PHP get JSON object value from Input array (array-like name) - php

Question

I have 3 inputs like this:
<input type="text" name="product[1][name]" >
<input type="text" name="product[1][cost]" >
<input type="text" name="product[1][qty]" >
... which goes until n products
<input type="text" name="product[n][name]" >
<input type="text" name="product[n][cost]" >
<input type="text" name="product[n][qty]" >
and based on the input value a JSON string like this:
{"product[1][name]": "Prod1", "product[1][cost]": "100$", "product[1][qty]": "3", "product[2][name]": "Prod2", ... }
how can I retrieve their name and value because neither json_decode function can take their values because of the array-like name
$decodedObject=json_decode($array['data']); // this data contains the json string
echo $decodedObject->product; // does not work
echo $decodedObject->product[1][qty]; // does not work
is there any simple way?
Or the only way is to cut the name like product[, take the inside elements , and the value after the : and so on?
But how can I even take the object from it without letting PHP know that's not an array ?

Answer 1

Firstly I found an alternative. The problem is that this:
$decodedObject=json_decode($array['data']); // will create an object
will not transform it in an array, instead I have used this:
$decodedObject=json_decode($array['data'], true); // will create an array
after that I had checked how many objects exist, and then just add them to another array:
$i=1;
while(isset($decodedObject["product[$i][qty]"])) // while any element exists
{
$newProducs= array();
$newProducs['name'] = $decodedObject["product[$i][name]"];
$newProducs['cost'] = $decodedObject["product[$i][cost]"];
$newProducs['qty'] = $decodedObject["product[$i][qty]"];
array_push($products, $newProducs); // optional: add to the main array (products) the new-created array (newProducs)
$i++; //increment to search another product
}
The problem was that I was not fully creating an array -_-
While this is not the full answer I still hope somebody will find a better solution and not a change.