Mysql/PHP Json nested array - php

I got issue with nested array which seems are not Json object for some reason. When i try for e.g access jsonData["user"] it works, but when i try go deeper such as jsonData["user"]["photo_url"] then it's treated like a string and i cant access the value.
Current code:
<?php
require_once("db_connection.php");
$userId = $_GET["user_id"];
$query = "WITH user AS (SELECT id, JSON_OBJECT('display_name', u.display_name, 'photo_url', u.photo_url) AS user FROM users u WHERE id = :userId), info AS (SELECT id, JSON_ARRAYAGG(JSON_OBJECT('text', text, 'start_at', start_at, 'end_at', end_at, 'status', status)) AS information FROM report GROUP BY id), img AS (SELECT report_id, JSON_ARRAYAGG(JSON_OBJECT('name', name)) AS images FROM report_images GROUP BY report_id), cmt AS (SELECT report_id, COUNT(*) AS totalcomments FROM report_comments rc JOIN users u ON rc.user_id = u.id GROUP BY report_id) SELECT u.user, info.information, img.images, cmt.totalcomments FROM report r JOIN user u ON u.id = r.user_id LEFT JOIN info ON info.id = r.id LEFT JOIN img ON img.report_id = r.id LEFT JOIN cmt ON cmt.report_id = r.id";
$stmt = $db->prepare($query);
// Bind our variables.
$stmt->bindValue(":userId", $userId);
// Execute.
$stmt->execute();
$result = $stmt->fetchAll();
if (count($result) > 0) {
$toJson = json_encode($result);
echo $toJson;
} else {
$toJson = json_encode("Error");
echo $toJson;
}
?>
Old code which worked:
<?php
require_once("db_connection.php");
require_once("functions.php");
$userId = $_GET["user_id"];
$query = "SELECT * FROM report WHERE `user_id` = :userId";
$stmt = $db->prepare($query);
// Bind our variables.
$stmt->bindValue(":userId", $userId);
// Execute.
$stmt->execute();
$result = $stmt->fetchAll();
if (count($result) > 0) {
foreach ($result as $key => $value) {
$result[$key]["user"] = getUserById($db, $value["user_id"]);
}
$toJson = json_encode($result);
echo $toJson;
} else {
$toJson = json_encode("Error");
echo $toJson;
}
?>

Because you are aggregating some of the values as JSON in your query, you need to decode those first before attempting to use the values and then JSON encode the whole result set. You need to do that as you fetch the data, so replace:
$result = $stmt->fetchAll();
with:
$result = array();
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
$row['user'] = json_decode($row['user']);
$row['images'] = json_decode($row['images']);
$row['comments'] = json_decode($row['comments']);
$result[] = $row;
}

Related

MySQL - Join part of query to a new query?

I've got the following code which queries a table. Then it uses the result to make another query. That result is then used to make a third query.
But how do I grab the userid field from the 2nd query in order to grab a name from a users table and join that to the result of the 3rd query?
Please note once I figure out the code I will convert this to a prepared statement. It's just easier for me to work with legacy code when figuring out queries.
$selectaudioid = "SELECT audioid FROM subscribe WHERE userid = $userid";
$audioResult=$dblink->query($selectaudioid);
if ($audioResult->num_rows>0) {
while ($row = $audioResult->fetch_assoc()) {
$newaudio = $row[audioid];
$getallaudio = "SELECT opid, userid from audioposts WHERE audioid = $newaudio" ;
$getallresult = $dblink->query($getallaudio);
if ($getallresult->num_rows>0) {
while ($row = $getallresult->fetch_assoc()) {
$opid = $row[opid];
$opuserid = $row[userid];
$getreplies =
"SELECT * from audioposts ap WHERE opid = $opid AND opid
NOT IN (SELECT opid FROM audioposts WHERE audioposts.opid = '0' )";
$getreplyresults = $dblink->query($getreplies);
if ($getreplyresults->num_rows>0) {
while ($row = $getreplyresults->fetch_assoc()) {
$dbdata[]=$row;
}
}
}
}
}
} "SELECT * from audioposts ap WHERE opid = $opid AND opid
NOT IN (SELECT opid FROM audioposts WHERE audioposts.opid = '0' )";
$getreplyresults = $dblink->query($getreplies);
if ($getreplyresults->num_rows>0) {
while ($row = $getreplyresults->fetch_assoc()) {
$dbdata[]=$row;
}
}
}
}
}
}
echo json_encode($dbdata);
The result I need are rows of json encoded instances of $getreplyresults with the $row[userid] from the original result joined to each row.
Here's what I did in the end. Now I just have to figure out how to convert this to a prepared statement in order to avoid malicious injection.
$selectaudioid = "SELECT audioid FROM subscribe WHERE userid = $userid";
$audioResult=$dblink->query($selectaudioid);
if ($audioResult->num_rows>0) {
while ($row = $audioResult->fetch_assoc()) {
$newaudio = $row[audioid];
$getallaudio = "
SELECT ap.audioid, ap.title, us.name FROM audioposts ap
INNER JOIN audioposts a2 ON a2.audioid = ap.opid
INNER JOIN users us ON us.id = a2.userid
WHERE ap.opid = $newaudio AND ap.opid <> '0'
";
$getallresult = $dblink->query($getallaudio);
if ($getallresult->num_rows>0) {
while ($row = $getallresult->fetch_assoc()) {
$dbdata[]=$row;
}}}}

How to nest 2 SQL statements with a foreach loop inside each other

Okay I try with the first query to get all names of the computers from the table psComputers. Now I need in the second query a variable from the first query to iterate over all entries which are assigned to the respective computer in the table psTest. I wonder if such a thing is possible at all?
Table psComputer contains ID, name
Table psTest contains ID, computername, category, value
index.php
$statement = $pdo->prepare("SELECT * FROM psComputers ");
$statement->execute();
$result = $statement->fetchAll();
if ($statement->rowCount() > 0) {
foreach ($statement->fetchAll() as $row) {
$id = $row['ID'];
$name = $row['name'];
$statement2 = $pdo->prepare("SELECT * FROM psTest WHERE computerName = $name");
$statement2->execute();
$result2 = $statement2->fetchAll();
if ($statement2->rowCount() > 0) {
foreach ($statement2->fetchAll() as $row2) {
$id2 = $row2['ID'];
$computerName = $row2['computerName'];
$category = $row2['category'];
$value = $row2['value'];
}
}
}
}
You need quotes around $name in the second query, since it's a string.
$statement2 = $pdo->prepare("SELECT * FROM psTest WHERE computerName = '$name'");
But since you're using a prepared query, you should use a parameter instead of substituting a variable.
You also shouldn't call $statement->fetchAll() twice. The first call will read all the rows, and the second won't have anything left to read (it doesn't reset the cursor).
$statement = $pdo->prepare("SELECT * FROM psComputers ");
$statement->execute();
$result = $statement->fetchAll();
if (count($result) > 0) {
$statement2 = $pdo->prepare("SELECT * FROM psTest WHERE computerName = :name");
$statement2->bindParam(':name', $name);
foreach ($result as $row) {
$id = $row['ID'];
$name = $row['name'];
$statement2->execute();
$result2 = $statement2->fetchAll();
if (count($result2) > 0) {
foreach ($result2 as $row2) {
$id2 = $row2['ID'];
$computerName = $row2['computerName'];
$category = $row2['category'];
$value = $row2['value'];
}
}
}
}
But even better is to just join the two queries:
$statement = $pdo->prepare("
SELECT c.id AS computerID, c.name AS computerName, t.id AS testID, t.category, t.value
FROM psComputers AS c
JOIN psTest AS t ON c.name = t.computerName
ORDER BY c.id");
A couple things to note,
When using strings in queries, they must be quoted.
You are already preparing the statement - bind the value instead, and the note above becomes irrelevant.
You can use a JOIN instead of running a query in a loop. This will also remove the variable in the name, making both notes above irrelevant! (You should take note of both, but they become irrelevant for the code in question).
Its rarely a good idea to run a query within a loop.
$statement = $pdo->prepare("SELECT pt.*
FROM psTest pt
JOIN psComputers pc ON pt.computerName=pc.name");
$statement->execute();
$result = $statement->fetchAll();
if (count($result)) {
foreach ($result as $row) {
$id2 = $row['ID'];
$computerName = $row['computerName'];
$category = $row['category'];
$value = $row['value'];
}
}

Looping a query from previous result in mysql

I have two tables, user and leads. My goal is to find users with leads having status 'completed' and 'idle', after that use that result to get all the leads for that user. Here is my query
$sql = "SELECT u.id FROM users u LEFT JOIN leads l ON u.id = l.user_id WHERE l.status IN('completed', 'idle')";
...
$result = $stmt->fetchAll();
...
$usersleads = array();
foreach ($result as $userId) {
$sql = "SELECT * FROM leads where user_id = ". $userId;
...
$results = $stmt->fetchAll();
foreach ($results as $ul) {
array_push($usersleads, $row);
}
}
This works for small results. But if data gets bigger this just crashed and I can understand it. I am looking for a more efficient way to query the db.
UPDATE
I think I have found a solution. Now only has two queries over all.
$sql = "SELECT u.id FROM users u LEFT JOIN leads l ON u.id = l.user_id WHERE l.status IN('completed', 'idle')";
...
$userResult = $stmt->fetchAll();
...
$userIds = [];
foreach ($userResult as $user) {
$userIds[] = $user['id'];
}
$sql = "SELECT * FROM leads where user_id IN('" . implode("','", $userIds) ."')";
...
$leadsResult = $stmt->fetchAll();
...
foreach ($userResult as &$lead) {
$lead['date'] = $this->getDateForLead($lead['id'], $leadsResult);
// add other fields to $userResult
}
...
public function getDateForLead($leadId, $leads)
{
foreach($leads as $lead) {
if ($leadId = $lead['id']) {
return $lead['date'];
}
}
return null;
}

Results not showing after converting PDO query to mySQLi

I have a script to extract data from two tables matieres and sous_matieres but it's written for PDO, I need it to work for mySQLi:
$stmt = $pdo->query('SELECT
m.id AS m_id, m.url AS m_url, m.title AS m_title,
s.id AS s_id, s.url AS s_url, s.title AS s_title
FROM matieres m
INNER JOIN sous_matieres s ON m.url = s.parent');
while ($row = $stmt->fetchObject()) {
$matieres[$row->m_id]['url'] = $row->m_url;
$matieres[$row->m_id]['title'] = $row->m_title;
$matieres[$row->m_id]['sous_matieres'][$row->s_id] = $row;
}
foreach ($matieres as $m_id => $matiere) {
echo "<h2>$matiere[title]</h2>";
foreach ($matiere['sous_matieres'] as $id => $sm) {
echo "<div>
<a href='{$sm->s_url}'>{$sm->s_title}</a>
</div>";
}
}
My new mySQLi code that shows nothing despite the two tables have data:
$query = 'SELECT
m.id AS m_id, m.url AS m_url, m.title AS m_title,
s.id AS s_id, s.url AS s_url, s.title AS s_title
FROM matieres m
INNER JOIN sous_matieres s ON m.url = s.parent';
$stmt = $mysqli->query($query);
$stmt->execute();
$stmt->store_result();
while ($row = $stmt->fetch()) {
$matieres[$row->m_id]['url'] = $row->m_url;
$matieres[$row->m_id]['title'] = $row->m_title;
$matieres[$row->m_id]['sous_matieres'][$row->s_id] = $row;
}
foreach ($matieres as $m_id => $matiere) {
echo "<h2>$matiere[title]</h2>";
foreach ($matiere['sous_matieres'] as $id => $sm) {
echo "<div>
<a href='{$sm->s_url}'>{$sm->s_title}</a>
</div>";
}
}
I don't know if it's missing $stmt->bind_result() and the variable inside. As for normal mySQLi queries (without joins) I have to declare the selected column names as variable inside the $stmt->bind_result()
mysqli_stmt::fetch is used when you bind variables to results on a prepared statement, to populate those variables. The alternative method of getting the results is to use the mysqli_result class, which you can use the way you're trying to:
$result = $mysqli->query($query);
while ($row = $result->fetch_object()) {
$matieres[$row->m_id]['url'] = $row->m_url;
$matieres[$row->m_id]['title'] = $row->m_title;
$matieres[$row->m_id]['sous_matieres'][$row->s_id] = $row;
}
See http://php.net/manual/en/mysqli.query.php and http://php.net/manual/en/class.mysqli-result.php.

Alternate query using if statement in PHP

I'm trying to run an alternate query if the initial query fails (it does because the id I'm searching for in this instance only exists in one of the databases being joined) using an if statement and I've constructed it like so:
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/php/link_costreport_2013.php');
$id = $_GET['id']; //ID # For page/query
if($query = $link->prepare("SELECT locale.id, locale.provider_num, locale.provider_name, locale.state, locale.city,
finstat_ca.coh_and_banks, finstat_ca.temp_investments, finstat_ca.notes_receivable, finstat_ca.accounts_receivable, finstat_ca.other_receivables,
finstat_ca.afun_and_ar, finstat_ca.inventory, finstat_ca.prepaid_expenses, (finstat_ca.other_cur_assets + finstat_ca.due_from_other_funds) as other_cur_assets, finstat_ca.total_current_assets,
finstat_fa.total_fixed_assets,
finstat_olta.investments, (finstat_olta.dep_on_leases + finstat_olta.due_from_owners_officers + finstat_olta.other_assets) as all_olta, finstat_olta.total_other_assets, finstat_olta.end_assets,
finstat_cl.accounts_payable, finstat_cl.salaries_wages_fees_payable, finstat_cl.payroll_taxes_payable, finstat_cl.notes_loans_payable, finstat_cl.deferred_income, finstat_cl.total_current_liabilities,
(finstat_cl.total_current_liabilities - (finstat_cl.accounts_payable + finstat_cl.salaries_wages_fees_payable + finstat_cl.payroll_taxes_payable + finstat_cl.notes_loans_payable + finstat_cl.deferred_income)) as all_other_cl,
finstat_ltl.mortgage_payable, finstat_ltl.notes_payable, finstat_ltl.unsecured_loans, finstat_ltl.other_long_term_liabilities, finstat_ltl.total_long_term_liabilities,
finstat_talfb.total_fund_balance, finstat_talfb.total_lia_plus_fb
FROM `locale`
INNER JOIN `finstat_ca`
ON locale.id = finstat_ca.id
INNER JOIN `finstat_fa`
ON locale.id = finstat_fa.id
INNER JOIN `finstat_olta`
ON locale.id = finstat_olta.id
INNER JOIN `finstat_cl`
ON locale.id = finstat_cl.id
INNER JOIN `finstat_ltl`
ON locale.id = finstat_ltl.id
INNER JOIN `finstat_talfb`
ON locale.id = finstat_talfb.id
WHERE locale.id = :id
LIMIT 1")){
} else {
$query = $link->prepare("SELECT id, provider_num, provider_name, state, city
FROM `locale`
WHERE id = :id
LIMIT 1");
}
$query->bindParam(':id', $id);
$query->execute();
$results = $query->fetch(PDO::FETCH_ASSOC);
echo json_encode($results);
Basically it defaults to the single table where the ID does exist and only pulls a couple fields as opposed to the large statement above it. My only issue is that my code here is not working. My JSON only says false when I echo it. It obviously should not.
Is there an error in my code here?
Thanks in advance
:edit: I should note that when I enter an ID that exists in all the tables joined, the correct result (json) is displayed on the page.
I believe the problem is that even if ID does not exist in the first query, the $query variable still has a proper query in it and there is nothing false about it. That's not what you should be if-testing.
I think you should be testing $results.
This shows you the logic.
<?php
require_once($_SERVER['DOCUMENT_ROOT'] . '/php/link_costreport_2013.php');
//ID # For page/query
$id = $_GET['id'];
$sql_1 = "SQL CODE FOR QUERY 1";
$sql_2 = "SQL CODE FOR QUERY 2";
$query = $link->prepare($sql_1);
$query->bindParam(':id', $id);
$query->execute();
$results = $query->fetch(PDO::FETCH_ASSOC);
if (!$results)
{
$query = $link->prepare($sql_2);
$query->bindParam(':id', $id);
$query->execute();
$results = $query->fetch(PDO::FETCH_ASSOC);
}
echo json_encode($results);
However as you can see there are a few lines of code that are repeated inside the if-statement that very similar to code that was just before the if-statement. Perhaps with a loop that loops twice but breaks out if $results is not false would be neater.
<?php
require_once($_SERVER['DOCUMENT_ROOT'] . '/php/link_costreport_2013.php');
//ID # For page/query
$id = $_GET['id'];
$sql[] = "SQL CODE FOR QUERY 1";
$sql[] = "SQL CODE FOR QUERY 2";
foreach ($sql as $sql_query)
{
$query = $link->prepare($sql_query);
$query->bindParam(':id', $id);
$query->execute();
$results = $query->fetch(PDO::FETCH_ASSOC);
if ($results)
{
break;
}
}
echo json_encode($results);
The world is your oyster.

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