I would like to move to the next record using an HTML button. I have tried for and foreach SQL statements I have also tried using num rows and calling the cells values.
$id=$_get['Badge ID Number'];
$sqlkc = "select * from Badges.BADGEMSTR";
$result = mysqli_query($sqlc, $sqlkc);
if($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
$BIDN= $row['Badge ID Number'];
$Fname= $row['First Name'];
$MI= $row['Middle Initial'];
$Lname= $row['Last Name'];
}
$next = next($result);
?>
Thank you in advance for your help.
Forgot to add my current onclick command
onclick='<?php echo $next;?>'
All HTML code as requested
<table style="background-color: tan; margin: auto">
<tr>
<td><input type="text" value="<?php echo $BIDN;?>"/>
<input type="text" value="01"/></td>
</tr>
<tr>
<td>
<input type="text" value="<?php echo $Fname;?>"/>
<input type="text" value="<?php echo $MI;?>"/>
<input type="text" value="<?php echo $Lname;?>"/>
</td>
</tr>
<tr>
<td><input type="button" value="Next" style="float: right" onclick='<?php echo $next;?>'/></td>
<td><input type="button" value="Last" style="float: right" onclick='<?php echo $nextid;?>'/></td>
</tr>
</table>
I hope I understood the question right.
Since you would pass the Badge ID between pages, you should use prepared statements as such. So, taking the Badge ID Number is Integer, your PHP code should look like this:
$link = mysqli_connect(hostname,username,password,dbname);
if (isset($_GET['last_id'])) {
// Last row in the table
$stmt = mysqli_prepare($link, 'SELECT * FROM Badges.BADGEMSTR ORDER BY `Badge ID Number` DESC LIMIT 1');
} elseif (isset($_GET['id'])) {
// Specific row in the table
$stmt = mysqli_prepare($link, 'SELECT * FROM Badges.BADGEMSTR WHERE `Badge ID Number`>? ORDER BY Rb ASC LIMIT 1');
$stmt->bind_param('d',$_GET['id']);
} else {
// First row in the table
$stmt = mysqli_prepare($link, 'SELECT * FROM Badges.BADGEMSTR ORDER BY `Badge ID Number` ASC LIMIT 1');
}
// Execute the query and get the results
$stmt->execute();
$result = $stmt->get_result();
$row = $result->fetch_array();
// Initialize variables from the given $row
$BIDN = $row['Badge ID Number'];
$Fname = $row['First Name'];
$MI = $row['Middle Initial'];
$Lname = $row['Last Name'];
As for the HTML code, it's a bit unclear from the question, but I think something like this would be in order:
<html>
<head></head>
<body>
<table style="background-color: tan; margin: auto">
<tr>
<td><?php echo htmlspecialchars($BIDN, ENT_QUOTES); ?></td>
<td>01</td>
</tr>
<tr>
<td><?php echo htmlspecialchars($Fname, ENT_QUOTES); ?></td>
<td><?php echo htmlspecialchars($MI, ENT_QUOTES); ?></td>
<td><?php echo htmlspecialchars($Lname, ENT_QUOTES); ?></td>
</tr>
<tr>
<td>
Next
</td>
<td>
Last
</td>
</tr>
</table>
</body>
</html>
You also don't have to use inputs to display the results, you could show them between TD elements in the table like <td><?php echo $row['Badge ID Number']; ?>.
Related
I get the data from mysql and display it in the table now i'm trying to send it to the database for each student by checking the checkbox, then what should i do to send all table data into the msql database with the different student id
<form class="col-md-12" action="Attendance.php" method="post">
<table id="example" class="myclass table table-striped" />
<thead>
<tr>
<th>ID</th>
<th>Full Name</th>
<th>Father Name</th>
<th><label><input type="checkbox" id="selectAll" name="chbox[]"> All Present </label></th>
</tr>
</thead>
<tbody>
<?php
$SrNo = 0;
global $dbManager;
$sql = "SELECT * FROM studentinfo";
$stmt = $dbManager->query($sql);
while($DataRows = $stmt->fetch()){
$RollNo = $DataRows['id'];
$FullName = $DataRows['fullname'];
$FatherName = $DataRows['fathername'];
?>
<tr>
<td><?php echo $RollNo; ?></td>
<td><?php echo $FullName; ?></td>
<td><?php echo $FatherName; ?></td>
<td><input type="checkbox" name="chbox[]" value="1" /></td>
</tr>
</tbody>
<?php } ?>
<tfoot>
<?php
if(isset($_POST['Submit'])){
$StudentRollNo = $RollNo;
$Attendance = $_POST['chbox'];
// date_default_timezone_set("Asia/Kabul");
$CurrentTime = time();
$DateTime = strftime("%B-%d-%Y %H:%M:%S", $CurrentTime);
if(empty($Attendance)){
$_SESSION['ErrorMessage'] = "Please filled all fields";
RedirectTo("Attendance.php");
}
else{
// the sql code is here.
global $dbManager;
foreach ($Attendance as $key => $value) {
$sql = "INSERT INTO attendance(sid, subjectid, classid, attendance, datetime) VALUES(:studentId,'1','2', :attendancE, :dateTime)";
$stmt = $dbManager->prepare($sql);
$stmt->bindValue(':studentId',$StudentRollNo);
$stmt->bindValue(':attendancE',$value);
$stmt->bindValue(':dateTime',$DateTime);
$Execute = $stmt->execute();
if($Execute){
$_SESSION['SuccessMessage'] = "Attendance Submited Successfully.";
RedirectTo("Attendance.php");
}
else{
$_SESSION['ErrorMessage'] = "Something went wrong. Try Again!";
RedirectTo("Attendance.php");
}
}
}
?>
<tr>
<td>
<i class="fa fa-check"></i>
<input type="submit" name="Submit" value="Save Attendance">
</td>
</tr>
</tfoot>
</table>
</form>
Mysql database: the problem is that the record saves only for one student.
Bring you table inside the while loop where you are fetching the values from the database and then assign the value of students dynamically for the checkbox value
you can do
value="<?php echo $RollNo; ?>";
just like you echo out the other values add the echo into the value field of the checkbox in order to get the values dynamically assigned to each checkbox
How to correctly display data from the mysql database but through the ID number. The ID number is entered on the INPUT(Edit) field in the field. Connection to the database works.
<form action="" method="post">
<input type="number" name="id">
<input type="submit" value"enter">
</form>
<table>
<thead>
<tr>
<td>id</td>
<td>First Name</td>
<td>Last Name</td>
</tr>
</thead>
<tbody>
<?php
require_once('conect.php');
$id = $_POST['id'];
$result = $conn->prepare("SELECT * FROM users WHERE id = $id ORDER BY id DESC ");
$result->execute();
$results = $result->fetchAll();
foreach ($results as $index => $row)
{
?>
<tr>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['FirstName']; ?></td>
<td><?php echo $row['LastName']; ?></td>
</tr>
<?php } ?>
</tbody>
</table>
The name attribute on the submit button is submit not Submit
Should be
if(isset($_POST['submit']))
Also you should be using prepared statements. Bind the id variable to placeholder.
Im new in php. this problem stuck me for two days. ergh. I want to display a table that contain input field so that user can insert the data and update it into database. User can change all the data in the table. I want to update multiple rows at a time, but it ends up updating only 1 row (the last row). Anyone please help me for this. Thnks.
This are the form.
This are the following code.
[<table>
<thead>
<tr>
<td><b>Item Code</b></td>
<td><b>Item Barcode</b></td>
<td><b>Item</b></td>
<td><b>QOH</b></td>
<td><b>Quantity</br>Checked</b></td>
<td><b>Quantity</br>Order</b></td>
</tr>
</thead>
<?php
$Barcode=$_SESSION\["Barcode"\];
$code=$_SESSION\["Code"\];
$itemcode=$_SESSION\["Itemcode"\];
$guid=$_SESSION\["guid"\];
$sql = "SELECT itemmastersupcode.*, itembarcode.*, stock_count_item.*, stock_count.*, po_ex_c.*, d.itemlink_total_qty
FROM itemmastersupcode
WHERE stock_count.SupCode = '$code' and stock_count_item.TRANS_GUID = '$guid'
GROUP BY itemmastersupcode.Itemcode";
$result=mysqli_query($conn2,$sql);
$rowcount = mysqli_num_rows($result);
while($row = mysqli_fetch_assoc($result))
{
?>
<tbody>
<tr>
<td><?php echo $row\["Itemcode"\]; ?></td>
<td><?php echo $row\["Barcode"\]; ?></td>
<td><?php echo $row\["Description"\]; ?></td>
<td><?php echo $row\["itemlink_total_qty"\]; ?></td>
<td><?php echo $row\["qty"\]; ?></td>
<form class="form-inline" role="form" method="POST" id="myForm">
<td><input type="number" name="qty" value=""/></td>
</tr>
</tbody>
<input type="hidden" name="itemcode" value="<?php echo $row\["itemcode"\]; ?>"/>
<input type="hidden" name="supcode" value="<?php echo $_SESSION\["Code"\] ?>"/>
<input type="hidden" name="guid" value="<?php echo $_SESSION\["guid"\] ?>"/>
<?php
}
?>
</table>
<button name="save" type="submit" ><b>SUBMIT</b></button>
</form>
<?php
if (isset($_POST\["save"\]))
{
$itemcode=$_POST\['itemcode'\];
$qty=$_POST\['qty'\];
$supcode=$_POST\['supcode'\];
$guid=$_POST\['guid'\];
$sql = "UPDATE stock_count, stock_count_item SET stock_count.posted = '1', stock_count_item.qty_order = '$qty'
WHERE stock_count.TRANS_GUID = '$guid' AND stock_count_item.Itemcode ='$itemcode'
and stock_count_item.TRANS_GUID = '$guid' ";][1]
An UPDATE query will update all records that are filtered by the WHERE clause. If no WHERE is given, all records are updated:
UPDATE table1 SET field1='value1';
will set the field1 column of all records to value1.
UPDATE table1 SET field1='value1' WHERE field2='value2';
will set the field1 column to value1 or all records where field2 is equal to value2.
So, in your case, the records that are found through the WHERE clause are updated. This is all basic SQL stuff by the way, so I advise you to read up on SQL.
Finally, also use prepared statements in your code to prevent SQL injection.
<table>
<thead>
<tr>
<td><b>Item Code</b></td>
<td><b>Item Barcode</b></td>
<td><b>Item</b></td>
<td><b>QOH</b></td>
<td><b>Quantity</br>Checked</b></td>
<td><b>Quantity</br>Order</b></td>
</tr>
</thead>
<?php
$Barcode=$_SESSION["Barcode"];
$code=$_SESSION["Code"];
$itemcode=$_SESSION["Itemcode"];
$guid=$_SESSION["guid"];
$sql = "SELECT itemmastersupcode.*, itembarcode.*, stock_count_item.*, stock_count.*, po_ex_c.*, d.itemlink_total_qty
FROM itemmastersupcode
WHERE stock_count.SupCode = '$code' and stock_count_item.TRANS_GUID = '$guid'
GROUP BY itemmastersupcode.Itemcode";
$result=mysqli_query($conn2,$sql);
$rowcount = mysqli_num_rows($result);
while($row = mysqli_fetch_assoc($result))
{
?>
<tbody>
<tr>
<td><?php echo $row["Itemcode"]; ?></td>
<td><?php echo $row["Barcode"]; ?></td>
<td><?php echo $row["Description"]; ?></td>
<td><?php echo $row["itemlink_total_qty"]; ?></td>
<td><?php echo $row["qty"]; ?></td>
<form class="form-inline" role="form" method="POST" id="myForm">
<td><input type="number" name="itemcode[<?php echo $row["itemcode"]; ?>][qty]" value=""/></td> //update here
</tr>
</tbody>
<?php
}
?>
</table>
<input type="hidden" name="supcode" value="<?php echo $_SESSION["Code"] ?>"/> //update here
<input type="hidden" name="guid" value="<?php echo $_SESSION["guid"] ?>"/>//update here
<button name="save" type="submit" ><b>SUBMIT</b></button>
</form>
Php content
<?php
if (isset($_POST["save"]))
{
$itemcodes=$_POST['itemcode'];
$qty=$_POST['qty'];
$supcode=$_POST['supcode'];
$guid=$_POST['guid'];
$sql = "UPDATE stock_count, stock_count_item SET
stock_count.posted = '1',
stock_count_item.qty_order = CASE stock_count_item.Itemcode";
foreach( $itemcodes as $itmcode=>$qty)
{
$sql.=" WHEN ".$itmcode." THEN ".$qty
}
$sql.=" END WHERE stock_count.TRANS_GUID =$guid AND stock_count_item.TRANS_GUID=$guid AND stock_count_item.Itemcode IN (".implode(",",array_keys( $itemcodes)).") ";
?>
Hope it will help
I am trying to delete a product from the table, but it does not work.
Is the script wrong? How can I correct it?
include_once('connection.php');
include_once('functions.php');
if(isset($_POST['delete'])){
mysqli_query( $conDB, "DELETE FROM products WHERE name='$_POST[hidden]'");
};
$page = (int)(!isset($_GET["page"]) ? 1 : $_GET["page"]);
if ($page <= 0) $page = 1;
$per_page = 10; // Set how many records do you want to display per page.
$startpoint = ($page * $per_page) - $per_page;
$statement = "products ORDER BY id DESC";
$results = mysqli_query($conDB, "SELECT * FROM {$statement} LIMIT {$startpoint} , {$per_page}");
if (mysqli_num_rows($results) != 0) {
while ($row = mysqli_fetch_array($results)) {
$name = $row['name'];
?>
<tr>
<td align="left" colspan='2' ><big style="color:red" ><b><?php echo $row['name']?></b></big><td>
</tr>
<tr>
<td align="left" colspan='2'><big style="color:333333"><b><?php echo $row['category']?></b> / <?php echo $row['subcategory']?></big></td>
</tr>
<tr>
<td style="vertical-align:top" >
<?php echo "<img border=3 width= 300px height =250px src=\"products/" . $row['picture']>?>"<br />
</td>
<td style="vertical-align:top">
<?php echo nl2br($row['description'])?>
</td>
</tr>
<tr>
<td> <input type="hidden" name="hidden" value="$name" ><input type="submit" name="delete" onClick='return confirmDelete()' value='Delete Product'></td>
When I delete the "delete product" the confirmation will show if I will delete it. but after the confirmation. it does not delete the selected row from the table.
There is no show of error from php after the confirmation. Why is it happening and
how can I fix it?
Looking at the hidden value, it seems its not written properly in the markup:
<input type="hidden" name="hidden" value="$name" >
<!-- ^ literal string, not a variable value -->
Should be:
<input type="hidden" name="hidden" value="<?php echo $name; ?>" />
Sidenote: Since you're already using mysqli, why not utilize prepared statements.
if(isset($_POST['delete'])) {
$delete = $_POST['delete'];
$del = $conDB->prepare('DELETE FROM products WHERE name = ?');
$del->bind_param('s', $delete);
$del->execute();
}
I suggest do it like this, remove the hidden input and use this instead:
<button type="submit" name="delete" onClick='return confirmDelete()' value="<?php echo $row['id']; ?>">Delete Product</button>
Just correct your input hidden field:
<input type="hidden" name="hidden" value="<?php echo $name; ?>" >
Try
echo "DELETE FROM products WHERE name='$_POST[hidden]'";
and then try executing the sql or modify
"DELETE FROM products WHERE name='".$_POST[hidden]."'"
It's been a while since I looked at php and I've got a brain block. I'm trying to get the values from a table using foreach so that I can store the values in a session and also display the number of items that have been ordered.
eg 2 of item number 4 etc
here's the table / form
<form id="products" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<?php
//every item from the products table is queried because all fields need to be displayed
$sSQL = "SELECT * FROM products";
$rsResult = mysql_query($sSQL);
?>
<table id="products_table">
<tr style="font-weight:bold">
<td style="text-align:center">ID</td>
<td>Ref No.</td>
<td>Product Name</td>
<td>Description</td>
<td style="text-align:right">Price</td>
<td colspan='2' style='text-align:center'>Add To Order</td>
</tr>
<!--for each record in the table that matches the query a row is created in the table and the data in the relevant field is displayed-->
<?php while ($row = mysql_fetch_array($rsResult)){ ?>
<tr>
<input type="hidden" name="productID[<? echo $row['productID']; ?>]" value="<? echo $row['productID']; ?>" />
<td style="text-align:center"><? echo $row['productID']; ?></td>
<td><? echo $row['productReference']; ?></td>
<td><? echo $row['productName']; ?></td>
<td><? echo $row['productDescription']; ?></td>
<td style="text-align:right"><? echo '£'. $row['productPrice']; ?></td>
<td style="text-align:center"><span>Qty</span><input type='text' name="qty[<? echo ($_POST['qty']); ?>]" value="" ></td>
<? } ?>
</table>
Heres the php
<?php
foreach($_POST as $key => $value){
echo $key . ' ' .$value.'<br />';
print_r($key);
}
?>
I know that the php is no where complete for filling sessions etc, I just can't work out how to get the values out of the form. This php was my attempt to try and at least get some kind of value out of it
Any help is greatly appreciated
in your code , there is no need of
<input type="hidden" name="productID[<? echo $row['productID']; ?>
field .
also change the line
<td style="text-align:center"><span>Qty</span><input type='text' name="qty[<? echo ($_POST['qty']); ?>]" value="" ></td>
to
<td style="text-align:center"><span>Qty</span><input type='text' name="qty[<? echo ($row['productID']); ?>]" value="" ></td>
so that after the submission of the form , you can access the posted values with :
$sSQL = "SELECT * FROM products";
$rsResult = mysql_query($sSQL);
while ($row = mysql_fetch_array($rsResult))
{
echo $_POST['qty'.$row['productID']];
}
why don't you just display data in inputs with proper names?