Here I just grabbed the ID or a data in the check box. But I want to capture more data with the ID. How to do it?
<input type="checkbox" name="man" value="<?php echo $row['id']; ?>">
And how do I insert that data into another table via PHP MySQL?
You have to set checkboxes name with array brackets.
Ex: <input type="checkbox" name="man[]" value="<?php echo $row['id']; ?>">
After that if you get their values with $_POST["man"], then an array with value of the checkboxes will be return.
Related
I have code similar to the following:
<input type="checkbox" name="visitProperty" value="1" id="visit-0">
<input type="checkbox" name="visitProperty" value="1" id="visit-1">
<input type="checkbox" name="visitProperty" value="1" id="visit-2">
...
Once the form is submitted I want to get checked checkboxes, so far I've been using
if (isset($_POST['visitProperty']) {..}
But to my understanding it only gets one checkbox? Where as I need to check all of them and see if they were checked, so inside the if statement I can create a loop that gets id's of all submitted checkboxes and then gets the number from id, to update a certain array.
<input type="checkbox" name="visitProperty[]" value="1" id="visit-0">
<input type="checkbox" name="visitProperty[]" value="2" id="visit-1">
<input type="checkbox" name="visitProperty[]" value="3" id="visit-2">
<?php
foreach($_POST['visitProperty'] as $check) {
echo $check . "<br>"; // for example
}
?>
NOTE: $_POST['visitProperty'] will hold checked checkbox values. You will access all the checkboxs as an array as following $_POST['visitProperty'][]
When you put in the name, you are declaring a variable. You need to declare it as an array, or each checkbox will bump out the last one. Add some empty square brackets to the name.
You would need or defined ID or a unique value, otherwise you will not be able to identify them on the server-side (the ID does not get sent in $_POST).
So in case of a unique, identifyable ID, you could do something like:
<input type="checkbox" name="visitProperty[<?php // echo some unique id from a database for example ?>]" value="1" id="visit-0">
The reason you would need the ID to be identifyable, is that unchecked checkboxes do not get sent to the server, so you might end up with an array of 2 if visitProperty is an array, but you would not know which 2.
In my html I have this,
<tr>
<td class="grid_cell" width="5%">
<input type="checkbox" name="workspace_trees_rpt_target" id="<?php echo $t["tree_id"];?>" value="<?php echo $t["tree_id"];?>" />
</td>
</tr>
this are inside a loop so what will be displayed is a lot of checkboxes with different values. And in my script I have this,
if(confirm("Delete cannot be undone, click OK button to proceed.")) {
document.forms[0].method="POST";
document.forms[0].action="delete.php";
document.forms[0].submit();
}
after selecting two of the checkboxes and click the OK button, I then go to delete.php to print_r my post data. But when the result of print_r is displayed it only showed one value for the checked checkboxes, but I was expecting two of them. How can I make it such that when I check multiple checkboxes, the post data for the checkboxes will be an array of values of the checked checkboxes?
you must set the name of the inputs as array:
name="workspace_trees_rpt_target[]"
You have given the same name to all of your checkboxes. So only one value can be returned.
Change to
<input type="checkbox" name="workspace_trees_rpt_target[]" id="<?php echo $t["tree_id"];?>" value="<?php echo $t["tree_id"];?>" />
Then in your PHP code you will get and array of $_POST['workspace_trees_rpt_target'][]
So process it like this:
if ( isset( $_POST['workspace_trees_rpt_target'] ) ) {
// at least one checkbox has been ticked
foreach ( $_POST['workspace_trees_rpt_target'] as $checkboxe ) {
// do whatever $checkbox it will be set to the value="" that you set earlier
}
}
I'm presented with a problem using PHP and MYSQL. I have a dynamic list of options which the user can select (maximum of 3) that are added from the administration panel as shown below:
<input type="checkbox" name="<?php echo "category".$i; ?>"
value="<?php echo $cat_id; ?>" />
<?php echo $cat_name; ?><br />
<?php
$i++;
}
echo "<input type='hidden' name='num_cat' value='$num_cat' />";
?>
I now want to count how many check boxes are 'checked' and if there are more than 0 and less than 4 checked it will update the mysql table with these stored. They are stored by means of 1's and 0's. So they tick 'yes' and a 1 is stored, they tick 'no' and a 0 is stored.
I've been trying to use jQuery and Javascript but they all seem to be for Check Box Forms which have the values pre-written within a form, mine are dynamic from a database.
Many thanks for your help.
Use [] in the end of your checkbox names and use the sizeof function on the corresponding $_POST[] array in your php script.
<input type="checkbox" name="values[]" value="1" />Value 1
<input type="checkbox" name="values[]" value="2" />Value 2
sizeof($_POST['values']);
Note that the checkboxes have the same name and end with brackets (values[]). This indicates that the checkboxes belong together and are bundled as an array in php. Only the selected values will be present in the array as well.
I have a checkbox that if checked stores the value "testing" to the field "checkbox" om my database.
<input type="checkbox" name="checkbox" value="testing">
I would like to store two values, on two fields on my database, from one checkbox.
If checked:
store value testing to the checkbox field
store value testing2 to the checkbox2 field
Is this possible?
Thanks in advance
<input type="checkbox" name="checkbox" <?php if($val=="testing"): echo "value='testing' echo checked='on'" ?>">
<input type="checkbox2" name="checkbox2" <?php if($val=="testing2"): echo "value='testing2' echo checked='on'" ?>">
Hope this is what you are looking for..
I have spent quite some time making a function and the last 15-20 minutes trying to figure this out. I need help!
I am selecting multiple rows from the database and then running them in a while loop.
They are available on a dropdown menu.
<form method="POST" action="adminprocess.php">
<fieldset>
<p>
<label class="left2">League:</label>
<select name="league" class="combo">
<?php
$q = $database->selectAllLeagues();
while($row=mysql_fetch_assoc($q))
{
$theid = $row['id'];
extract($row);
?>
<option value="<? echo $theid; ?>">
<? echo $format.'_'.$game.'_'.$name.'_Season '.$season;?>
</option>
<?
}
?>
</select>
</p>
<p>
<input type="hidden" name="replaceleague" />
<input type="hidden" name="format" value="<? echo $format; ?>" />
<input type="hidden" name="game" value="<? echo $game; ?>" />
<input type="hidden" name="name" value="<? echo $name; ?>" />
<input type="hidden" name="season" value="<? echo $season; ?>" />
<input type='submit' class="button" value='Select league' />
</p>
</fieldset>
</form>
$theid seems to be working fine dependning on which row i select on the dropdown menu.
However, I cant get the values below in the hidden inputs to pass through the correct values from the row selected in the dropdown box.
It seems to always pass through the 4 variables from the first row of the database.
So basically, I need it to select the right row and use that data.
What am i doing wrong!!!
Thanks for reading!
Your hidden fields are initialized outside the loop, so they'll use the values that were left over from the last iteration of the while loop. (i.e. the last fetched row)
Why do you actually need the hidden fields in the first place? When you submit the form, the league field will contain the ID of the row selected in the drop-down box. Using the ID, you can fetch the other fields from the database when processing the form.
To directly answer your question about the while loop, it's because the hidden inputs are echoed outside the loop, after which data the last-iterated row from your database is used by PHP to output to those hidden inputs.
But I suggest that instead of using hidden form elements like that, you submit your form with the <option> with the value a user chooses, read the value (as in $_POST['league']), and fetch the row from your database with that ID and use it accordingly. (You may wish to keep the replaceleague hidden input if your application needs it of course.)
It's much easier, plus it ensures the information about the row a user chooses is coming from your database and not tampered with. In fact, for most applications this is the right way to go.