Table will not display - php

Question

I am having no success linking the upper part of the code containing the prepared statements to the table display. After eradicating several syntax errors, all I am getting now is a single row of numbers starting at 0 and running through to 2713 instead of the database results. The code below is exactly as I am using it except that for this purpose I have removed my personal details from the '$con'
<?php
$con= new PDO('mysql:host=;', "",
"");
$con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
if (isset($_POST['submit-keyword'])) {
$keyword = '%'.$keyword. '%';
$stmt = $con->prepare("SELECT * FROM Bath_Wells_NBR WHERE Founder LIKE :keyword ORDER BY DATE");
$stmt->bindParam(':keyword',$keyword,PDO::PARAM_STR);
$stmt->execute();
//use fetchAll to get full array of results, or an empty array
$result=$stmt->fetchAll();
if(count($result)>0) {
print "<table>";
//return only the first row (we only need field names)
$row = $result;
print " <tr>";
foreach ($row as $field => $value){
print " <th>$field</th>";
} // end foreach
print " </tr>";
//second query gets the data
$data = $con->prepare("SELECT * FROM Bath_Wells_NBR WHERE Founder LIKE :keyword ORDER BY DATE");
$data->setFetchMode(PDO::FETCH_ASSOC);
foreach($data as $row){
print " <tr>";
foreach ($row as $name=>$value){
print " <td>$value</td>";
} // end field loop
print " </tr>";
} // end record loop
print "</table>";
}
}
?>
\\

Answer 1

your second query not get bind param properly
See Doc
$data = $con->prepare("SELECT * FROM Bath_Wells_NBR WHERE Founder LIKE :keyword ORDER BY DATE");
$data->bindParam(':keyword', $keyword, PDO::PARAM_STR);
$data->setFetchMode(PDO::FETCH_ASSOC);
$rows = $data->execute();