I have a php code as shown below in which on the 1st day of every month, I am copying 2nd JSON object array (next_month) content into 1st JSON object array (current_month).
In the 2nd JSON object array (next_month), I want to have next month dates. That will also happen on the 1st day of every month. Currently I am storing nada. Let us suppose that today is 1st day of November.
php code:
$value = json_decode(file_get_contents('../hyt/dates.json'));
if ((date('j') == 1)) {
$month = 11;
$year = date('Y');
$current_month_days = (date('t', strtotime($year . '-' . $month . '-01')));
$next_month_days = (date('t', strtotime($year . '-' . ($month + 1) . '-01')));
$value->current_month = $value->next_month; // Line Y
$value->next_month = array_fill(0, ($next_month_days), nada); // Line Z
}
The current look of JSON (dates.json) is shown below:
{"current_month": ["2020-10-01", "2020-10-02", "2020-10-03", "2020-10-04", "2020-10-05", "2020-10-06", "2020-10-07", "2020-10-08", "2020-10-09", "2020-10-10", "2020-10-10", "2020-10-12", "2020-10-13", "2020-10-14", "2020-10-15", "2020-10-16", "2020-10-17", "2020-10-18", "2020-10-19", "2020-10-20", "2020-10-21", "2020-10-22", "2020-10-23", "2020-10-24", "2020-10-25", "2020-10-26", "2020-10-27", "2020-10-28", "2020-10-29", "2020-10-30","2020-10-31"],
"next_month": ["2020-11-01", "2020-11-02", "2020-11-03", "2020-11-04", "2020-11-05", "2020-11-06", "2020-11-07", "2020-11-08", "2020-11-09", "2020-11-11", "2020-11-11", "2020-11-12", "2020-11-13", "2020-11-14", "2020-11-15", "2020-11-16", "2020-11-17", "2020-11-18", "2020-11-19", "2020-11-20", "2020-11-21", "2020-11-22", "2020-11-23", "2020-11-24", "2020-11-25", "2020-11-26", "2020-11-27", "2020-11-28", "2020-11-29", "2020-11-30"] }
Problem Statement:
I am wondering what changes I should make at Line Z so that in the second JSON object array, I am able to get next month dates. At present, I am storing nada.
The content which I want in the JSON on the 1st day of November month after successful execution of Line Y and Line Z is:
{"current_month": ["2020-11-01", "2020-11-02", "2020-11-03", "2020-11-04", "2020-11-05", "2020-11-06", "2020-11-07", "2020-11-08", "2020-11-09", "2020-11-11", "2020-11-11", "2020-11-12", "2020-11-13", "2020-11-14", "2020-11-15", "2020-11-16", "2020-11-17", "2020-11-18", "2020-11-19", "2020-11-20", "2020-11-21", "2020-11-22", "2020-11-23", "2020-11-24", "2020-11-25", "2020-11-26", "2020-11-27", "2020-11-28", "2020-11-29", "2020-11-30"],
"next_month": ["2020-12-01", "2020-12-02", "2020-12-03", "2020-12-04", "2020-12-05", "2020-12-06", "2020-12-07", "2020-12-08", "2020-12-09", "2020-12-11", "2020-12-11", "2020-12-12", "2020-12-13", "2020-12-14", "2020-12-15", "2020-12-16", "2020-12-17", "2020-12-18", "2020-12-19", "2020-12-20", "2020-12-21", "2020-12-22", "2020-12-23", "2020-12-24", "2020-12-25", "2020-12-26", "2020-12-27", "2020-12-28", "2020-12-29", "2020-12-30", "2020-12-31"] }
This is what I have tried:
This is what I have tried at Line Z but its storing only today's date in JSON object array.
$value->next_month = array_fill(0, ($next_month_days), date("Y-m-d")); // Line Z
I think you should completely recreate your JSON string. It starts on the first day of the current month. The loop always runs as long as the month remains. The whole thing then again for the following month.
$arr = $cur = [];
$date = date_create('first day of this month 00:00');
$startMonth = $month = $date->format('m');
while($startMonth == $month){
$cur[] = $date->format('Y-m-d');
$date->modify('+1 Day');
$month = $date->format('m');
}
$arr["current_month"] = $cur;
$startMonth = $month;
$cur = [];
while($startMonth == $month){
$cur[] = $date->format('Y-m-d');
$date->modify('+1 Day');
$month = $date->format('m');
}
$arr["next_month"] = $cur;
$jsonStr = json_encode($arr);
You are using array_fill, which is used to fill at least part of an array with the same value. I would recommend using a simple for loop:
$next_month_array = [];
$next_month = $month < 12 ? $month + 1 : 1;
$year = date('Y');
for($day_counter = 1; $day_counter <= $next_month_days; $day_counter++) {
$next_month_array[] = "$year-$next_month-$day_counter";
}
$value->next_month = $next_month_array;
Related
I have got a script that repeats activitities.
When the repeat settings are:
repeat "the 2nd tuesday every 2 months, stop at 5 instances" (like google calendar would do).
I can accomplish "the 2nd tuesday every 2 months" with the script below:
<?php
$pubDay = 19;
$pubMonth = 7;
$pubYear = 2017;
$repeatMonths = 2;
$newMonth = $pubMonth;
$newYear = $pubYear;
$raisedMonth = $pubMonth + $repeatMonths;
if ( $raisedMonth > 12 ) {
$newMonth = ($raisedMonth) % 12; // off 12 at starts at 1
$newYear = $pubYear + 1;
} else {
$newMonth = $raisedMonth;
}
$occurenceInMonth = ceil($pubDay / 7); // determine the weekday occurence in the month (b.e. the "2nd thursday")
$dates = array();
foreach (getWeekDayDates($pubDow, $newYear, $newMonth) as $weekdaydate) {
$dates[] = $weekdaydate->format("Y-m-d");
}
// we need the x occurence (-1)
$newPubDate = isset($dates[$occurenceInMonth -1]) ? $dates[$occurenceInMonth -1] . " " . $pubHour . ":" . $pubMin : "";
echo $newPubDate;
function getWeekDayDates($weekday, $y, $m) {
return new DatePeriod(
new DateTime("first " . $weekday . " of $y-$m"),
DateInterval::createFromDateString('next ' . $weekday),
new DateTime("next month $y-$m-01")
);
}
?>
This works like a charm.
But now i need to check wether it is the 5th instance, starting at 17-9-2016.
My script is now like this:
// get the end date
$startdate = "2016-09-17";
$repeatMonths = 2;
$endTime = strtotime($startdate . " +" . ($repeatMonths * $reps) . " months");
if ( $endTime >= strtotime($newPubDate) ) {
$doRepeat = true;
}
But this can go wrong!
By example when the repetitons starts (startddate) at saturday 4-7 and it repeats every first sunday.
When the sunday in the last repetition is on the 6th of the month. The script above returns false, but it shouldnt't.
How can i check on a simple way if it is the 5th occurence?
I would create an array which holds DateTime objects of the next 5 "2nd tuesdays of the month":
$startdate = new \DateTime('second tue of february 2017');
$dates = array();
$repetitions = 5;
for ($i=0; $i<$repetitions; $i++) {
$dates[] = clone $date->modify('+1 month');
}
Using this array it should be easy to check, whether the date is reached or not yet.
I am trying to show results of each month.
Im having this for loop:
foreach ($overview as $day) {
$year = date("Y") - 1;
if ($day->user == $info->id) {
$startDate = new DateTime($day->Calendar_startdate);
$endDate = new DateTime($day->Calendar_enddate);
$s = $startDate->format('Y-m-d');
$e = $endDate->format('Y-m-d');
if ($s > $year) {
$workdays = number_of_working_days($s, $e);
$daysleft = $daysleft + $workdays;
} else {
}
}
}
This for loop is also in an if statement which echos the months.
Now I need to let it work for the months January, February etc...
I am able to not show results if in the previous year which works well.
If you want to compare $s with $year just change $year to :
$time = new DateTime('now');
/*** you can use `now` for today
/* or you can change to a fixed date exmp: 2016-01-01
*/
$year = $time->modify('-1 year')->format('Y-m-d');
Than you can compare $s > $year
I fixed by checking each month if it contained for example -01-
DB::table('Calendar')->where('Calendar_startdate', 'like','%' . $monthnumber . '%')->where('user', $info->id)->where('Calendar_type',2)->get();
I have an event having the following properties:
id
name
weekday
So, an event happens every week on that weekday. I wanted to create an array containing all the dates (Format: dd-mm-yyyy), when that event will take place two specific dates.
I'm unable to figure out the appropriate logic/code.
I implemented the following code:
$day = date('d');//returns today's date in 2-digit format.
$year = date('Y');//4-digit format of current year
$month = date('m');//2-digit format of current month
$cal = array();
$ttdayid = $weekday;//5
$tt = 0;
$tt = abs($day-$ttdayid);
$ttday = $date - $tt;
while ($ttday>0) {
if ($ttday<10) {
$ttday = '0' . $ttday;
}
$arr = array(
'id' => $id,
'title' => $name,
'start' => $year . '-' . $month . '-' . $ttday
);
array_push($cal, $arr);
$ttday-= 7;
}
The above code works for the current month only before today. I'm unable to figure out how to extend it to show dates for previous and next months for the whole year. Also, how to included cases for leap years.
Use the DateTime() object:
$current = new DateTime(); // creates a date for "today" by default
$end = new DateTime('yyyy-mm-dd'); // the ending date
$interval = new DateInterval('P7D'); // 1 week
while($current <= $end) {
$cal[] = $current->format('Y-m-d');
$current = $current->add($interval);
}
I have got strange issue with dates of events and I have tried hard to get it fixed but unable to do it.
I am attaching a screenshot of how I want to display the dates on the page :
In the picture the first event Deine Energie in Aktion! is a combination of 5 events with each event having its start date and end date.
The first part of the event is 1 day event which starts on 4th April and ends on 4th April. Similarly the second part is on 7th April, 3rd part on 9th April and 4th part on 20th April
The last part starts on 5th May and ends on 10th May.
The dates are stored in database in this format :
I am showing the dates for last part of event.
Event Start Date : 2013-05-05 00:00:00
Event End Date : 2013-05-10 00:00:00
So I want to display dates in the format shown in the picture.
There are multiple cases:
First is if all the dates are coming within a single month then we display the month name at the end only once.
Second is if months are changed then the month name will be shown after the date when the month is changed.
I am getting events dates in a while loop, so how do I compare the current event date with the coming event date in a loop.
This is the code I have used so far to get the dates from the database..
$nid = $row->nid;
$get_product_id = "SELECT product_id from {uc_product_kits} where nid='$nid'";
$res = db_query($get_product_id);
while ($get_product_id_array_value = db_fetch_array($res)) {
$prductid = $get_product_id_array_value['product_id'];
$start_date = db_query("select event_start,event_end from {event} where nid=%d",$prductid);
$start_date_value = db_fetch_object($start_date);
$end_value = $start_date_value->event_start;
$event_end_date = $start_date_value->event_end;
$TotalStart = date("d M Y", strtotime($end_value));
$TotalEnd = date("d M Y", strtotime($event_end_date));
$onlyMonthStart = date("M", strtotime($end_value));
$onlyMonthEnd = date("M", strtotime($event_end_date));
//$groupMonth = db_query("select event_start,event_end, month from {event} where nid=%d group by ",$prductid);
if($TotalStart == $TotalEnd ){
$startDay = date("d", strtotime($end_value));
$startMonth = date("M", strtotime($end_value));
if(in_array($startMonth,$newMonth)) {
echo $onlstartdate;
}
else {
$onlstartdate = date("d", strtotime($end_value));
echo $onlstartdate;
$tempStorage[] = $startMonth
}
//$newMonth[] = $startMonth;
}
}
Easiest would be to first collect all data from your query into e.g. array.
Only then iterate over the array. Having all data together will allow you to compare two consecutive date ranges to decide level of details you need to print for each.
Commented example:
// collect data from SQL query into structure like this:
$events = array(
array("event_start" => "2013-4-4", "event_end" => "2013-4-4"),
array("event_start" => "2013-4-7", "event_end" => "2013-4-7"),
array("event_start" => "2013-4-9", "event_end" => "2013-4-9"),
array("event_start" => "2013-4-20", "event_end" => "2013-4-20"),
array("event_start" => "2013-5-5", "event_end" => "2013-5-10"),
array("event_start" => "2014-1-1", "event_end" => "2014-1-2"),
);
// the actual code for range list generation:
for ($i = 0; $i < count($events); $i++)
{
// parse start and end of this range
$this_event = $events[$i];
$this_start_date = strtotime($this_event["event_start"]);
$this_end_date = strtotime($this_event["event_end"]);
// extract months and years
$this_start_month = date("M", $this_start_date);
$this_end_month = date("M", $this_end_date);
$this_start_year = date("Y", $this_start_date);
$this_end_year = date("Y", $this_end_date);
$last = ($i == count($events) - 1);
// parse start and end of next range, if any
if (!$last)
{
$next_event = $events[$i + 1];
$next_start_date = strtotime($next_event["event_start"]);
$next_end_date = strtotime($next_event["event_end"]);
$next_start_month = date("M", $next_start_date);
$next_end_month = date("M", $next_end_date);
$next_start_year = date("Y", $next_start_date);
$next_end_year = date("Y", $next_end_date);
}
// ranges with different starting and ending months always go
// on their own line
if (($this_start_month != $this_end_month) ||
($this_start_year != $this_end_year))
{
echo date("j M", $this_start_date);
// print starting year only if it differs from ending year
if ($this_start_year != $this_end_year)
{
echo " ".date("Y", $this_start_date);
}
echo "-".date("j M Y", $this_end_year)." <br/>\n";
}
else
{
// this is range starting and ending in the same month
echo date("j", $this_start_date);
// different starting and ending day
if ($this_start_date != $this_end_date)
{
echo "-".date("j", $this_end_date);
}
$newline = false;
// print month for the last range;
// and for any range that starts(=ends) in different month
// than the next range ends
if ($last ||
($this_start_month != $next_end_month))
{
echo " ".date("M", $this_start_date);
$newline = true;
}
// print year for the last range;
// and for any range that starts(=ends) in different year
// than next range ends
if ($last ||
($this_start_year != $next_end_year) ||
($next_start_month != $next_end_month))
{
echo " ".date("Y", $this_start_date);
$newline = true;
}
if ($newline)
{
echo " <br/>\n";
}
else
{
// month (and year) will be printed for some future range
// on the same line
echo ", ";
}
}
}
This outputs:
4, 7, 9, 20 Apr <br/>
5-10 May 2013 <br/>
1-2 Jan 2014 <br/>
A possibility to check if you need to print the month for the current date item is actually to check in the next item. Let me try to explain with pseudocode:
<?php
$month = 0; // Initialize $month variable to unset
// Loop over all your events
foreach($dates as $date) {
// Convert $date to a timestamp
// If the 'month' of the current $timestamp is unequal to $month
// it means we switch months and we have to print the $month first
if(date('m', $timestamp) != $month) {
echo $month; // Of course format how you want it to be displayed
// Set $month to the new month
$month = date('m', $timestamp);
}
// Print the rest of the event, like day numbers here
}
?>
Well, since you need to compare value from one loop to another, you won't be able to use echo directly.
You need to use temp variables. So with the first loop for the start date, you store $tmp_day_1 and $tmp_month_1 then with the end date loop you can compare both months and check if they are diferents. Then you can use echo. I hope I make my point :)
Does anyone have a PHP snippet to calculate the next business day for a given date?
How does, for example, YYYY-MM-DD need to be converted to find out the next business day?
Example:
For 03.04.2011 (DD-MM-YYYY) the next business day is 04.04.2011.
For 08.04.2011 the next business day is 11.04.2011.
This is the variable containing the date I need to know the next business day for
$cubeTime['time'];
Variable contains: 2011-04-01
result of the snippet should be: 2011-04-04
Next Weekday
This finds the next weekday from a specific date (not including Saturday or Sunday):
echo date('Y-m-d', strtotime('2011-04-05 +1 Weekday'));
You could also do it with a date variable of course:
$myDate = '2011-04-05';
echo date('Y-m-d', strtotime($myDate . ' +1 Weekday'));
UPDATE: Or, if you have access to PHP's DateTime class (very likely):
$date = new DateTime('2018-01-27');
$date->modify('+7 weekday');
echo $date->format('Y-m-d');
Want to Skip Holidays?:
Although the original poster mentioned "I don't need to consider holidays", if you DO happen to want to ignore holidays, just remember - "Holidays" is just an array of whatever dates you don't want to include and differs by country, region, company, person...etc.
Simply put the above code into a function that excludes/loops past the dates you don't want included. Something like this:
$tmpDate = '2015-06-22';
$holidays = ['2015-07-04', '2015-10-31', '2015-12-25'];
$i = 1;
$nextBusinessDay = date('Y-m-d', strtotime($tmpDate . ' +' . $i . ' Weekday'));
while (in_array($nextBusinessDay, $holidays)) {
$i++;
$nextBusinessDay = date('Y-m-d', strtotime($tmpDate . ' +' . $i . ' Weekday'));
}
I'm sure the above code can be simplified or shortened if you want. I tried to write it in an easy-to-understand way.
For UK holidays you can use
https://www.gov.uk/bank-holidays#england-and-wales
The ICS format data is easy to parse. My suggestion is...
# $date must be in YYYY-MM-DD format
# You can pass in either an array of holidays in YYYYMMDD format
# OR a URL for a .ics file containing holidays
# this defaults to the UK government holiday data for England and Wales
function addBusinessDays($date,$numDays=1,$holidays='') {
if ($holidays==='') $holidays = 'https://www.gov.uk/bank-holidays/england-and-wales.ics';
if (!is_array($holidays)) {
$ch = curl_init($holidays);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,true);
$ics = curl_exec($ch);
curl_close($ch);
$ics = explode("\n",$ics);
$ics = preg_grep('/^DTSTART;/',$ics);
$holidays = preg_replace('/^DTSTART;VALUE=DATE:(\\d{4})(\\d{2})(\\d{2}).*/s','$1-$2-$3',$ics);
}
$addDay = 0;
while ($numDays--) {
while (true) {
$addDay++;
$newDate = date('Y-m-d', strtotime("$date +$addDay Days"));
$newDayOfWeek = date('w', strtotime($newDate));
if ( $newDayOfWeek>0 && $newDayOfWeek<6 && !in_array($newDate,$holidays)) break;
}
}
return $newDate;
}
function next_business_day($date) {
$add_day = 0;
do {
$add_day++;
$new_date = date('Y-m-d', strtotime("$date +$add_day Days"));
$new_day_of_week = date('w', strtotime($new_date));
} while($new_day_of_week == 6 || $new_day_of_week == 0);
return $new_date;
}
This function should ignore weekends (6 = Saturday and 0 = Sunday).
This function will calculate the business day in the future or past. Arguments are number of days, forward (1) or backwards(0), and a date. If no date is supplied todays date will be used:
// returned $date Y/m/d
function work_days_from_date($days, $forward, $date=NULL)
{
if(!$date)
{
$date = date('Y-m-d'); // if no date given, use todays date
}
while ($days != 0)
{
$forward == 1 ? $day = strtotime($date.' +1 day') : $day = strtotime($date.' -1 day');
$date = date('Y-m-d',$day);
if( date('N', strtotime($date)) <= 5) // if it's a weekday
{
$days--;
}
}
return $date;
}
What you need to do is:
Convert the provided date into a timestamp.
Use this along with the or w or N formatters for PHP's date command to tell you what day of the week it is.
If it isn't a "business day", you can then increment the timestamp by a day (86400 seconds) and check again until you hit a business day.
N.B.: For this is really work, you'd also need to exclude any bank or public holidays, etc.
I stumbled apon this thread when I was working on a Danish website where I needed to code a "Next day delivery" PHP script.
Here is what I came up with (This will display the name of the next working day in Danish, and the next working + 1 if current time is more than a given limit)
$day["Mon"] = "Mandag";
$day["Tue"] = "Tirsdag";
$day["Wed"] = "Onsdag";
$day["Thu"] = "Torsdag";
$day["Fri"] = "Fredag";
$day["Sat"] = "Lørdag";
$day["Sun"] = "Søndag";
date_default_timezone_set('Europe/Copenhagen');
$date = date('l');
$checkTime = '1400';
$date2 = date(strtotime($date.' +1 Weekday'));
if( date( 'Hi' ) >= $checkTime) {
$date2 = date(strtotime($date.' +2 Weekday'));
}
if (date('l') == 'Saturday'){
$date2 = date(strtotime($date.' +2 Weekday'));
}
if (date('l') == 'Sunday') {
$date2 = date(strtotime($date.' +2 Weekday'));
}
echo '<p>Næste levering: <span>'.$day[date("D", $date2)].'</span></p>';
As you can see in the sample code $checkTime is where I set the time limit which determines if the next day delivery will be +1 working day or +2 working days.
'1400' = 14:00 hours
I know that the if statements can be made more compressed, but I show my code for people to easily understand the way it works.
I hope someone out there can use this little snippet.
Here is the best way to get business days (Mon-Fri) in PHP.
function days()
{
$week=array();
$weekday=["Monday","Tuesday","Wednesday","Thursday","Friday"];
foreach ($weekday as $key => $value)
{
$sort=$value." this week";
$day=date('D', strtotime($sort));
$date=date('d', strtotime($sort));
$year=date('Y-m-d', strtotime($sort));
$weeks['day']= $day;
$weeks['date']= $date;
$weeks['year']= $year;
$week[]=$weeks;
}
return $week;
}
Hope this will help you guys.
Thanks,.
See the example below:
$startDate = new DateTime( '2013-04-01' ); //intialize start date
$endDate = new DateTime( '2013-04-30' ); //initialize end date
$holiday = array('2013-04-11','2013-04-25'); //this is assumed list of holiday
$interval = new DateInterval('P1D'); // set the interval as 1 day
$daterange = new DatePeriod($startDate, $interval ,$endDate);
foreach($daterange as $date){
if($date->format("N") <6 AND !in_array($date->format("Y-m-d"),$holiday))
$result[] = $date->format("Y-m-d");
}
echo "<pre>";print_r($result);
For more info: http://goo.gl/YOsfPX
You could do something like this.
/**
* #param string $date
* #param DateTimeZone|null|null $DateTimeZone
* #return \NavigableDate\NavigableDateInterface
*/
function getNextBusinessDay(string $date, ? DateTimeZone $DateTimeZone = null):\NavigableDate\NavigableDateInterface
{
$Date = \NavigableDate\NavigableDateFacade::create($date, $DateTimeZone);
$NextDay = $Date->nextDay();
while(true)
{
$nextDayIndexInTheWeek = (int) $NextDay->format('N');
// check if the day is between Monday and Friday. In DateTime class php, Monday is 1 and Friday is 5
if ($nextDayIndexInTheWeek >= 1 && $nextDayIndexInTheWeek <= 5)
{
break;
}
$NextDay = $NextDay->nextDay();
}
return $NextDay;
}
$date = '2017-02-24';
$NextBussinessDay = getNextBusinessDay($date);
var_dump($NextBussinessDay->format('Y-m-d'));
Output:
string(10) "2017-02-27"
\NavigableDate\NavigableDateFacade::create($date, $DateTimeZone), is provided by php library available at https://packagist.org/packages/ishworkh/navigable-date. You need to first include this library in your project with composer or direct download.
I used below methods in PHP, strtotime() does not work specially in leap year February month.
public static function nextWorkingDay($date, $addDays = 1)
{
if (strlen(trim($date)) <= 10) {
$date = trim($date)." 09:00:00";
}
$date = new DateTime($date);
//Add days
$date->add(new DateInterval('P'.$addDays.'D'));
while ($date->format('N') >= 5)
{
$date->add(new DateInterval('P1D'));
}
return $date->format('Y-m-d H:i:s');
}
This solution for 5 working days (you can change if you required for 6 or 4 days working). if you want to exclude more days like holidays then just check another condition in while loop.
//
while ($date->format('N') >= 5 && !in_array($date->format('Y-m-d'), self::holidayArray()))