Displaying array contents in pairs - php

Question

I'm trying to make a website that displays all userprofiles. I want to wrap every two users in a <div>, until there is no left. So say we have 19 arrays consisting of userprofileinfo in $info - the following code will work fine, but will print out the 20th out as an empty div, which I want to prevent. What to do here?
$info = mysqli_fetch_all($result, MYSQLI_ASSOC);
for ($count = 0; $count <= mysqli_num_rows($result) - 1; $count += 2) {
echo <div class="row">
echo "<div>".print_r($info[$count])."</div>";
echo "<div>".print_r($info[$count+1])."</div>";¨
echo </div>
}

Answer 1

I think you might overthinking this. Why not simply use array_chunk()?
$info = mysqli_fetch_all($result, MYSQLI_ASSOC);
foreach (array_chunk($info, 2) as $chunk) {
echo '<div class="row">';
foreach ($chunk as $element) {
echo "<div>".$element['name']."</div>";
}
echo '</div>';
}
The way array_chunk() works is that it will group the array elements into chunks of a given size. You can have a double loop. The inner loop will iterate on each chunk and display both elements.

Answer 2

Just to provide a slightly cleaner version of Yvan1263's answer using OPs updated code (having fixed quotes).
$info = mysqli_fetch_all($result, MYSQLI_ASSOC);
for ($count = 0; $count <= count($info) - 1; $count += 2) {
echo '<div class="row">';
echo "<div>".print_r($info[$count])."</div>";
if (isset($info[$count+1])) {
echo "<div>".print_r($info[$count+1])."</div>";
}
echo </div>
}

Answer 3

You can just do this:
$info = mysqli_fetch_all($result, MYSQLI_ASSOC);
for ($count = 0; $count <= mysqli_num_rows($result); $count += 2) {
if($count+1 >= mysqli_num_rows($result)) {
/* IF MAX IS MORE THAN ENTRIES NUMBER */
echo "<div>".print_r($info[$count])."</div";
}
else {
echo "<div>".print_r($info[$count])."</div";
echo "<div>".print_r($info[$count+1])."</div";
}
}
NB: Use PDO instead of MySQLi.