How to insert new rows into database from a submitted json string? - php

Question

I am not able decode and insert the array data in PHP. I tried to functions like decode and foreach, but nothing work.
The $_POST['area'] data:
[area] => [{"text":"DATA1"},{"text":"DATA2"},*,{"text":"DATA3"}]
I am new to PHP, how can I insert these rows of data into my database with pdo's prepared statements?
$area = $_POST['area'];
foreach ($area as $data) {
echo json_decode($data);
}
echo json_decode($area);
However it does not echo.
Ultimately, I want to use the data in this:
$stmt = $con->prepare(INSERT INTO `table` (`areas`) VALUES(:data));
$stmt->execute(array($data));

Answer 1

First things first, you have an invalid json string because of the *,.
$_POST['area'] = '[{"text":"DATA1"},{"text":"DATA2"},*,{"text":"DATA3"}]';
// uh oh, not valid json -----^^
So I'll assume that this is a posting error and run with the following input data:
$_POST['area'] = '[{"text":"DATA1"},{"text":"DATA2"},{"text":"DATA3"}]';
This means that before you can iterate $_POST['area'], you must json_decode() it. (Demo)
An unchanging prepared statement should be declared before entering the loop -- it is designed to be used over and over.
The binding of values to placeholders and the execution of the query is to be done inside the loop.
$stmt = $con->prepare(INSERT INTO `table` (`areas`) VALUES(?));
foreach (json_decode($_POST['area']) as $obj) {
$stmt->execute([$obj->text]);
}

Answer 2

Your json format is incorrect. To do json_decode(); you need correct json format
$post['area'] = [{"text":"DATA1"},{"text":"DATA2"},*,{"text":"DATA3"}];
changed it to
$post['area'] = [{"text":"DATA1"},{"text":"DATA2"},{"text":"DATA3"}];
then do
$ex = json_decode($data, true);

Answer 3

Use This:
$area = json_decode($_POST['area'],true);
You can't echo an array in PHP. You have to use the var_dump() function to do that.
Have a good day ;).