Getting specific column from sql database using raw query in laravel - php

Question

I have this raw query that extracts data from the database table in Laravel
$username = DB::table('hotspot_users')
->select('userName')
->where('assignedTo', '786')->get();
I get these values: [{"userName":"kim"}]
but I want to extract just the username "kim" itself, not an array. I have tried to do this without success:
$convert1=json_decode($username);
$newusername=$convert1->userName;
but i get an error: Trying to get property 'userName' of non-object
Any idea how I can solve this

Answer 1

Instead of what you're doing, you can just do this:
HotspotUser::where('assignedTo', 786)->pluck('userName');
Now you will have a collection of names; or if you only want the first one:
HotspotUser::where('assignedTo', 786)->first()->user_name;
(I'm not certain if the property will be user_name or userName; you should have simple column names to make things easier.)

Answer 2

You are getting the result of DB as php stdClass object, so you can iterate over it and get every variable that is queried. Something like below code may help you.
In case of using get()
$data = DB::table('hotspot_users')
->where('assignedTo', '786')->select('userName')->get();
foreach ($data as $datum) {
$result[] = $datum->userName;
}
In case of using first()
$data = DB::table('hotspot_users')
->where('assignedTo', '786')->select('userName')->first()->userName;

Answer 3

Hi As you mentioned that is an array [{"userName":"kim"}]
So you have two choices
First , you first insted of get
$username = DB::table('hotspot_users')
->select('userName')
->where('assignedTo', '786')->first();
$newusername=$convert1->userName;
Second , get the first element of array
$username = DB::table('hotspot_users')
->select('userName')
->where('assignedTo', '786')->get();
$username = reset($username);
$convert1=json_decode($username);
$newusername=$convert1['userName'];