I am trying to get the Total Sum of values from a table. Query works without WHERE Clause, but i need to get the total sum per user. Like user ABC has 100USD and user BDC has 200USD. Here is the code
$PWithdrawls = mysqli_query($con, "SELECT * FROM withdraw WHERE status='Pending'");
$S_NO = 0;
while ($row = mysqli_fetch_assoc($PWithdrawls)) {
$S_NO++;
$posted_by = mysqli_query($con,"SELECT * FROM users WHERE userId=".$row['seller_id']);
$user_ad = mysqli_fetch_assoc($posted_by);
$TotalOrders_Amount = mysqli_query($con, "SELECT SUM(amount) as total FROM orders WHERE userId=".$row['seller_id']);
$sum_amount = mysqli_fetch_assoc($TotalOrders_Amount);
$sum = $sum_amount['total'];
And here is my call
<td>$<?php echo $sum; ?></td>
Here is DB
Think you have error in your SQL Query:
SELECT SUM(amount) as total FROM orders WHERE userId=".$row['seller_id'] GROUP BY userId LIMIT 1
You need to use GROUP BY to get actual SUM. Also you can get all users with Total, there is no need to second query:
SELECT u.*, SUM(o.amount) AS total
FROM users u
LEFT JOIN orders o ON (o.userId = u.id)
GROUP BY u.userId
This should get you entire user row + total of their orders.
I found the issue. I was calling the wrong variable. userId was not in my table, it was seller_id. So correct query was
$TotalOrders_Amount = mysqli_query($con, "SELECT SUM(amount) as total FROM orders WHERE seller_id=".$row['seller_id']);
Thanks to everyone. I really appreciate.
Related
At the moment I'm able to count all the record's in a table with the value "Waiting". This is done by using:
$query = "SELECT COUNT(*) AS SUM FROM jobs WHERE status='Waiting'";
When I want to echo the row count I just do:
echo $rows['SUM'];
How can I do it so it also count's all the record's in a table with the value "Ready"?
This query will return all status count divided by status:
SELECT status, COUNT(status) AS tot FROM jobs GROUP BY status
The resulting set is something like this:
status tot
----------- ------
Waiting 123
Ready 80
... 56
So you want status='Waiting' or status='Ready'? You can separate parameters with OR or AND; for example:
$query = "SELECT COUNT(*) AS SUM FROM jobs WHERE status='Waiting' OR status='Ready'";
SELECT count(status) AS 'count' FROM jobs GROUP BY status HAVING status='Ready'
This will count the records with the status = Ready. You use GROUP BY to get an aggregate on the status field. And because you have used GROUP BY, you use HAVING (which is the equivalent of WHERE in GROUP situations) to filter the data.
By using IN operator in your query.
$query = "SELECT COUNT(*) AS SUM FROM jobs WHERE status IN ('Waiting','Ready')";
Get group based(status) counts by using GROUP BY operator
$query = "SELECT COUNT(*) AS SUM FROM jobs GROUP BY status";
Print the status based result.
//Create the `mysqli_connection` and assign to `$conn` variable.
$result = mysqli_query($conn, $query);
if($result->num_rows>0)
{
while($row = mysqli_fetch_assoc($result))
{
echo "<br>status=" . $row['status'];
echo "<br>SUM=" . $row['SUM'];
}
}
$users = mysql_query("SELECT *, COUNT(votes.id) FROM users INNER JOIN votes
ON users.id=votes.recipientuserid WHERE votes.datenumber >='2014' ");
while($user = mysql_fetch_array($users)){
$count = $user[COUNT(votes.id)];
}
In phpmyadmin the query count displays a number. The value of $count is not a number but the users.username value. Why?
One way to accomplish what you want is to modify your query by adding a field name to count so that you can access it as any other field in the results:
SELECT *, COUNT(votes.id) as nbvotes FROM users ...
And the from php once you have the results, you can access it this way
$row['nbvotes']
where $row is the variable containing the record returned from mysql. Do not forget the appostrophes.
Cheers
$users = mysql_query("SELECT COUNT(votes.id) as count FROM users INNER JOIN votes
ON users.id=votes.recipientuserid WHERE votes.datenumber >='2014' ");
while($user = mysql_fetch_array($users)){
$count = $user['count'];
}
Thanks for helping, first I will show code:
$dotaz = "Select * from customers JOIN contracts where customers.user_id ='".$_SESSION['user_id']."' and contracts.customer_contract = ".$_SESSION['user_id']." order by COUNT(contracts.customer_contract) DESC limit $limit, $pocetZaznamu ";
I need to get the lists of users (customers table) ordered by count of contracts(contracts table)
I tried to solve this by searching over there, but I can't... if you help me please and explain how it works, thank you! :) $pocetZanamu is Number of records.
I need get users (name, surname etc...) from table customers, ordered by number of contracts in contracts table, where is contract_id, customer_contract (user id)..
This should do it where is the column name you are counting.
$id = $_SESSION['user_id'] ;
$dotaz = "Select COUNT(`customer_contract`) AS CNT, `customer_contract` FROM `contracts` WHERE `user_id`=$id GROUP BY `customer_contract` ORDER BY `CNT` DESC";
Depending on what you are doing you may want to store the results in an array, then process each element in the array separately.
while ($row = mysqli_fetch_array($results, MYSQL_NUM)){
$contracts[$row[1]] = $row[0];
}
foreach ($contracts AS $customer_contract => $count){
Process each user id code here
}
Not sure what you are counting. The above counts the customer_contract for a table with multiple records containing the same value in the customer_contract column.
If you just want the total number of records with the same user_id then you'd use:
$dotaz = "Select 1 FROM `contracts` WHERE `user_id`=$id";
$results = $mysqli->query($dotaz);
$count = mysql_num_rows($results);
I have this query which gives me the transactions for a user, and the output is a table with the information. There is this row named basket_value which contains some numbers, and I need to get the sum of those numbers. Could you please help me?
$query3 = 'SELECT users.first_name,users.last_name,users.phone,
retailer.date, SUM(retailer.basket_value),
retailer.time,retailer.location,retailer.type_of_payment
FROM users ,retailer
WHERE users.user_id="'.$id_user.'"
AND users.user_id=retailer.user_id GROUP BY users.user_id';
$result3 = mysql_query($query) or die(mysql_error());
// Print out result
while($row = mysql_fetch_array($result3)) {
echo "Total ". $row['user_id']. " = $". $row['SUM(basket_value)'];
echo "<br />";
}
I suppose that also your query have some problem and suppose that you have an id to retrieve users, I would do in that way
$query3 = 'SELECT users.user_id,users.first_name,users.last_name,
users.phone, retailer.date,
SUM(retailer.basket_value) as total_sum,
retailer.time,retailer.location,retailer.type_of_payment
FROM users ,retailer WHERE users.user_id="'.$id_user.'"
AND users.user_id=retailer.user_id
GROUP BY users.user_id,users.first_name,users.last_name,
users.phone, retailer.date,retailer.time,retailer.location,
retailer.type_of_payment '
$result = $mysqli->query($query3);
Now if you want the sum for each user:
while ($row = $result->fetch_row()) {
echo "Player: ".$row['user_id']." total: ".$row['total_sum'];
}
If you want the WHOLE GLOBAL sum, you have to way:
Modify your query in that way:
SELECT SUM(retailer.basket_value) as total_sum
FROM retailer
Sum into while loop like: $total += $row['total_sum'];
You're missing a GROUP BY on your query. You most likely want to add GROUP BY users.user_id
Try this query:
SELECT u.first_name, u.last_name, u.phone, SUM(r.basket_value) as total_sum
FROM users u
JOIN retailers r
ON u.user_id = r.user_id
WHERE u.user_id="'.$id_user.'"
GROUP BY u.user_id
You can omit all other columns in the select list and only have the sum() aggregate run on the set to avoid the GROUP BY clause.
$query3 = 'SELECT SUM(retailer.basket_value) as total_sum
FROM users ,retailer WHERE users.user_id="'.$id_user.'"
AND users.user_id=retailer.user_id';
$sql = "SELECT * FROM books LEFT JOIN users
ON books.readby=users.user_id WHERE users.email IS NOT NULL";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo $row['readby']. " - read 10 books";
} //while ends
this is the code I have so far. I am trying to retrieve the number of books read by each user
and echo the results. echo the user_id and number of books he/she read
books table is like this : id - name - pages - readby
the row readby contains the user id.any ideas/suggestions? I was thinking about using count() but Im not sure how to go about doing that.
A subquery can return the count of books read per user. That is left-joined back against the main table to retrieve the other columns about each user.
Edit The GROUP BY had been omitted...
SELECT
users.*,
usersread.numread
FROM
users
/* join all user details against count of books read */
LEFT JOIN (
/* Retrieve user_id (via readby) and count from the books table */
SELECT
readby,
COUNT(*) AS numread
FROM books
GROUP BY readby
) usersread ON users.user_id = usersread.readby
In your PHP then, you can retrieve $row['numread'] after fetching the result.
// Assuming you already executed the query above and checked errors...
while($row = mysql_fetch_array($result))
{
// don't know the contents of your users table, but assuming there's a
// users.name column I used 'name' here...
echo "{$row['name']} read {$row['numread']} books.";
}
You can use count() this way:
<?php
$count = mysql_fetch_array(mysql_query("SELECT COUNT(`user_id`) FROM books LEFT JOIN users ON books.readby=users.user_id WHERE users.email IS NOT NULL GROUP BY `user_id`"));
$count = $count[0];
?>
Hope this helps! :)