$output["data"] = array();
// after fetching data form db
while($row = $stmt->fetch()){
$output["data"][] = [
$row['inventory_order_id'],
$row['inventory_order_name'],
$row['inventory_order_total'],
$row['inventory_order_date'],
];
if(($_SESSION['user_type'] == 'user'){
$output['data'][] = 'user';
}
}// end while loop
and gives this result:
{"data":[[1,"1","Hina","10000.00","2021-01-11 15:01:54"],"user"]}
but i need result like following:
{"data":[[1,"1","Hina","10000.00","2021-01-11 15:01:54","user"]]}
user should be in same array
You need to define a reuse the same key. In your current code new key for user is used.
$i = 0;
while($row = $stmt->fetch()){
$output["data"][$i] = [
$row['inventory_order_id'],
$row['inventory_order_name'],
$row['inventory_order_total'],
$row['inventory_order_date'],
];
if (($_SESSION['user_type'] == 'user')) {
$output['data'][$i] = 'user';
}
$i++;
}
Related
function practise()
{
$this->load->database();
$qry = mysql_query("select * from demmo");
if (mysql_num_rows($qry) > 0)
{
while ($row = mysql_fetch_array($qry))
{
$created = $row['created'];
//from here
$qry = mysql_query("select * from demmo where created = '$created'");
while ($res = mysql_fetch_array($qry))
{
$user_id = $res['id'];
$name = $res['name'];
$created2 = $res['created'];
$users[] = array('user_id' => $user_id, 'name' => $name);
}
$dotts[] = array('created' => $created2);
//till here
}
return array ($dotts,$users);
}
}
in demmo table i am trying to fetch data and showing that data according to date .the problem is that the code is only selecting one date from the table from created rows and showing that data only .fortunately data shown is not only last but the data with actual date.
You need to create an array and use array_push to get more than one result. Right now your code is only returning the last result of the while loop:
For example, to get all of the dates:
$dotts = array();
$allusers = array();
while ($res = mysql_fetch_array($qry))
{
$user_id = $res['id'];
$name = $res['name'];
$created2 = $res['created'];
array_push($dotts, $created2);
$users[] = array('user_id' => $user_id, 'name' => $name);
array_push($allusers, $users);
}
//
return array ($dotts,$allusers);
You need to create an array and use array_push function , then only it will have more than one value.
example:
create an empty array as
$allUser = array();
then after this line
$users[] = array('user_id' => $user_id, 'name' => $name);
use array_push as
array_push($allUser, $users);
}
return array($dots, $allUser);
I'm trying to create a single array of status id's and their names pulled from the database. My array needs to come out looking like this
$options = array("1" => "Active", "2" => "Inactive");
I've been trying to use array_push and array merge but it keeps going wrong. Here is what I have so far...
$allStatus = implode(',', array('1', '2'));
$statuses = $clCont->getAllRecords('*', '`status` WHERE idstatus IN ('.$allStatus.')');
$status = mysqli_fetch_assoc($statuses);
$statusOpt = array();
do
{
array_push($statusOpt[$status['idstatus']],$status['statusName']);
}
while ($status = mysqli_fetch_assoc($statuses));
$rows = mysqli_num_rows($statuses);
if($rows > 0)
{
mysqli_data_seek($statuses, 0);
$status = mysqli_fetch_assoc($statuses);
}
print_r($statusOpt);
Ok, let's try to modify your code:
$allStatus = implode(',', array('1', '2'));
$statuses = $clCont->getAllRecords('*', '`status` WHERE idstatus IN ('.$allStatus.')');
// you don't need to fetch first item.
// $status = mysqli_fetch_assoc($statuses);
// and use a do-while loop
// use just while:
$statusOpt = array();
while ($status = mysqli_fetch_assoc($statuses))
{
$id = $status['idstatus'];
// The first time you try to put a value in a
// $statusOpt[$status['idstatus']] it's not exists,
// so you should define it explicitly:
if (!isset($statusOpt[$id])) {
$statusOpt[$id] = array();
}
// after that it should be okay:
array_push($statusOpt[$id],$status['statusName']);
}
print_r($statusOpt);
In a project, I have to return user_id, user_age from the database and the return format should be like
user object which contains user_id and user_age
average age of users
count of users
the return format should be in JSON format.
I have created user array and encoded to JSON by using the method
json_encode(user);
my code is like this :
while ($row = mysql_fetch_array($result)) {
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
array_push($response, $user);
$count = $count+1;
$sum_of_age = $sum_of_age+$row["age_of_user"];
}
echo json_encode($response);
I have calculated the average age ($sum_of_age/$count) and count of returned users ($count), but I don't know how to return average age and count of users with the same json response.any help will be appreciated.
You can do like this:
$count=0;
$sum_of_age=0;
$response=array();
$response['users']=array();
while ($row = mysql_fetch_array($result)) {
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
array_push($response['users'], $user);
$count = $count+1;
$sum_of_age = $sum_of_age+$row["age_of_user"];
}
$response['count']=$count;
$response['avg']=$sum_of_age/$count;
echo json_encode($response);
You can try this:
$users = array();
$sum_of_age = 0;
$count = 0;
$users = array();
while ($row = mysql_fetch_array($result))
{
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
$users[] = $user;
$count++;
$sum_of_age += (int) $row["age_of_user"];
}
$response = array(
'users' => $users,
'averageAge' => $sum_of_age/$count,
'count' => $count
);
echo json_encode($response);
This should result in the following json response:
{
"users":[
{ "id" : "1", "name" : "John Doe" , "date" : "2014-03-22 15:20" , "age" : 42 },
{...},
...
],
"averageAge": 42,
"count": 1337
}
<?php
$response = array();
while ($row = mysql_fetch_array($result)) {
$user["id"] = $row["id"];
$user["name"] = ucfirst($row["user_name"]);
$user["date"] = $row["date_of_treatment"];
$user["age"] = $row["age_of_user"];
// push single user into final response array
array_push($response, $user);
$count = $count+1;
$sum_of_age = $sum_of_age+$row["age_of_user"];
}
$response["average_age"] = $sum_of_age / $count;
$response["count"] = $count;
echo json_encode($response);
}
This is the answer, thanks #Amal Murali (commented a link), the link you have provided is working.. :-)
I store the field names within an array, in hopes to dynamically create the variables.
I receive a illegal offset type error for the if and else, these two lines:
$data[$tmp_field] = $tmp_field[$id];
$data[$tmp_field] = 0;
I checked the post data and it is posting with the appropriate data, but I am not sure what the problem is.
$student_id stores all the students ids., for example: $student_id = array(8,9,11,23,30,42,55);
function updateStudentInfo() {
$student_id = $this->input->post('student_id');
$internet_student = $this->input->post('internet_student');
$dismissed = $this->input->post('dismissed');
$non_matriculated_student = $this->input->post('non_matriculated_student');
$felony = $this->input->post('felony');
$probation = $this->input->post('probation');
$h_number = $this->input->post('h_number');
$office_direct_to = $this->input->post('office_direct_to');
$holds = $this->input->post('holds');
$fields = array('internet_student', 'non_matriculated_student', 'h_number', 'felony', 'probation', 'dismissed');
foreach($student_id as $id):
$data = array();
foreach($fields as $field_name):
$tmp_field = ${$field_name};
if(empty($tmp_field[$id])) {
$data[$tmp_field] = 0;
} else {
$data[$tmp_field] = $tmp_field[$id];
}
endforeach;
print '<pre style="color:#fff;">';
print_r($data);
print '</pre>';
endforeach;
}
This is the array format I desire:
Array
(
[internet_student] => 1
[non_matriculated_student] => 1
[h_number] => 0
[felony] => 0
[probation] => 1
[dismissed] => 0
)
Added screenshot to give you a visual of the form the data is being posted from
foreach($student_id as $id):
$data = array();
foreach($fields as $field_name):
$tmp_field = ${$field_name};
if(empty($tmp_field[$id])) {
$data[$field_name] = 0;
} else {
$data[$field_name] = $tmp_field[$id];
}
endforeach;
print '<pre style="color:#fff;">';
print_r($data);
print '</pre>';
endforeach;
I am assuming that all these fields are arrays, as otherwise you wouldn't need any loops.
function updateStudentInfo()
{
$student_id = $this->input->post('student_id');
$internet_student = $this->input->post('internet_student');
$dismissed = $this->input->post('dismissed');
$non_matriculated_student = $this->input->post('non_matriculated_student');
$felony = $this->input->post('felony');
$probation = $this->input->post('probation');
$h_number = $this->input->post('h_number');
$office_direct_to = $this->input->post('office_direct_to');
$holds = $this->input->post('holds');
$fields = array('internet_student', 'non_matriculated_student', 'h_number', 'felony', 'probation', 'dismissed');
$student_count = count($student_id);
foreach($student_id as $id)
{
$data = array();
foreach($fields as $field)
{
if(array_key_exists($id, $$field))
$data[$field] = ${$field}[$id];
}
}
}
You are trying to use the student id as an array key for the other fields but the HTML form is just a standard indexed array, not keyed to any student data.
I want to add an additional value into an array before passing it to json_encode function,
but I can't get the syntax right.
$result = db_query($query);
// $row is a database query result resource
while ($row = db_fetch_object($result)) {
$stack[] = $row;
// I am trying to 'inject' array element here
$stack[]['x'] = "test";
}
echo json_encode($stack);
If it's an array you can directly add a value:
$row['x'] = 'test';
$stack[] = $row;
if it's an object you can add another property:
$row->x = 'test';
$stack[] = $row;
if you want to keep the object and the extra value separated:
$data = array($row, 'x' => 'test');
$stack[] = $data;
but this does work.
$stack[] = $row;
$row->x = 'test';
How about something like:
$row['x'] = 'test';
$stack = $row;