This question already has answers here:
How to count value in Laravel Eloquent?
(4 answers)
Closed 1 year ago.
I want to count member that has been time in each day but dont have a time out yet. In short i want to count member in particular date that doesnt have time out. This is because i want to count all the member inside the compound for safety guidelines. For example G-51405 been time in but no time out in the table, G-51405 will be counted because he/she dont have a time out yet and so on..
$memberCode = 'G-51405';
$membersCount = Member::where('status','in')->where('member_code', $memberCode)->count();
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When to use VARCHAR and DATE/DATETIME
(5 answers)
Closed 2 years ago.
I have a table that holds few records less than 20. The table (cow_inactive) is just with ID (int) & COW_INACTIVE_DATE (varchar) columns. I am trying to use the DATEDIFF to get all cows that are ready for insemination after 60 Days of being inactive.
SELECT * from cow_inactive where DATEDIFF(CURRENT_DATE, inactive_date)>=60
Result :
Showing rows 0 - 0 (1 total, Query took 0.0022 seconds.)
you need to update field data type COW_INACTIVE_DATE (DATETIME). then run above query
This question already has answers here:
Laravel Eloquent get results grouped by days
(17 answers)
Closed 2 years ago.
I am using laravel and I am trying to get data from database grouped by the column "created_at".
The data into created_at column is being stored is in the below format,
2020-07-23 07:03:59
My question is , how can we fetch the data using group for dates only.
For example , All the records should be grouped into one array/object with same dates.
I tried executing the following query,
$transactions= MyTransaction::where('id','=',$user->id)->orderBy('created_at')->get()->groupBy(function($item) {
return $item->created_at->format('Y-m-d');
});
but it does not return what i am expecting, it considers the seconds and hours into the consideration too.
Please guide me solving this query.
$column = \DB::raw("CONCAT(YEAR(`ride_date`),'-',MONTH(`ride_date`),'-',DAY(`ride_date`)) AS `group_column`");
$transactions= MyTransaction::select('*',$column)->where('id','=',$user->id)->orderBy('created_at')->groupBy('group_column')->get();
This question already has answers here:
How do I calculate the offsets for pagination?
(4 answers)
How to apply bindValue method in LIMIT clause?
(11 answers)
Closed 5 years ago.
I asked a question yesterday titled "How do i use binded variables with MySql LIMIT clause. Sorry, I guess it was not clear enough and got 30 views but no suggestions. So here is what I found after a day of trial and error. First, I discovered that the the LIMIT is the actual physical position of a record in a table not my auto_incremented id_ number. A lot of documentation i read also indicated it was the OFFSET that held the record position, so I wasted a lot of time with weird results. Second, I found documentation with a couple of ways to bind a variable to LIMIT. None of them worked, so I resorted to assigning a $variable to the LIMIT as follows.
("SELECT * FROM $livetable WHERE cust_zip = :cust_zip
HAVING distance < :mydistance ORDER BY client_id ASC LIMIT $start_record_position
, $how_many_records_to_display");
This works for me but any better suggestions, would be appreciated. And I hope this will save someone else a day of figuring this out.
This question already has answers here:
How can I return 10 of the most recent results in sql?
(4 answers)
Closed 9 years ago.
How can i ask a question to a mysql-database (via PDO) to return the 3 latest added rows? The id column is key and auto incremented. That means that highest id means latest added. Don't take into account the fact that rows can have been deleted and such.
Could i somehow use * and LIMIT 3 and start from the bottom some way - or something?
Should be fairly easy but i am kind of stuck.
Order by ID desc limit 3
gives you the three rows with the highest ID. Those are not necessarily the latest three added rows. But they are the latest three added rows still existing in the table.
This question already has answers here:
How to put more than 1000 values into an Oracle IN clause [duplicate]
(11 answers)
Closed 9 years ago.
I am using an IN clause, whereby, it needs to search the id IN these set of IDs that are not in order, meaning, it came from a different criteria., how to solve this ?
SELECT DISTINCT ID FROM "projeck"."mytable" "t" WHERE staffID IN (75953,196262,196387,133585,195639,196702,195790,195820,192903,145383,179603,175896,176554,43545,154843,183798,195767,195715,etc..etc.. etc..)
and i am getting this oracle error
General error: 1795 OCIStmtExecute: ORA-01795: maximum number of expressions in a list is 1000
My first choice would be to reference the function that generates these values directly.
If the values were being used for multiple queries and were expensive to calculate then I'd think about loading them into a global temporary table and joining to it.