i can't figure out this thing i think it possible with only one pattern, please help me improve.
I have this string 2 / 3 items and i wont receive only 2 / 3
Items can also be write in cirillic so 2 / 3 штуки
So i think the best way is use \D all non digit (result 23)
But this delete also the slash that i want to keep, how i can do?
// this was my solution for now,
// but it not complete for cirillic cause i have an error
// it return: 2 / 3 �
// maybe is something with encoding?
preg_replace('#[a-zA-Zа-яА-Я]*#', '', '2 / 3 штуки');
// so i chose to do this, but doesn't know how to keep slash
preg_replace('#[\D]*#', '', '2 / 3 штуки');
// it return: 23
# How to get 2 / 3 ?
You can use
if (preg_match('~\d+\s*/\s*\d+~u', $text, $match)) {
echo $match[0];
}
Also, if the fraction part is optional, use
preg_match('~\d+(?:\s*/\s*\d+)?~u', $text, $match)
And if you need to extract all occurrences, use preg_match_all:
preg_match_all('~\d+(?:\s*/\s*\d+)?~u', $text, $matches)
See the regex demo and the PHP demo. Note that preg_match extracts the match rather than remove it (as is the case with preg_replace).
Pattern details
\d+ - one or more digits
- \s*/\s* - / enclosed with zero or more whitespaces
\d+ - one or more digits
Note that u is used in case the whitespace in your string can be other than regular ASCII whitespace, like \xA0.
Related
There is a string with numbers I need to validate with PHP preg_match.
If it starts with 10 or 20 or 30, I need 7 more numbers after the inital 2, but in any other cases I need 8 numbers only and don't care what are the lead characters.
The first part is the simple one
/^(1|2|3)0\d{7}$
But how can I add an ELSE part? There I need a simple
^\d{8}$
I need to match these examples:
101234567
201234567
12345678
33445566
You may use
^(?:[1-3]0\d{7}|(?![1-3]0)\d{8})$
See the regex demo
Details
^ - start of string
(?: - start of a non-capturing group:
[1-3]0\d{7} - 1, 2 or 3, then 0 and any 7 digits
| - or
(?![1-3]0)\d{8} - no 10, 20 or 30 immediately at the start of the string are allowed, then any 8 digits are matched
) - end of the group
$ - end of the string.
Here's an alternative using (?(?=regex)then|else) aka conditionals:
^(?(?=[1-3]0)[1-3]0\d{7}|\d{8})$
It literally says: if [1-3]0 is right at the start, match [1-3]0\d{7}, else match \d{8}.
Demo: https://regex101.com/r/LXoHyk/1 (examples shamelessly taken from Wiktor's answer)
I have a value like this 73b6424b. I want to split value into two parts. Like 73b6 and 424b. Then the two split value want to reverse. Like 424b and 73b6. And concatenate this two value like this 424b73b6. I have already done this like way
$substr_device_value = 73b6424b;
$first_value = substr($substr_device_value,0,4);
$second_value = substr($substr_device_value,4,8);
$final_value = $second_value.$first_value;
I am searching more than easy way what I have done. Is it possible?? If yes then approach please
You may use
preg_replace('~^(.{4})(.{4})$~', '$2$1', $s)
See the regex demo
Details
^ - matches the string start position
(.{4}) - captures any 4 chars into Group 1 ($1)
(.{4}) - captures any 4 chars into Group 2 ($2)
$ - end of string.
The '$2$1' replacement pattern swaps the values.
NOTE: If you want to pre-validate the data before swapping, you may replace . pattern with a more specific one, say, \w to only match word chars, or [[:alnum:]] to only match alphanumeric chars, or [0-9a-z] if you plan to only match strings containing digits and lowercase ASCII letters.
I an trying to get a regex for a phone number with exactly 12 digits in the format: +############.
Code i am trying to use is ([+]?)\d{12}(\d{2})?$ but no luck.
Please help
This pattern will match exactly 12 digits after a plus sign:
/^\+\d{12}$/
What is your trailing optional (/d{2})? component doing in your pattern?
This is the same functionality without regex:
$phone='+012345678912';
if($phone[0]=='+' && strlen($phone)==13 && is_numeric(substr($phone,1))){
echo 'valid';
}else{
echo 'invalid';
}
// displays: valid
Try this:
^\+\d{12}(\d{2})?$
You needed to escape the plus sign
Regex101 Demo
Do we need to capture certain digits/sequences or are you just validating its a number with that format?
I use this online tool regex101 whenever I'm unsure of regex. It shows on the right exactly what you're capturing/checking which is very useful. Depending on your use case, I don't see how this regex doesn't work, please provide an example. Otherwise:
You're only capturing the + sign and the 2 digits after the initial 12.
You anchor to the end of the string and not the beginning
Both the + and 2 extra numerals are optional but you wanted to get the +############ exact?
I suggest you use \+(\d{12}) and avoid using anchors and capture groups you do not require.
If you want to support optional spaces between sets of three numbers, you would use this regex instead
^(\+)(\d{3}\s?){4}(\d{2})?$
where \s is a space character and ? means optional
https://regex101.com/r/nX5XnH/3 (demo)
+012 345 678 912 (ok)
+012345 678 912 (ok)
+012 345678912 (ok)
+01234567891244 (ok)
012345678913 (no mach - missing plus sign)
$txt = "toto1 555.4545.555.999.7465.432.674";
$rgx = "/([\w]+)\s([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)/";
preg_match($rgx, $txt, $res);
var_dump($res);
I would like to simplify this pattern by avoiding repeating "([0-9]+)" because i don't know how many they are.
Any one can say me how ?
Here is a direct answer to the question, as you have stated it:
/[\w]+\s[0-9]+(?:\.[0-9]+)+/
However, note that I have removed all of the numbered capture groups. This could be problematic, depending on what you're actually trying to achieve.
It is not possible to "count" with capture groups in regular expressions, so you would need to write some other code (i.e. not just one match, with one regex, and using back-references) to deal with this if you wish to run any queries like "What digits appear after the fifth "."?"
There are two ways you can do this. If you just need to verify that the string matches the pattern, this regex will do the job: \w+\s(?:[0-9]+\.?)+
However, if you need to split the string in to it's component parts (in my interpretation, the beginning word followed by the sequence of decimal separated numbers), then you could use this pattern: (\w+)\s((?:[0-9]+\.?)+)
The second pattern will return the beginning word, toto1 in group 1, followed by the decimal separated numbers in group 2 555.4545.555.999.7465.432.674 which you could then split in PHP if required: $sequence = explode('.', $matches[2]);
What you need can be obtained with a preg_split with a regex matching 1 or more whitespaces or dots:
$txt = "toto1 555.4545.555.999.7465.432.674";
$rgx = '/[\s.]+/';
$res = preg_split($rgx, $txt);
print_r($res);
See the PHP demo
If you need a regex approach, you can use a \G based regex with preg_match_all:
'~(?|([\w]+)|(?!\A)\G[\s.]*([0-9]+))~'
See the regex demo and a PHP demo:
$txt = "toto1 555.4545.555.999.7465.432.674";
$rgx = '~(?|(\w+)|(?!\A)\G[\s.]*([0-9]+))~';
preg_match_all($rgx, $txt, $res);
print_r($res[1]);
Pattern details:
The (?|...) is a branch reset group to reset group IDs in all the branches
(\w+) - Group 1 matches 1+ word chars
| - or (then goes Branch 2)
(?!\A)\G - the end of the previous successful match
[\s.]* - zero or more whitespaces or dots
([0-9]+) - Group 1 (again!) matching 1 or more digits.
I'm attempting to extract [digit][digit][colon][digit][digit] from a string if it is present. The Regex should match:
02:59
03:24
So far I've got quite lost, though I've realised \d will return me a single digit, and \d{2} should find me 2, but I've got stuck with adding in the separator : and finding 2 more digits to fit into my preg_match:
$trackTime = preg_match($regexEludingMe, $track, $matches);
Example $track is:
10. Break Your Heart 03:42 should match 03:42
Just add the separator : and duplicate the first part that you've already figured out \d{2}:\d{2}. Don't forget delimiters:
preg_match('/\d{2}:\d{2}/', $track, $trackTime);
print_r($trackTime);