i have two things to complete in my project, First thing is to hide the image path,That is done using dynamically loading the image (imageJPEG) from imageConvert.php with the parameters,The Second thing is i need to implement client side browser caching, For this i was using the
<link rel='subresource'>
before ( with normal image path ) , but it is not working with dynamic image loading. Do anybody have solution for this.
echo "<img class='lazy' src='imageConvert.php?raw=$image&cap=ps&hash=$user_id' />";
echo '<link rel="subresource" href="imageConvert.php?raw=$image&cap=ps&hash=$user_id" as="image">';
Thanks in advance.
Your image will not be cached by the browser because, as you know, it's a dynamic image being printed by a php script file.
PHP outputs cannot be cached by the browser, so if you wanna hide the image path, try to use a Rewrite condition in your htaccess to change it to another location.
Related
I'm creating a slideshow where I'm displaying images based on their urls. I've used PHP to extract the image urls from web pages and I've used JavaScript to display them in a slideshow format. Only thing is, the first picture takes a lot of time to load so I decided to cache the urls by storing them in a text file, but I don't know how to read the urls from the text file in my JavaScript bit?
Could anyone point me in the right direction as to how I should proceed. I couln't find anything helpful online.
My JS code is like this:
<script language="JavaScript1.1">
var slideimages=new Array()
slideshowimages("<?php echo join("\", \"", $image_urls); ?>") <--this is where I was initially echoing the array or image urls from php, but it proves slow for the first few images
function slideshowimages(){
for (i=0;i<slideshowimages.arguments.length;i++){
slideimages[i]=new Image()
slideimages[i].src=slideshowimages.arguments[i]
}
}
var slideshowspeed1=30000
var whichimage1=0
function slideit1(){
if (!document.images)
return
document.images.slide1.src=slideimages[whichimage1].src
if (whichimage1<slideimages.length-1)
whichimage1++
else
whichimage1=0
setTimeout("slideit1()",slideshowspeed1)}slideit1()
</script>
Thanks!
Why are you pulling from an external website? You generally will get a lot more speed if you pull them locally. I do believe that once it pulls the images once or so, it will cache for users when it shows up again. What you could do is to use that list you pull and create the images hidden on the page so they load with the page. Then when going through the slideshow, the user should have had time to cache the images and the slideshow will have sped up.
Just make a CSS class known as hidden and visability:hidden;it. Most browsers will still try to load the data.
I have limited space in my server. So, I am looking for an alternative for hooking up image URLs to my site like a product image.
What I would like to do is input an URL then load an image without refreshing the whole page.
Here is my idea:
input "any url" then submit
if url is image and existing {
display the image
}
else if (url is a non-image) or (url is image but not existing) {
display a default image
}
I tried getimagesize but it was so heavy. curl is not functioning on my server, so I am trying to do is use jQuery or JavaScript or something.
At the moment I'm using something like this:
HTML
<img src="http://www.yoursite.com/img/someimage.jpg" onerror="NoImage(this);">
Javascript part:
<script type="text/javascript">
function NoImage(p){
p.src="http://www.yoursite.com/img/nopic.gif";
}
</script>
Hope it helps
use fopen to check if that image exists u dont have to read the full content
http://www.astro.keele.ac.uk/oldusers/rno/Computing/File_magic.html
( u should restrict that possible urls cause auf bandwidth stealing from other pages - and maybe some copyright problems caused by that images )
There is an image inside HTML page. I use Jquery for 360 grad rotation. My Jquery plugin gets the list of all images via AJAX request. But the problem is, that I don't know where the user will locate scripts ang images.
For example images will be located at home/mypage/public_html/gallery/pictures/ and scripts at home/mypage/public_html/scripts/rotate/. I have an option for user to show the path to scripts and want the script to get images path automatic, based on first image path.
For example I have some image with relative path:
<img src='pictures/001.jpg'>
url is: mypage.com/gallery/pictures/001.jpg
How can I get a path to containing folder in form:
home/mypage/public_html/gallery/pictures/
It's no matter to do it with Jquery or PHP
a PHP script then loads all images from home/mypage/public_html/gallery/pictures/
Thx!
<img src='<?php echo $_SERVER['DOCUMENT_ROOT'] ?>/gallery/pictures/001.jpg'>
try this
In the end it depends on whether you process your data on the server side (PHP) or on the client side (JavaScript), but you need to use the getcwd() PHP function:
http://il.php.net/manual/en/function.getcwd.php
So you can pass the relative image path to PHP through jQuery, and then append the current working directory (getcwd) to the beginning.
How about this:
$_SERVER['DOCUMENT_ROOT'];
Path of mypage.com\ plus gallery\pictures plus Image name
I know there has to be a better way to do this.
Currently I have a php script which will generate a random image from a certain directory when called.
I have div's calling the background.php file in the stylesheet under the div's background setting
background:url(randomimagescript.php);
There are a lot of little div's on this page right now, all calling separate random image php scripts... is there a way I could use a variable when calling the file, so I can just use one script? I still need to have good styling control over the image, so i'm not sure if there is a better option than calling the script as a background image for a div.
If anyone has any ideas, let me know!
try this (it might not be optimal):
background:url("randomimagescript.php?folder=myfolder");
and in randomimagescript.php:
<?php
$folder = #_$REQUEST['folder'];
$url = "galleries/$folder/thumbs/image.jpg"; // ie, compose image
http_redirect($url); // go and find the image.
?>
It sounds a little crazy, but you could actually make your stylesheet be generated by PHP, and just fill in the blank, so to speak.
background:url(<? echo pickRandomImage(); ?>)
set the background for all divs once on the page using jquery
var image = <?echo randomimagescript.php?>
$("div").css('background', 'url('+ image+ ')');
I have some thumbnail images with its larger version.I placed the thumbnail images in a page.Now for link I just gave a link
<img src="thumbnail1.jpg>
but for this I have to make different pages for showing larger one.I want to give a link to show them in a single page.means whenever I will click the thumbnail it will open the larger one in a page with the same url but with its name like
imagegallery.php?news=images/largerimage1/13.jpg
imagegallery.php?news=images/largerimage1/14.jpg
so how to do that?
Pretty basic stuff, I suggest you get to read some PHP tutorials on the internet to get some knowledge on one thing and another.
The ?news= part in your URL is a parameter that can be read by PHP. This type is known as $_GET. To get this part you would need $_GET['news'] so if we'd use your first link and place this inside a script: echo $_GET['news']; the page would say images/largerimages1/13.jpg.
In order to get the image loaded on your website we need some simple steps, I'm changing the news parameter into image, that suits better for your script since it ain't news items:
<?php
// Define the path (used to see if an image exists)
$path = 'your/absolute/path/to/public_html/'; # or wwwroot or www folder
// First check if the parameter is not empty
if($_GET['image'] != "") {
// Then check if the file is valid
if(file_exists($path . $_GET['image'])) {
// If an image exists then display image
echo '<img src="'. $_GET['image'] . '" />;
}
}
?>
Below this script you can put all your thumbnails the way you want. Ofcourse, also for these thumbnails there are some automated options. But I strongly suggest you get a good look at the script above and some beginner PHP tutorials so you completely understand the example given. This still isn't the best method, but it's kicking you in the right direction.
if your imagegallery.php is in root of your domain, you can just add slash as a first char to links like this:
<img src="thumbnail1.jpg>
else you will have to write some php function which it returns BaseUrl of your web. Then it should looks like this:
<img src="thumbnail1.jpg>
maybe you can something like this,
Techincally, there is no thumbnail image, just a stretch version of the regular image
I don't understand which part you don't know how to do:
- the link part?
it should look like
<img src="thumbnail1.jpg>
- or the PHP part (the file called imagegallery.php)?