I want to get the contents of my install.sql file that sits one directory up but when I use file_get_contents("../install.sql") it returns false.
How can I fix it?
I have also tried to use fopen and fread.
<?php
// Get the install SQL Files
if (#$install_sql = file_get_contents("../install.sql")){
// Prepare the statement to install
$install_stmt = $conn_test->prepare($install_sql);
// Execute the install
$install_stmt->execute();
} else {
// This is where the code ends up
}
?>
Code shortened
Full code available here
For people suggesting to remove '#' to show errors:
Warning:
file_get_contents(../install.sql): failed to open stream: No such file or directory in
/Users/yigitkerem/Code/SkyfallenSecureForms/Configuration/install.php
on line
55
For me it wasn't making any more sense, that was why I didn't include it, but here we go in case there is something that I don't know.
I have fixed the problem.
I will now briefly describe it here as well.
So this install file was called from another file,
// Unless the installation was complete, the Database Config should exist, if not, run the install.
if((#include_once SSF_ABSPATH . "/Configuration/SecureFormDatabaseConfiguration.php") === false){
// Include the install file
include_once SSF_ABSPATH."/Configuration/install.php";
// Stop further execution
die();
}
I was using the path relative to the install.php file inside the Configuration folder but it turns out the path I used, should have been relative to the file it made the call from.
So to not come across the same problem in the future, I now define a ABSOLUTE PATH from the root file just like WordPress to use as a reference, as expected now I don't need to consider about where the file was called from.
Thanks to #Luuk #tadman for helping me out
Related
I have a php file (php1.php). Within that php file i have the following line:
include('php/PROTECT/login.php')
However when i load the page i get the following error:
Warning: include(php/login.php) [function.include]: failed to open stream: No such file or directory
it just totally ignores the /PROTECT/ section?
Does anyone have any ideas why this is and how i can resolve the issue?
My file structure is as follows: (php1.php is within /php and login.php is within /php/PROTECT
It should look like:
include('php/PROTECT/login.php');
Make absolutely sure that that's the include call that's throwing the error. Make sure that no other code, in php1.php or in any file it has included or required tries to include php/login.php.
If php1.php is within /php/ (which I understand it to be), then you will need to use the following:
include('PROTECT/login.php');
Includes in includes can be a bit messy, but if you concatenate with DIR it is easier. DIR is always path to the file it self, if you use DIR you can always use the relative path. Like this:
include DIR . "/PROTECT/login.php";
As you can see by the error message:
Warning: include(php/login.php)
"PROTECT" is excluded from the path, probably for being in all caps.
Change the directory to all lowercase ("protect" or similar) and see if you get the same error.
I am having a weird problem with my php. Whenever I try to move a file with rename(), not only the file is not moved, but also the directory to which it should be copied is deleted, together with all files within it. The original code is:
rename('temp.odt', 'tmp/report.odt');
but I have already tried other path delimiters like
rename('temp.odt', 'tmp\report.odt');
rename('temp.odt', 'tmp\\report.odt');
rename('temp.odt', 'tmp' . DIRECTORY_SEPARATOR . 'report.odt');
rename('C:\wamp\www\zaiko\temp.odt', 'C:\wamp\www\zaiko\tmp\report.odt');
all to no avail. The code comes from a 3rd-party module which is used in the system I am working on.
Points well checked:
The file 'temp.odt' does exist in the current directory;
The directory 'tmp' does exist and there are several files in it. Also it is not read only.
The target file does not already exist (the actual file name has a timestamp, I reduced it here for simplicity)
After running rename(), the 'temp.odt' file is intact in its original location, while the folder 'tmp' is vanished as well as everything inside it. The following warning is issued:
( ! ) Warning: rename(temp.odt,tmp\report.odt) [function.rename]: The system couldn't find the specified path*. (code: 3) in C:\wamp\www\zaiko\modules\mod_deliver.php on line 192
*translated from Portuguese
Running: Apache 2.2.17 with PHP 5.3.5 on Windows XP with NTFS
Editing:
Just found the cause of the problem. It turns out that the module used by the application uses, in turn, a compression library; this library uses a temporary folder with exactly the same name as the one used by the application.
It must use some sort of cache, which would explain why the error didn't appear 100% times.
Problem solved by changing the name of the 'tmp' folder to anything else.
Thank you all for your time, and sorry for bothering you with such a stupid thing that, as it turns out, had absolutely nothing to do with my initial guess and, consequently, with the question formulated.
The example on PHP.net tells you exactly what to do - use the ROOT PATH to the file - normally this can be got by using $_SERVER['DOCUMENT_ROOT'] (but this only goes to the htdocs/public_html directory - you need to specify the rest) or by manually typing the path in (but try to avoid this).
<?php
rename("/tmp/tmp_file.txt", "/home/user/login/docs/my_file.txt");
?>
At a guess, the following should work (assuming this is your path) - this also checks that your file actually exists so it can be renamed - you need to make sure that tmp/ actually exists in the first place, but you will get an error popping out if it didn't:
<?php
$root = getcwd().DIRECTORY_SEPARATOR; // Obtain the current working dir
$srcpath = $root."temp.odt"; // The file you want to rename
$destpath = $root."tmp/report.odt"; // Where you want to rename the file to
// make sure file exists and its movable
if(is_writable($srcpath)){
// if it exists, rename it
rename($srcpath, $dstpath);
echo "File was renamed!";
} else {
echo "It seems that the specified file doesn't exist!";
}
?>
You were escaping characters by using backslashes - always use forward slashes (I know this is within a single quote, which is ok, but if you use double quote then you would wonder what's gone wrong)!
Attempting to expand my knowledge by using PHP on the Command Line.
Currently I have a default installation of XAMPP, and have set up my Environment Variable.
I've been able to execute simple scripts like:
<?php echo 'hello world!'; ?>
Questions ~
Where do I store the scripts I am using? Currently I am doing:
C:\Users\Ross>php c:\helloworld.php
it works. Does this mean I need to specify a path every time? Or should I store php files inside my c:>xampp\php directory? I tried this and it doesn't appear to work.
What would be the accepted "best practice".
2nd question
Could someone explain why this doesn't work:
<?php
fwrite(STDOUT, "Enter file name:\n");
$file=fgets(STDIN);
print 'you entered...' . $file;
$fp=fopen($file,'r');
if(!$fp)
{
print 'File could not be opened..';
}
else
{
/* show file pointer */
print($fp);
}
?>
and then I do:
C:\Users\Ross>php c:\file.php
Enter file name:
c:\foo.txt
you entered...c:\foo.txt
Warning: fopen(c:\foo.txt): failed to open stream: Invalid argument in C:\file.php on line 6
File could not be opened..
"foo.txt" is in the same directory and does exist.
thanks for any clarification.
As far as were to store the files is concerned: I normally add the directory where php.exe is to my PATH environment variable, that way I can just call php in whatever directory contains the script I need to run. If you don't add the directory to PATH, then you would need to either run php from its directory and specify the full path to the PHP script, or run it from the directory where the PHP script is and specify the full path to the PHP executable.
Regarding opening the file: the reason this is occurring is because fgets is returning the newline from you pressing enter, too (it would seem). So in reality, it's trying to open a file whose name actually ends with a new line character.
Change the line:
$file=fgets(STDIN);
to:
$file=trim(fgets(STDIN));
and you should be fine.
question #1: all your php files should be inside the www folder of xampp (c:\xampp\www)
question #2: probably because you are not working in the correct folder.
xammp is good but I recommend you to use wamp, it's much easier to understand and use. Just google for it. xampp is more for those who are more techically skilled.
When I use ../mysqlConnect.php I get the following messages.
Warning: require_once(../mysqlConnect.php) [function.require-once]:
failed to open stream: No such file or directory in /home/content/etc...
Fatal error: require_once() [function.require]: Failed opening required
'../mysqlConnect.php' (include_path='.:/usr/local/php5/lib/php') in /home/content/etc...
When I use the directory name - mydir/mysqlConnect.php - everything works fine.
require_once('../mysqlConnect.php') asks PHP to look in the directory above the one your script is currently in for mysqlConnect.php.
Since your connection file appears to be in a mydir directory, require_once('mydir/mysqlConnect.php') works because it looks in that directory, which is contained by the one it's currently in.
Visual representation (assuming script.php is your script including that file):
dir/
subdir/ # PHP looks here for ../mysqlConnect.php
script.php
mydir/ # PHP looks here for mydir/mysqlConnect.php
mysqlConnect.php
Require is relative to the invoced script, not the script you call require() in. Use something like this to have an absolute path:
require(dirname(__FILE__) . '/../mysqlConnect.php');
In PHP 5 you can also use DIR.
because it doesn't find your file then. to give a more specific answer I need to see you file-/folder-structure
That's because you are not specifying the correct include path. ../ refers to parent directory. ../../ goes two directories back, ../../../ goes three of them back. If the mysqlConnect.php file is present in the same folder as your script, you don't need to specify ../ in the include.
Make sure that you specify the correct path. You can easily check whether or not you are specifying correct path like:
if (file_exists('../mysqlConnect.php'))
{
echo 'Iam specifying the correct path !!';
}
else
{
echo 'Well, I am not :(';
}
I'm working on a site here where I include parts of the site that are called in multiple locations in it's own sub directory. I created a file in said directory and tried to include it in a file, but for some reason tis' not working. Here's the code that is within that file.
<?php
require_once("a_file.php"); //this file loads
require_once("another_file.php"); //so does this one
require_once("problem_file.php"); //this one does not.
echo foo('I exist');
?>
and the code for the file not being found.
<?php
function foo($string) {
if ($string) {
return $string;
}
}
?>
The spelling for the file has been verified to be correct in both the file with the require and the file being called. The include path in the .htaccess file is correct (otherwise none of the required files would load without the full path being specified. The error message is "failed to open stream: No such file or directory". All permissions are the same for the files in the include directory.
Has anyone else ran into this issue?
Do you have any error in the error_log? It could be that the third file has some more require_once that are not found.
You could try using $_SERVER['DOCUMENT_ROOT'] to get your root directory and use it for your requires.
A quick way to know if it came from the content of the file would be to paste it in the main file.
If that test doesn't give anything make sure PHP has enough permissions to read the concerned file.
Is it reasonable to assume that the real file that won't include is not called problem_file.php? If that is so, then perhaps your file name has characters (like spaces) that need to be escaped.