There are a page page1.php below:-
<?php
$name = "xyz";
?>
<form action="page2.php" method="POST">
Age : <input type="number" name="age">
<button type="submit">SUBMIT</button>
</form>
after submitting the form at page1,
How to get value of $name of page1.php in page2.php
what should change in page-1?
If you ask also for a name on page1, then simply use another input:
<form action="page2.php" method="POST">
Name : <input type="text" name="name">
Age : <input type="number" name="age">
<button type="submit">SUBMIT</button>
</form>
If the name is fixed and you want it transmitted via POST, usa a hidden input:
<form action="page2.php" method="POST">
Name : <input type="hidden" name="name" value="<?php echo htmlspecialchars($name) ?>">
Age : <input type="number" name="age">
<button type="submit">SUBMIT</button>
</form>
Then in page2.php read the POST-ed value:
$name = $_POST['name'];
You can submit the parameters in page1 by setting the hidden mode in the form，like this:
<input type="hidden" name="field＿name" value=$name >
You can get it in Page2
You can use a hidden input type.
Just be aware that users can edit these values so you should consider any vulnerability this may bring.
Related
I am facing a problem while self posting form data, when I hit submit button the page should display the data inserted in the input box,
but it does not show the data....
Here is my example form
<?php
if($_SERVER['REQUEST_METHOD']=='POST')
{
$mail = $_POST['mail'];
echo $mail;
}
?>
<form action="<?php $_SERVER['PHP_SELF']; ?>" method="post" name="myForm">
Mail : <input id="mail" name="mail" type="text"/>
<input type="submit" value="Submit"/>
</form>
This should obviously display the mail value from the input box. But it does not work. Then I tried to change the action attribute value to "mywordpress/index.php/customer-details-2/"
Since I am new with Wordpress, any help would be highly appreciated.
Add the posted value in your input text box as :
<form action="<?php $_SERVER['PHP_SELF']; ?>" method="post" name="myForm">
Mail : <input id="mail" name="mail" type="text" value="<?php echo (isset($_POST['mail'])) ? $_POST['mail'] : '' ?>" />
<input type="submit" value="Submit" />
</form>
I am assuming that you want to show data inside input text box.
Hope it helps you.
I have 2 html pages :
page1.html
<html>
<body>
<form action="page2.html" method="post">
Enter First name: <input type="text" id="text1">
<input type="submit" value="Next">
</form>
</body>
</html>
page2.html
<html>
<body>
<form action="test.php" method="post">
Enter Last name: <input type="text" id="text2">
<input type="submit" value="Submit">
</form>
</body>
</html>
Now, i would like to retrieve the value of text1 from page1.html and text2 from page2.html. How can i go about it?
Looks like you are looking for forms. See this tutorial http://www.w3schools.com/php/php_forms.asp. Post your form data from page1.php to page2.php. On page2.html you can access them via $_POST.
Please be aware: This is not a secure example, just for showing purposes! When you want to show user generated data in your frontend, please use sanitizing and validation http://www.php.net/manual/en/filter.examples.sanitization.php.
page1.php:
<form action="page2.php" method="post">
Enter first name: <input type="text" name="firstName"><br>
<input type="submit">
</form>
page2.php
<h1>Hey <?php echo $_POST['firstName']; ?></h1>
<form action="lastpage.php" method="post">
Enter last name: <input type="text" name="lastName"><br>
<input type="hidden" name="firstName" value="<?php echo $_POST['firstName']; ?>">
<input type="submit">
</form>
lastpage.php
<h1>Yo, my mate <?php echo $_POST['firstName']; ?> <?php echo $_POST['lastName']; ?>!</h1>
I have a php and html based tool that has a form that, when submitted, outputs the data reformatted using echo commands.
I'd like to add a 2nd form to the same page that will also output using echo.
My issue is, when I submit the 2nd form the first forms output disappears. I'd like to make it so the echo output from the first form does not go away when the 2nd form is submitted so they will both be on the screen at the same time.
Is there a way I can do this?
Only one <form> block in a page can be submitted at a single time. <input> fields defined in one form will not be submitted when the other form is submitted.
e.g.
<form>
<input type="text" name="foo" />
<input type="submit" />
</form>
<form>
<input type="text" name="bar" />
<input type="submit" />
</form>
Clicking on submit will submit either a foo field, OR a bar field. Not both. If you want both fields to be submitted, then you have to either build them into a SINGLE form:
<form>
<input type="text" name="foo" />
<input type="text" name="bar" />
<input type="submit" />
</form>
or use Javascript to copy the data from one form to another.
<form method="post"> <div>Module1</div> <input type="text"
value="module1" name="module_id"> <input type="text" value="title 1"
name="title"> <input type="text" value="some text 1" name="text">
<input type="submit" name="form_1" value="submit"> </form>
<form method="post"> <div >Module2</div> <input type="text"
value="module2" name="module_id"> <input type="text" value="title 2"
name="title"> <input type="text" value="some text 2" name="text">
<input type="submit" name="form_2" value="submit"> </form>
<?php
if(isset($_POST['form_1'])){
echo '<pre>';
print_r($_POST); }
if(isset($_POST['form_2'])){
echo '<pre>';
print_r($_POST); } ?>
Yes,you can do it.
Eg :
// form1 on page a.php
<form method="post" action="a.php" name="form_one" >
<input type="text" name="form_1" value="if(isset($_POST['form_1'])) echo $_POST['form_1']; ?>" >
<input type="submit" name="submit_1" >
</form>
<?php
if(isset($_POST['submit']))
{
?>
<form method="post" action="a.php" name="form_two" >
<input type="text" name="form_2" value="if(isset($_POST['form_2'])) echo $_POST['form_2']; ?>" >
<input type="submit" name="submit_2" >
</form>
<?php
}
?>
Now when you will submit form_one you will see form_two appear and the value in form one will stay intact in form_one and one the submitting form two the value will remain.
Hope it helped :)
I have two input forms and would like the second one to stay on the page even when it is submitted.
<div id="first">
<form method="POST">
Number: <input type="text" name="number"><br>
<input type="submit" value="Submit">
</form><br>
</div>
<div id="second">
<?php
if (isset($_POST['number']) && !empty($_POST['number'])){
?>
<form method="POST">
Name: <input type="text" name="name"><br>
<input type="submit" value="Submit">
</form><br>
<?php
}
?>
</div>
<div id="third">
<?php
if (isset($_POST['name']) && !empty($_POST['name'])){
echo "TEST";
}
?>
</div>
When I submit my first form, the second form appears correctly since $_POST['number'] is not empty. However, the content of 'number' disappears as soon as I submit it.
Then, when I submit the second form, the word "TEST" appears correctly but the form itself disappears since $_POST['number'] from the first form is now empty.
I need to find a way to somehow save the value of number in the first form so that the second form does not disappear.
Any suggestions?
You can add hidden field:
<input type="hidden" name="number" value="<?php echo $_POST['number']; ?>">
Then your second form will be changed to:
<form method="POST">
Name: <input type="text" name="name"><br>
<input type="hidden" name="number" value="<?php echo $_POST['number']; ?>">
<input type="submit" value="Submit">
</form
I'm trying to create a BMI calculator. This should allow people to use either metric or imperial measurements.
I realise that I could use hidden tags to solve my problem, but this has bugged me before so I thought I'd ask: I can use $_POST['variableName'] to find the submitted variableName field-value; but...I don't know, or see, how to verify which form was used to submit the variables.
My code's below (though I'm not sure it's strictly relevant to the question):
<?php
$bmiSubmitted = $_POST['bmiSubmitted'];
if (isset($bmiSubmitted)) {
$height = $_POST['height'];
$weight = $_POST['weight'];
$bmi = floor($weight/($height*$height));
?>
<ul id="bmi">
<li>Weight (in kilograms) is: <span><?php echo "$weight"; ?></span></li>
<li>Height (in metres) is: <span><?php echo "$height"; ?></span></li>
<li>Body mass index (BMI) is: <span><?php echo "$bmi"; ?></span></li>
</ul>
<?php
}
else {
?>
<div id="formSelector">
<ul>
<li>Metric</li>
<li>Imperial</li>
</ul>
<form name="met" id="metric" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="form/multipart">
<fieldset>
<label for="weight">Weight (<abbr title="Kilograms">kg</abbr>):</label>
<input type="text" name="weight" id="weight" />
<label for="height">Height (<abbr title="metres">m</abbr>):</label>
<input type="text" name="height" id="height" />
<input type="hidden" name="bmiSubmitted" id="bmiSubmitted" value="1" />
</fieldset>
<fieldset>
<input type="reset" id="reset" value="Clear" />
<input type="submit" id="submit" value="Submit" />
</fieldset>
</form>
<form name="imp" id="imperial" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="form/multipart">
<fieldset>
<label for="weight">Weight (<abbr title="Pounds">lbs</abbr>):</label>
<input type="text" name="weight" id="weight" />
<label for="height">Height (Inches):</label>
<input type="text" name="height" id="height" /
<input type="hidden" name="bmiSubmitted" id="bmiSubmitted" value="1" />
</fieldset>
<fieldset>
<input type="reset" id="reset" value="Clear" />
<input type="submit" id="submit" value="Submit" />
</fieldset>
</form>
<?php
}
?>
I verified that it worked (though without validation at the moment -I didn't want to crowd my question too much) with metric; I've added the form but not the processing for the imperial yet.
To identify the submitted form, you can use:
A hidden input field.
The name or value of the submit button.
The name of the form is not sent to the server as part of the POST data.
You can use code as follows:
<form name="myform" method="post" action="" enctype="multipart/form-data">
<input type="hidden" name="frmname" value=""/>
</form>
You can do it like this:
<input type="text" name="myform[login]">
<input type="password" name="myform[password]">
Check the posted values
if (isset($_POST['myform'])) {
$values = $_POST['myform'];
// $login = $values['login'];
// ...
}
The form name is not submitted. You should just add a hidden field to each form and call it a day.
In the form submitting button (id method of form is post):
<input type="submit" value="save" name="commentData">
In the PHP file:
if (isset($_POST['commentData'])){
// Code
}
For some reason, the name of the submit button is not passed to the superglobal $_POST when submitted with Ajax/jQuery.
Use a unique value on the submit button for each form like so
File index.html
<form method="post" action="bat/email.php">
<input type="text" name="firstName" placeholder="First name" required>
<input type="text" name="lastName" placeholder="Last name" required>
<button name="submit" type="submit" value="contact">Send Message</button>
</form>
<form method="post" action="bat/email.php">
<input type="text" name="firstName" placeholder="First name" required>
<input type="text" name="lastName" placeholder="Last name" required>
<button name="submit" type="submit" value="support">Send Message</button>
</form>
File email.php
<?php
if (isset($_POST["submit"])) {
switch ($_POST["submit"]) {
case "contact":
break;
case "support":
break;
default:
break;
}
}
?>
As petervandijck.com pointed out, this code may be susceptible to XSS attacks if you have it behind some kind of log-in system or have it embedded in other code.
To prevent an XSS attack, where you have written:
<?php echo "$weight"; ?>
You should write instead:
<?php echo htmlentities($weight); ?>
Which could even be better written as:
<?=htmlentities($weight); ?>
You can use GET in the form's action parameter, which I use whenever I make a login/register combined page.
For example: action="loginregister.php?whichform=loginform"
I had a similar problem which brought me to this question. I reviewed all the preceding answers, but ultimately I ending up figuring out my own solution:
<form name="ctc_form" id="ctc_form" action='' method='get'>
<input type="hidden" name="form_nm" id="form_nm">
<button type="submit" name="submit" id="submit" onclick="document.getElementById('form_nm').value=this.closest('form').name;">Submit</button>
</form>
It seamlessly and efficiently accomplishes the following:
Passes the form name attribute via a hidden input field, without using the fallible value attribute of the submit button.
Works with both GET and POST methods.
Requires no additional, independent JavaScript.
You could just give a name to the submit button and do what needs to be done based on that. I have several forms on a page and do just that. Pass the button name and then if button name = button name do something.
Only the names of the form fields are submitted, but the name of the form itself is not. But you can set a hidden field with the name in it.