($cell).'</td>';
}
echo '</tr>';
}
} else {
echo '<tr><td colspan="'.$columnCount.'">No records in the table!</td></tr>';
}
echo '</table>';
}
outputMySQLToHTMLTable($pdo, 'user');
P.S. The table existence check can be optimized with the following code instead:
$tableNames = $pdo->prepare('SELECT COUNT(1) FROM information_schema.TABLES WHERE TABLE_SCHEMA = SCHEMA() AND TABLE_NAME=?');
$tableNames->execute([$table]);
if (!$tableNames->fetchColumn()) {
throw new UnexpectedValueException('Unknown table name provided!');
}

I just read your question, and coded to meet your needs, but I used PDO and not MYSQLI, maybe it is better for you to understand the code, because with PDO everything is simpler. And the way I did it, you don't need to put all the tags, PHP will update automatically, and know that the file must end with the extension .php!
<?php
$conn = new PDO("mysql:host=localhost;dbname=YOUR_DATABASE_HERE", "USERNAME", "PASSWORD");
if(!$conn){
echo "Could not connect!";
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
<style>
table, th, td {
border: 1px solid black;
}
</style>
</head>
<body>
<table style="width:100%;">
<thead>
<tr>
<th>ID</th>
<th>FirstName</th>
<th>LastName</th>
<th>Birthday</th>
</tr>
</thead>
<tbody>
<?php
$sql = "SELECT * FROM user";
$result = $conn->prepare($sql);
$result->execute();
if($result->rowCount() > 0):
$rows = $result->fetchAll();
foreach($rows as $row):
?>
<tr>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['first_name']; ?></td>
<td><?php echo $row['last_name']; ?></td>
<td><?php echo $row['birthday']; ?></td>
</tr>
</tbody>
<?php
endforeach;
endif;
?>
</table>
</body>
</html>

Related

get all values of columns in sql php [duplicate]

I want to retrieve the values from a database table and show them in a html table in a page.
I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading.
The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number.
How can I get it to show all the values from the db in a html table like this:
<table border="1">
<tr>
<th>Submission ID</th>
<th>Form ID</th>
<th>IP</th>
<th>Name</th>
<th>E-mail</th>
<th>Message</th>
</tr>
<tr>
<td>123456789</td>
<td>12345</td>
<td>123.555.789</td>
<td>John Johnny</td>
<td>johnny#example.com</td>
<td>This is the message John sent you</td>
</tr>
</table>
And then all the other values below 'john'.
Example taken from W3Schools: PHP Select Data from MySQL
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
It's a good place to learn from!
Try this: (Completely Dynamic...)
<?php
$host = "localhost";
$user = "username_here";
$pass = "password_here";
$db_name = "database_name_here";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$connection = mysqli_connect($host, $user, $pass, $db_name);
//get results from database
$result = mysqli_query($connection, "SELECT * FROM products");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
$all_property[] = $property->name; //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
Here is an easy way to fetch data from a MySQL database using PDO.
define("DB_HOST", "localhost"); // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");
$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8mb4", DB_USER, DB_PASS);
$print = ""; // assign an empty string
$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);
$print .= '<table border="1px">';
$print .= '<tr><th>First name</th>';
$print .= '<th>Last name</th></tr>';
while ($names = $stmt->fetch()) { // loop and display data
$print .= '<tr>';
$print .= "<td>{$names->firstname}</td>";
$print .= "<td>{$names->lastname}</td>";
$print .= '</tr>';
}
$print .= "</table>";
echo $print;
Learn more about PHP and the MySQLi Library at PHP.net.
First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjusting them to fit your environment, then creating a new connection object with new mysqli() and initializing it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:
<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $database);
echo "Connected successfully<br>";
?>
Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().
<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
echo "<tr>";
for($i = 0; $i < $queryResult->field_count; $i++){
echo "<td>$queryRow[$i]</td>";
}
echo "</tr>";
}
echo "</table>";
$conn->close();
?>
First, connect to the database:
$conn=mysql_connect("hostname","username","password");
mysql_select_db("databasename",$conn);
You can use this to display a single record:
For example, if the URL was /index.php?sequence=123, the code below would select from the table, where the sequence = 123.
<?php
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
$result=mysql_fetch_array($rs);
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>
<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>
</table>';
?>
Or, if you want to list all values that match the criteria in a table:
<?php
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>';
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>';
}
echo '</table>';
?>
Surely a better solution would by dynamic so that it would work for any query without having to know the column names?
If so, try this (obviously the query should match your database):
// You'll need to put your db connection details in here.
$conn = new mysqli($server_hostname, $server_username, $server_password, $server_database);
// Run the query.
$result = $conn->query("SELECT * FROM table LIMIT 10");
// Get the result in to a more usable format.
$query = array();
while($query[] = mysqli_fetch_assoc($result));
array_pop($query);
// Output a dynamic table of the results with column headings.
echo '<table border="1">';
echo '<tr>';
foreach($query[0] as $key => $value) {
echo '<td>';
echo $key;
echo '</td>';
}
echo '</tr>';
foreach($query as $row) {
echo '<tr>';
foreach($row as $column) {
echo '<td>';
echo $column;
echo '</td>';
}
echo '</tr>';
}
echo '</table>';
Taken from here: https://www.antropy.co.uk/blog/handy-php-snippets/
mysql_connect("localhost","root","");
mysql_select_db("database");
$query=mysql_query("select * from studenti");
$x=#mysql_num_rows($query);
echo "<a href='file.html'>back</a>";
echo "<table>";
$y=mysql_num_fields($query);
echo "<tr>";
for($i=0 ,$i<$y,$i++)
{
$values=mysql_field_name($query,$i);
echo "<th>$values</th>";
}
echo "</tr>";
while(list($p ,$n $your_table_list)=mysql_fetch_row($query))
{
print("<tr>\n".
"<td>$p</td>".
"</tr>/n");
}
?>
<?php
$mysql_hostname = "localhost";
$mysql_user = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database
$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()
echo '<table border=1px>'; // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers
while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}
echo '</table>'; //closing table tag
?>
it would print the table like this
just read line by line so that you can understand it easily..
OOP Style :
At first connection with database.
<?php
class database
{
public $host = "localhost";
public $user = "root";
public $pass = "";
public $db = "db";
public $link;
public function __construct()
{
$this->connect();
}
private function connect()
{
$this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
return $this->link;
}
public function select($query)
{
$result = $this->link->query($query) or die($this->link->error.__LINE__);
if($result->num_rows>0)
{
return $result;
}
else
{
return false;
}
}
?>
Then :
<?php
$db = new database();
$query = "select * from data";
$result = $db->select($query);
echo "<table>";
echo "<tr>";
echo "<th>Name </th>";
echo "<th>Roll </th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $row[name]</td>";
echo "<td> $row[roll]</td>";
echo "</tr>";
}
echo "</table>";
?>

PHP MYSQLI fetch Errors

At school my teacher told me a lot of thing about coding in PHP using a POSTGRES DATABASE.
But when I started to use MYSQLI Server i couldn't do a lot of thing.
First of all the functions.
My teacher told me to do this type of function
$rows = getBuildings();
if (count($elenco) == 0) {
print "<hr> No buildings here </hr>";
} else {
?>
<thead>
<tr>
<th>address</th>
<th>town</th>
<th>Manager</th>
</tr>
</thead>
<tbody>
<?php
foreach ($elenco as $riga) {
?>
<tr>
<td> <?= $row->address ?></td>
<td> <?= $row->town ?></td>
<td> <?= $row->name ?> <?= $riga->surname ?> </td>
</tr>
<?php
}
?>
</tbody>
</table>
</tbody>
</table>
<?php
}
?>
</body>
</html>
<?php
function getBuldings() {
global $db;
$sql = "select * from buildings, boss
where boss.codBo=buildings.codBu";
$rows = array();
if (!DB::isError($tab = $db->query($sql))) {
while ($row = $tab->fetchRow(DB_FETCHMODE_OBJECT)) {
$rows[] = $row;
}
} else {
die("ErrorSQL:" . $tab->getMessage());
}
return $rows;
}
?>
But to get it working in MYSQL i had to do a lot of changes. In fact there was an error in !BD::isError. I had to change the connection.php in from this one
<?php
Session_Start();
require_once("DB.php");
$db = DB::connect("pgsql:etc....");
if (DB::isError($db)) {
die("Error: " . $db->getMessage());
}
?>
to this one
<?php
$servername = "localhost";
$username = "test";
$password = "";
$dbname = "test";
// Create connection
$db = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($db->connect_error) {
die("Connection failed: " . $db->connect_error);
}
$a = mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
echo "Connected successfully " . $a . " ";
?>
In order to show the result of the query my code had become this:
<body>
<?php
$rows = getBoss();
if (count($rows) == 0) {
print "<h2>No Boss here</h2>";
} else {
foreach ($rows as $row) {
print "<p>" . $row['name'] . "</p>";
print "<p>" . $row['surname'] . "</p>";
}
}
?>
<?php
function getBoss() {
global $db;
$sql = "select *
from test_boss
order by name, surname";
$rows = array();
if ($tab = $db->query($sql)) {
while ($row = $tab->fetch_array()) {
$rows[] = $row;
}
return $elenco;
} else {
die("Errore sql: " . $tab->getMessage() . ":" . $sql);
}
}
?>
</body>
</html>
That in facts works pretty well, but I had to change FETCH_ROW to FETCH_ARRAY.
I could not use anymore the method of posting the data from the $rows value.
<?= $row->name ?>
Because there was an error
Notice: Trying to get property of non-object
but I had to use
print "<p>".$row['name']."</p>";
What can I do in order to use the method FETCH_ROW corretly?
You can type cast the array to an object by tweaking the code slight.
if you want to retrieve an object in form of $row->name then your code will be.
while ($row= $tab->fetch_array()) {
$rows[] = (object)$row;
}
OR
while ($row= $tab->fetch_object()) {
$rows[] = $row;
}

Show values from a MySQL database table inside a HTML table on a webpage

I want to retrieve the values from a database table and show them in a html table in a page.
I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading.
The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number.
How can I get it to show all the values from the db in a html table like this:
<table border="1">
<tr>
<th>Submission ID</th>
<th>Form ID</th>
<th>IP</th>
<th>Name</th>
<th>E-mail</th>
<th>Message</th>
</tr>
<tr>
<td>123456789</td>
<td>12345</td>
<td>123.555.789</td>
<td>John Johnny</td>
<td>johnny#example.com</td>
<td>This is the message John sent you</td>
</tr>
</table>
And then all the other values below 'john'.
Example taken from W3Schools: PHP Select Data from MySQL
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
It's a good place to learn from!
Try this: (Completely Dynamic...)
<?php
$host = "localhost";
$user = "username_here";
$pass = "password_here";
$db_name = "database_name_here";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$connection = mysqli_connect($host, $user, $pass, $db_name);
//get results from database
$result = mysqli_query($connection, "SELECT * FROM products");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
$all_property[] = $property->name; //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
Here is an easy way to fetch data from a MySQL database using PDO.
define("DB_HOST", "localhost"); // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");
$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8mb4", DB_USER, DB_PASS);
$print = ""; // assign an empty string
$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);
$print .= '<table border="1px">';
$print .= '<tr><th>First name</th>';
$print .= '<th>Last name</th></tr>';
while ($names = $stmt->fetch()) { // loop and display data
$print .= '<tr>';
$print .= "<td>{$names->firstname}</td>";
$print .= "<td>{$names->lastname}</td>";
$print .= '</tr>';
}
$print .= "</table>";
echo $print;
Learn more about PHP and the MySQLi Library at PHP.net.
First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjusting them to fit your environment, then creating a new connection object with new mysqli() and initializing it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:
<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $database);
echo "Connected successfully<br>";
?>
Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().
<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
echo "<tr>";
for($i = 0; $i < $queryResult->field_count; $i++){
echo "<td>$queryRow[$i]</td>";
}
echo "</tr>";
}
echo "</table>";
$conn->close();
?>
First, connect to the database:
$conn=mysql_connect("hostname","username","password");
mysql_select_db("databasename",$conn);
You can use this to display a single record:
For example, if the URL was /index.php?sequence=123, the code below would select from the table, where the sequence = 123.
<?php
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
$result=mysql_fetch_array($rs);
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>
<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>
</table>';
?>
Or, if you want to list all values that match the criteria in a table:
<?php
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>';
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>';
}
echo '</table>';
?>
Surely a better solution would by dynamic so that it would work for any query without having to know the column names?
If so, try this (obviously the query should match your database):
// You'll need to put your db connection details in here.
$conn = new mysqli($server_hostname, $server_username, $server_password, $server_database);
// Run the query.
$result = $conn->query("SELECT * FROM table LIMIT 10");
// Get the result in to a more usable format.
$query = array();
while($query[] = mysqli_fetch_assoc($result));
array_pop($query);
// Output a dynamic table of the results with column headings.
echo '<table border="1">';
echo '<tr>';
foreach($query[0] as $key => $value) {
echo '<td>';
echo $key;
echo '</td>';
}
echo '</tr>';
foreach($query as $row) {
echo '<tr>';
foreach($row as $column) {
echo '<td>';
echo $column;
echo '</td>';
}
echo '</tr>';
}
echo '</table>';
Taken from here: https://www.antropy.co.uk/blog/handy-php-snippets/
mysql_connect("localhost","root","");
mysql_select_db("database");
$query=mysql_query("select * from studenti");
$x=#mysql_num_rows($query);
echo "<a href='file.html'>back</a>";
echo "<table>";
$y=mysql_num_fields($query);
echo "<tr>";
for($i=0 ,$i<$y,$i++)
{
$values=mysql_field_name($query,$i);
echo "<th>$values</th>";
}
echo "</tr>";
while(list($p ,$n $your_table_list)=mysql_fetch_row($query))
{
print("<tr>\n".
"<td>$p</td>".
"</tr>/n");
}
?>
<?php
$mysql_hostname = "localhost";
$mysql_user = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database
$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()
echo '<table border=1px>'; // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers
while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}
echo '</table>'; //closing table tag
?>
it would print the table like this
just read line by line so that you can understand it easily..
OOP Style :
At first connection with database.
<?php
class database
{
public $host = "localhost";
public $user = "root";
public $pass = "";
public $db = "db";
public $link;
public function __construct()
{
$this->connect();
}
private function connect()
{
$this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
return $this->link;
}
public function select($query)
{
$result = $this->link->query($query) or die($this->link->error.__LINE__);
if($result->num_rows>0)
{
return $result;
}
else
{
return false;
}
}
?>
Then :
<?php
$db = new database();
$query = "select * from data";
$result = $db->select($query);
echo "<table>";
echo "<tr>";
echo "<th>Name </th>";
echo "<th>Roll </th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $row[name]</td>";
echo "<td> $row[roll]</td>";
echo "</tr>";
}
echo "</table>";
?>

Displaying all records in a mysql table

The code below works fine for printing one record from a database table, but what I really want to be able to do is print all the records in the mysql table in a format similar to my code.
I.E.: Field Name as heading for each column in the html table and the entry below the heading. Hope this is making sense to someone ;)
$raw = mysql_query("SELECT * FROM tbl_gas_meters");
$allresults = mysql_fetch_array($raw);
$field = mysql_query("SELECT * FROM tbl_gas_meters");
$num_fields = mysql_num_fields($raw);
$num_rows = mysql_num_rows($raw);
$i = 1;
print "<table border=1>\n";
while ($i < $num_fields)
{
echo "<tr>";
echo "<b><td>" . mysql_field_name($field, $i) . "</td></b>";
//echo ": ";
echo '<td><font color ="red">' . $allresults[$i] . '</font></td>';
$i++;
echo "</tr>";
//echo "<br>";
}
print "</table>";
Just as an additional piece of information you should probably be using PDO. It has more features and is helpful in learning how to prepare SQL statements. It will also serve you much better if you ever write more complicated code.
http://www.php.net/manual/en/intro.pdo.php
This example uses objects rather then arrays. Doesn't necessarily matter, but it uses less characters so I like it. Difference do present themselves when you get deeper into objects, but not in this example.
//connection information
$user = "your_mysql_user";
$pass = "your_mysql_user_pass";
$dbh = new PDO('mysql:host=your_hostname;dbname=your_db;charset=UTF-8', $user, $pass);
//prepare statement to query table
$sth = $dbh->prepare("SELECT name, colour FROM fruit");
$sth->execute();
//loop over all table rows and fetch them as an object
while($result = $sth->fetch(PDO::FETCH_OBJ))
{
//print out the fruits name in this case.
print $result->name;
print("\n");
print $result->colour;
print("\n");
}
You probably also want to look into prepared statements. This helps against injection. Injection is bad for security reasons. Here is the page for that.
http://www.php.net/manual/en/pdostatement.bindparam.php
You probably should look into sanitizing your user input as well. Just a heads up and unrelated to your current situation.
Also to get all the field names with PDO try this
$q = $dbh->prepare("DESCRIBE tablename");
$q->execute();
$table_fields = $q->fetchAll(PDO::FETCH_COLUMN);
Once you have all the table fields it would be pretty easy using <div> or even a <table> to arrange them as you like using a <th>
Happy learning PHP. It is fun.
Thanks guys, got it.
$table = 'tbl_gas_meters';
$result = MYSQL_QUERY("SELECT * FROM {$table}");
$fields_num = MYSQL_NUM_FIELDS($result);
ECHO "<h1>Table: {$table}</h1>";
ECHO "<table border='1'><tr>";
// printing table headers
FOR($i=0; $i<$fields_num; $i++)
{
$field = MYSQL_FETCH_FIELD($result);
ECHO "<td>{$field->name}</td>";
}
ECHO "</tr>\n";
// printing table rows
WHILE($row = MYSQL_FETCH_ROW($result))
{
ECHO "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
FOREACH($row AS $cell)
ECHO "<td>$cell</td>";
ECHO "</tr>\n";
}
while ( $row = mysql_fetch_array($field) ) {
echo $row['fieldname'];
//stuff
}
Try this :
$raw = mysql_query("SELECT * FROM tbl_gas_meters");
$allresults = mysql_fetch_array($raw);
$field = mysql_query("SELECT * FROM tbl_gas_meters");
while($row = mysql_fetch_assoc($field)){
echo $row['your field name here'];
}
Please note that, mysql_* functions are deprecated in new php version , so use mysqli or PDO instead.
Thanks! I adapted some of these answers to draw a table from all records from any table, without having to specify the field names. Just paste this into a .php file and change the connection info:
<?php
// Authentication detail for connection
$servername = "localhost";
$username = "xxxxxxxxxx";
$password = "xxxxxxxxxx";
$dbname = "xxxxxxxxxx";
$tablename = "xxxxxxxxxx";
$orderby = "1 DESC LIMIT 500"; // column # to sort & max # of records to display
// Create & check connection
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error); // quit
}
// Run query & verify success
$sql = "SELECT * FROM {$tablename} ORDER BY {$orderby}";
if ($result = $conn->query($sql)) {
$conn->close(); // Close table
$fields_num = $result->field_count;
$count_rows = $result->num_rows;
if ($count_rows == 0) {
die ("No data found in table: [" . $tablename . "]" ); //quit
}
} else {
$conn->close(); // Close table
die ("Error running SQL:<br>" . $sql ); //quit
}
// Start drawing table
echo "<!DOCTYPE html><html><head><title>{$tablename}</title>";
echo "<style> table, th, td { border: 1px solid black; border-collapse: collapse; }</style></head>";
echo "<body><span style='font-size:18px'>Table: <strong>{$tablename}</strong></span><br>";
echo "<span style='font-size:10px'>({$count_rows} records, {$fields_num} fields)</span><br>";
echo "<br><span style='font-size:10px'><table><tr>";
// Print table Field Names
while ($finfo = $result->fetch_field()) {
echo "<td><center><strong>{$finfo->name}</strong></center></td>";
}
echo "</tr>"; // Finished Field Names
/* Loop through records in object array */
while ($row = $result->fetch_row()) {
echo "<tr>"; // start data row
for( $i = 0; $i<$fields_num; $i++ ) {
echo "<td>{$row[$i]}</td>";
}
echo "</tr>"; // end data row
}
echo "</table>"; // End table
$result->close(); // Free result set
?>

Displaying all tables in a database

How do I display out all the information in a database (All tables and records) using PHP? I read displaying tables as HTML table but how do I do it for all the tables?
I tried the example here:
http://davidwalsh.name/html-mysql-php
But it shows the table names, how do I also display all the values?
Okay got it .. try this
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "username", "password", "DB");
$result = $mysqli->query("SHOW TABLES");
while ($row = $result->fetch_row()) {
$table = $row[0];
echo '<h3>', $table, '</h3>';
$result1 = $mysqli->query("SELECT * FROM `$table`");
echo '<table cellpadding="0" cellspacing="0" class="db-table">';
$column = $mysqli->query("SHOW COLUMNS FROM `$table`");
echo '<tr>';
while ($row3 = $column->fetch_row()) {
echo '<th>' . $row3[0] . '</th>';
}
echo '</tr>';
while ($row2 = $result1->fetch_row()) {
echo '<tr>';
foreach ($row2 as $key => $value) {
echo '<td>', $value, '</td>';
}
echo '</tr>';
}
echo '</table><br />';
}
$mysqli->close();
you can use the recursive function to display the tree Structure of your database.
Here is the a sample code from http://webcodingeasy.com/PHP/Simple-recursive-function-to-print-out-database-tree-structure
<?php
function print_menu($id = 0)
{
// get all records from database whose parent is $id
$result = $query->select_result("*", "table", "where parent = '".$id."'");
//check if there are any results
if($result != 0)
{
echo "<ul> n";
while($row = $query->fetch($result))
{
//print result and call function to check if it has children
echo "<li>".$row['name']."</li> n";
print_menu($row['ID']);
}
echo "</ul> n";
}
}
print_menu();
?>
If you want to pull all tables with the values in mysql, you can use the following code:
<?php
mysql_connect ("localhost", "DB_USER", "DB_PASSWORD"); //your mysql connection
mysql_select_db('DB_NAME') or die( "Unable to select database"); //your db name
$tables = mysql_query("SELECT table_name FROM information_schema.tables WHERE table_schema='DB_NAME'"); //pull tables from theh databsase
while ($table= mysql_fetch_row($tables)) {
$rsFields = mysql_query("SHOW COLUMNS FROM ".$table[0]);
while ($field = mysql_fetch_assoc($rsFields)) {
echo $table[0].".".$field["Field"].", "; //prints out all columns
}
echo $table[0];
$query = "SELECT * FROM ".$table[0]; //prints out tables name
$result = mysql_query($query);
PullValues($result); //call function to get all values
}
//function to pull all values from tables
function PullValues($result)
{
if($result == 0)
{
echo "<b>Error ".mysql_errno().": ".mysql_error()."</b>";
}
elseif (#mysql_num_rows($result) == 0)
{
echo("<b>Query completed. No results returned.</b><br>");
}
else
{
echo "<table border='1'>
<thead>
<tr><th>[Num]</th>";
for($i = 0;$i < mysql_num_fields($result);$i++)
{
echo "<th>" . $i . " - " . mysql_field_name($result, $i) . "</th>";
}
echo " </tr>
</thead>
<tbody>";
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
echo "<tr><td>[$i]</td>";
$row = mysql_fetch_row($result);
for($j = 0;$j < mysql_num_fields($result);$j++)
{
echo("<td>" . $row[$j] . "</td>");
}
echo "</tr>";
}
echo "</tbody>
</table>";
} //end else
}
?>
I am using this and works fine in mysql, for mysqli you need to tweak it a very little.

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