I am using PHP-Imagick to convert a PDF into images, which works fine.
A simplified example:
$im = new imagick();
$im->setResolution(250,250);
$page = $pdfPath."[0]";
$im->readImage($page);
if($im->getImageColorspace() == Imagick::COLORSPACE_CMYK)
{
$im->transformImageColorspace(Imagick::COLORSPACE_SRGB);
$im->autoLevelImage();
}
$im->setImageFormat('jpg');
$im->setImageCompression(imagick::COMPRESSION_JPEG);
$im->setImageCompressionQuality(90);
$im->writeImage("page1.jpg");
However the coloring seems to differ from the original PDF, for example (see image)
left side is original PDF.
right side the rendered image, which has different colors than the original.
It seems that the original color of dark-pink turns into purle. Also red colors seem to saturate.
I have tried the following, but none worked:
reduce saturation (e.g. $im->modulateImage(100, 80, 100); ) But this causes red to become orange and yellow colors to turn greenish.(see example below)
playing around with image filter (e.g. imagefilter($im, IMG_FILTER_COLORIZE,100, 0, 0); ), but this also changes all colors.
Thinking it had to do with differences between CMYK and RGB, I have added $im->transformImageColorspace() doesn't do anything to fix this.
playing with various hue filters, but these change all colors of the image also.
Question: it seems I need to reduce the redness of the image? (I think it's the excessive red color causing the difference) without affecting the other colors, so that for example yellow remains yellow. Is there a way to do this in PHP?
The solution is to add the following line before reading the image:
The code should be:
$im->setColorspace(Imagick::COLORSPACE_SRGB);
$im->readImage($page);
Related
I have an 8 bit PNG (original is here: https://i.ibb.co/s3024Y8/1000x1500-autumn-leaves.png) and I want to change the colour of the leaves.
I have a list of the hex colours that need to be changed and a list of the colours they need to be changed to - all to be done dynamically. I'm working towards a solution that has to work off those lists - but that can wait. For this question, being able to change the colour of just one leaf will do.
After changing the colour of the leaf I need the image to retain its transparent areas (so I can lay it on top of another image - that part I can do).
I am quite new to the GD library and am getting confused. I understand that an 8-bit PNG (as created in Photoshop) has full alpha - and that needs to be preserved.
That leads me to the start of my code:
$im = ImageCreateFromPNG('https://i.ibb.co/s3024Y8/1000x1500-autumn-leaves.png');
ImageAlphaBlending($im, false);
imagesavealpha($im, true);
Everything I've tried after that fails miserably. By that, I mean that the colour doesn't change. No error message, just no change in colour. It seems that the following has no effect when using that image:
$myColourToChange = imagecolorallocatealpha($im, 100, 24, 11, 0); // colour of dark brown leaf
imagecolorset($im, $myColourToChange, 255, 0, 0, 0); // try changing it to red, fully opaque
I've even tried (which gives 6559755)
$myColourToChange = imagecolorresolvealpha($im, 100, 24, 11, 0);
I think things are failing (ie the colour doesn't change) because the image I'm using isn't a paletted image in the way that GD needs it to be, in order for me to use imagecolorset
I've tried converting it to one using imagetruecolortopalette but that gives unpredictable results on the image, with all sorts of artifacts not visibly present in the original image - and the colour values change slightly.
Note that the following are representations if you want to experiment, use the image link above.
Original image before imagetruecolortopalette - dark brown leaf colour: #64180B
After imagetruecolortopalette - dark brown leaf colour: #631A0C
So how do I specify the colour that needs to be changed and then change it to the given colour? If it means I must use imagetruecolortopalette how do I deal with the artifacts and the colour change I get when using it?
(I won't know in advance the location of colours that need changing, so imagecolorat won't help)
Thanks in advance :)
I want to convert a given color to transparency with iMagick. I have found one way to do this, but it behaves like a paint bucket rather than examining the entire image.
For the following example, I'm using this:
$transparentColor = new ImagickPixel('transparent');
$image->floodFillPaintImage($transparentColor, 20000, "#0009c5", 0, 0, false, Imagick::CHANNEL_ALPHA);
This is the input image
This is the output image
The result I'd like to see is all the blue areas turned to transparency. Unfortunately, it seems that "fill" is the key point in this function and hence stops when confronted with non-"target" colors.
Does anyone know how to accomplish turning all the blue areas to transparent using iMagick (not command line imageMagick)?
Thanks in advance!
Try:
$image->transparentPaintImage($targetColor, $alphaLevel, $fuzz, false);
If the transparent areas are "messy", it may help to despeckle:
$image->despeckleimage();
Doc: http://php.net/manual/en/imagick.transparentpaintimage.php
My goal
I have an existing PNG. It currently has anti-aliasing, or in other words, shades of gray. I want the image to be 1 bit, or in other words, only using the colors black and white. My aim is to do this with PHP GD. I have to do this with an existing image, and can not create the image from scratch using imagecreatetruecolor.
What I'm trying
The function I've found that seems best for the job is imagetruecolortopalette
http://php.net/manual/en/function.imagetruecolortopalette.php
Here is a simple version of what I'm trying to do
$user_design = base64_decode($_POST['input']);
$design_file = fopen('path/filename.png', 'w') or die("Unable to open file!");
imagetruecolortopalette($design_file, false, 1);
fwrite($design_file, $user_design);
fclose($design_file);
With this being the key line. The 1 being the "maximum number of colors that should be retained in the palette."
imagetruecolortopalette($design_file, false, 1);
Behavior I'm getting
The image appears unchanged. I'm not sure if I'm using PHP GD correctly, or if this function doesn't do what I think it does.
Other ideas
These also seem promising.
imagecolordeallocate seems like I may be able to use it to deallocate colors, but not sure how to do this without calling it 254 times.
http://php.net/manual/en/function.imagecolordeallocate.php
imagecolorset seems like I may be able to use it to set the palette, but I'm not sure how to do this for existing images.
http://php.net/manual/en/function.imagecolorset.php
Mostly I suspect imagetruecolortopallette is the best bet, but any and all ideas welcome.
$im = imagecreatefromstring($user_design);
imagefilter($im, IMG_FILTER_GRAYSCALE);
imagefilter($im, IMG_FILTER_CONTRAST, -1000);
imagepng($im, 'path/filename.png');
imagedestroy($im);
How do you convert an image to black and white in PHP
i am trying to to colorize a black and white picture on my server.
i have tried doing this with multiple methods and the only one that kind-of-works is gd imagefilter via filter IMG_FILTER_COLORIZE.
it does kind of colorize the image in exactly the same color that i want, but it loses all the details on the image, as if it just trimmed black dots that were not black enough and thinned all the black lines, making them almost invisible. here is what i'm talking about:
this result was achieved with this code
$im=imagecreatefromjpeg($orig_file);
imagefilter($im, IMG_FILTER_COLORIZE, 71, 92, 10);
imagejpeg($im, $output_file, 95);
why is this happening? are there any other methods how i could colorize the image? my original image is quite large and i can't iterate over it as it is too slow; that's why i'm trying to use a library that would do this
i have managed to achieve the desired result with help of Imagick and compositeImage. here is the result
how i achieved it is kind of a trick that works only in a very specific condition- which is the need to have the background white and only black/gray objects in front (or the exact opposite). this technique wouldn't work on a background with transparency
the idea is to have 2 layers- underneath is the layer with original grayscale image and the top layer- fully filled with the desired color. then you composite these images using "COMPOSITE_LIGHTEN" (you might use other methods, like darken for example- if you have white objects on a black background)
this is the code
$base_color="#475c0a";
$im=new Imagick($orig_file);
$im2 = new Imagick();
$im2->newImage($im->getImageWidth(), $im->getImageHeight(), new ImagickPixel($base_color) );
$im->compositeImage($im2, Imagick::COMPOSITE_LIGHTEN, 0, 0);
$im->writeImage($new_image_path);
hope this will help someone out
I have pieced together a PHP class to perform various image related functions using GD functions of PHP.
It works great for all image types. Rotate, flip, resize, crop and to a lesser extent, watermark.
All but the latter work perfectly. For example after a few changes, rotated PNG images retained their transparency whereas before they were losing that and the background turning black. Common problem, it appears. But all working now.
Where I'm still getting stuck is watermarking a PNG image with another PNG image. It appears to work fine with JPG and other images. This is the code (simplified):
public function writeWatermarkSimple()
{
$watermarkFile = 'watermark.png';
$watermarkImage = imagecreatefrompng($watermarkFile);
imagealphablending($watermarkImage, false);
imagesavealpha($watermarkImage, true);
$imageFile = 'image.png';
$baseImage = imagecreatefrompng($imageFile);
imagealphablending($baseImage, false);
imagesavealpha($baseImage, true);
$marginH = imagesx($baseImage) - imagesx($watermarkImage);
$marginV = imagesy($baseImage) - imagesy($watermarkImage);
$cut = imagecreatetruecolor(imagesx($watermarkImage), imagesy($watermarkImage));
imagecopy($cut, $baseImage, 0, 0, $marginH, $marginV, imagesx($watermarkImage), imagesy($watermarkImage));
imagecopy($cut, $watermarkImage, 0, 0, 0, 0, imagesx($watermarkImage), imagesy($watermarkImage));
imagecopymerge($baseImage, $cut, $marginH, $marginV, 0, 0, imagesx($watermarkImage), imagesy($watermarkImage), 80);
if (!imagepng($baseImage, 'watermarked_image.png'))
{
return false;
}
return true;
}
This has been pieced together with various guides and advice people have given based on a similar issue. Again, working perfectly with JPG images and PNG watermarks, but not PNG & PNG.
Some example images:
http://i.imgur.com/hHRWinj.png - This is the watermark I'm using.
http://i.imgur.com/6sy8Ncs.png - This is the image I'm applying the watermark to.
http://i.imgur.com/ghovYLm.png - This is the end result.
The bit I find interesting is that any part of the watermark that is overlaid on a non-transparent portion of the image is working fine. Just the rest of it has the black background.
This leads me to believe I'm close, and I hope that the expertise of you fine people may lead me to the solution.
Thanks ever so for reading.
So, I'm not giving up on finding the correct answer to do this using GD. However, I was overjoyed to find that what needed up to 30 lines of code with GD can be achieved using much less with ImageMagick:
$image = new Imagick();
$image->readimage($this->_image);
$watermark = new Imagick();
$watermark->readimage($this->_watermark->_getImage());
$watermark->evaluateImage(Imagick::EVALUATE_DIVIDE, 2, Imagick::CHANNEL_ALPHA);
$image->compositeImage($watermark, imagick::COMPOSITE_OVER, $marginH, $marginV);
So this is before (with GD):
http://i.imgur.com/AlS0TcO.png
And after (with ImageMagick and the code above):
http://i.imgur.com/zBxlC3R.png
If anyone has an answer that is purely GD then I'd be immensely grateful.
Ran into some similar issues recently and while this may not exactly solve your problem, these were some useful discoveries that I made.
In my case, I have an original .jpg image and a watermark .png image. The watermark image has a fully transparent background. I wanted to specify the opacity in my script and have it change the watermark opacity before placing it on top of the origina image. Most posts out there regarding PHP watermarking assume that the original watermark .png file already has the solid watermark portion set to the correct opacity rather than changing it via the script.
gd didn't like a 24 bit .png and caused some goofy issues. Switching to 8 bit resolved that with gd. On the other hand, imagick works very well with a 24 bit .png and the final result seems to be better.
For me, using gd worked just fine if I was opening the original watermark .png and using imagecopymerge() to set the watermark transparency. If however I tried to scale the original watermark .png (which has transparent background) first, then I would get similar results as you with black or white background portion of where watermark image is. See How do I resize pngs with transparency in PHP? for a partial solution by filling the new wm image with transparent rectangle first. For me this still produced an opaque white background on the final result no matter what I tried.
I switched to imagick and was using setImageOpacity() to change the transparency of my watermark .png before applying it on top of my original image and I was still getting the same effect with a black background. Finally read in the PHP doc for setImageOpacity() that if the original .png has any transparent pixels and you try to lower the opacity, those pixels become opaque (black) with the new transparency applied. Instead, need to use the evaluateImage() function. This will instead evaluate each pixel's alpha channel only and divide by the specifid number.
I assume the black / white background issue with gd is likely due to similar ways that it treats alpha channels when scaling / combining as compared to imagick and if you want to do it all in gd you just need to find some similar way to evaluate and manipulate the alpha channel per-pixel because the "easy" ways seem to take an already transparent background and make it opaque.
So, the solution:
Assuming you want to apply your watermark at an opacity of 45% and you're using imagick, then instead of this:
$watermark->setImageOpacity(.45);
do this
$watermark->evaluateImage(Imagick::EVALUATE_DIVIDE, (1/.45), Imagick::CHANNEL_ALPHA);
You need to divide 1 by your opacity to get the demoninator by which the function will divide the alpha channel value for each pixel. In this case, 1/.45 = 2.2222, so then the function will divide the alpha channel of each pixel by 2.2222. This means a solid pixel (alpha of 1) would result in 1/2.2222 or .45 alpha or transparency when finished. Any pixels that were already transparent (alpha 0) would stay transparent because 0 divided by anything is always what? Zero!
After you change the watermark transparency then you can use compositeImage() to merge the watermark onto the original image.