Website working on xampp localhost but not online server [duplicate] - php

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Reference - What does this error mean in PHP?
(38 answers)
Closed 1 year ago.
My code is working perfectly well in my xampp localhost but when I tried to put my files online it did not work. On localhost, it works perfectly but when I tried it on online server, it connected to the database but does not store the user data and allows entry. What do I need to change here? I tried to include echos along the way and found out all functions till registering the user works (empty username, email, or password, not confirmed password, username exists, password exits). So I am not sure why there is a problem registering the user.
<?php
session_start();
// initializing variables
$username = "";
$email = "";
$errors = array();
// connect to the database
$db = mysqli_connect('localhost', 'rohit', 'mynameis111', 'registration');
// REGISTER USER
if (isset($_POST[''])) {
// receive all input values from the form
$username = mysqli_real_escape_string($db, $_POST['username']);
$email = mysqli_real_escape_string($db, $_POST['email']);
$password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
$password_2 = mysqli_real_escape_string($db, $_POST['password_2']);
// form validation: ensure that the form is correctly filled ...
// by adding (array_push()) corresponding error unto $errors array
if (empty($username)) { array_push($errors, "Username is required"); }
if (empty($email)) { array_push($errors, "Email is required"); }
if (empty($password_1)) { array_push($errors, "Password is required"); }
if ($password_1 != $password_2) {
array_push($errors, "The two passwords do not match");
}
// first check the database to make sure
// a user does not already exist with the same username and/or email
$user_check_query = "SELECT * FROM users WHERE username='$username' OR email='$email' LIMIT 1";
$result = mysqli_query($db, $user_check_query);
$user = mysqli_fetch_assoc($result);
if ($user) { // if user exists
if ($user['username'] === $username) {
array_push($errors, "Username already exists");
}
if ($user['email'] === $email) {
array_push($errors, "email already exists");
}
}
// Finally, register user if there are no errors in the form
if (count($errors) == 0) {
$password = md5($password_1);//encrypt the password before saving in the database
$query = "INSERT INTO users (username, email, password)
VALUES('$username', '$email', '$password')";
mysqli_query($db, $query);
$_SESSION['username'] = $username;
$_SESSION['success'] = "You are now logged in";
header('location: basics.php');
}
}
if (isset($_POST['login_user'])) {
$username = mysqli_real_escape_string($db, $_POST['username']);
$password = mysqli_real_escape_string($db, $_POST['password']);
if (empty($username)) {
array_push($errors, "Username is required");
}
if (empty($password)) {
array_push($errors, "Password is required");
}
if (count($errors) == 0) {
$password = md5($password);
$query = "SELECT * FROM users WHERE username='$username' AND password='$password'";
$results = mysqli_query($db, $query);
if (mysqli_num_rows($results) == 1) {
$_SESSION['username'] = $username;
$_SESSION['success'] = "You are now logged in";
header('location: basics.php');
}else {
array_push($errors, "Wrong username/password combination");
}
}
}
?>
Update: Hi, here is the errors.php file i forgot to add.
And I checked my error log this is what it shows
[26-Mar-2021 10:17:32 UTC] PHP Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, bool given in /home/z7mselap8dmo/public_html/server.php on line 33
Line 33: $user = mysqli_fetch_assoc($result);
<?php if (count($errors) > 0) : ?>
<div class="error">
<?php foreach ($errors as $error) : ?>
<p><?php echo $error ?></p>
<?php endforeach ?>
</div>
<?php endif ?>

Answer 1

enable error reporting.
For that add this code in start of file
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
Perform a query, check for error
$user_check_query = "SELECT * FROM users WHERE username='$username' OR email='$email' LIMIT 1";
$result = mysqli_query($db, $user_check_query);
if(!$result){
echo("Error description: " . $result->error);
}