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Notice: Undefined index: id in D:\xampp\htdocs\inventarisrf\update.php on line 34
Data Gagal diupdate.";
}
}
?>
Just add $id=null; before you declare $id
example:
$id=null;
$id= htmlspecialchars($_POST['id']);
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Closed 9 months ago.
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I have the following php code below, it keeps throwing out a undefined variable $checked once the plugin is activated.
How do I use function in function correctly?
write this :
function sanitize_check($check = null)
insted:
function sanitize_check($check)
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Closed 6 years ago.
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I need to remove [picture_names] from my array. Help me to remove this?
Use unset function:
unset($array['picture_names']);
You can do it with unset() function. Documentation here.
$result = unset($yourArray['picture_names']);
var_dump($result);
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Closed 7 years ago.
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I'm new in laravel 5.1. can you help me solving this error?
This is my code
You should refer to the User model like this:
$datas = \App\User::paginate(5);
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Closed 7 years ago.
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I have this code.
<?php echo "".$row['pname']."";?></h4>
When I click on the link,Its only posting the first word of the string,the rest are ignored
Missing the quotes for href attribute -
echo "<a href='pvendors.php?post=".$par."'>".$row['pname']."</a>";
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Closed 8 years ago.
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Laravel
What mistake am I actually doing?
Please have a look at the image below:
http://1drv.ms/1ybX4Cg
I think
$body['user_id'] = $user()->id;
should be
$body['user_id'] = $user->id;