I have 2 models, User and Conversation related to each other with a many-to-many relationship, many users to many conversations.
On my models I have:
User:
public function conversation() {
return $this->belongsToMany('App\Models\Conversation');
}
Conversation:
public function users() {
return $this->belongsToMany('App\Models\User');
}
So I could get the conversations a user has by : $user->conversation; and vice versa, retrieve the users a conversation has by $conversation->users, works like a charm. The problem is that I want a way to retrieve all users a certain user has made contact before, in few words, something like:
$user = User::find(1);
$talkedUsers = $user->conversation->user.
And also a way to check all the conversation user 'x' has made with user 'y' ('if any')
$userX = User::find(1);
$userY = 2;
$talkedUser = $userX->conversation->where('user.id', '=', $userY);
Obviously, the code above won't work. I wish to know if something like this is possible to accomplish without adding a complex raw query, I hope is possible only using only QueryBuilder.
The problem is that I want a way to retrieve all users a certain user
has made contact before,
$user->conversation is actually a collection of conversations, it is better to use plural i.e. $user->conversations. Then you can use higher order messages to deal with multiple objects at once. See https://laravel.com/docs/8.x/collections#higher-order-messages for more information
$users = $user->conversations->flatMap->users->unique('id');
flatMap combines multiple User collections retrieved from multiple Conversation objects into one collection of User objects then to remove duplicate users, you can use unique('id')
And also a way to check all the conversation user 'x' has made with
user 'y' ('if any')
First you should query all conversations from x then filter only conversations that have relationships with y.
$userX = User::find($x);
$conversations = $userX->conversations()
->whereHas('users', function($query) use ($y) {
$query->where('users.id', $y);
})
->get();
Related
i'm really new working with laravel 5.0, so I got this problem when I try to retrieve a result using a model. I have a users table, with a list of users who can be a manager or not, they can have assigned one or more companies, or none, a company table with companies which can have one or many managers, and a pivot table that I called companies_managers. I set up the relations in every model like this:
/***User model***/
public function companies()
{
return $this->belongsToMany('App\Company', 'companies_managers','id', 'manager_id');
}
and the same in Company model
public function managers()
{
return $this->belongsToMany('App\User', 'companies_managers', 'id', 'company_id');
}
I want to get the managers assigned to a company using a company id to get it, but it just gave me an huge object without the values I looking for (the names of the managers assigned to that company). This is the code that I tried:
$managers = Company::find($id)->managers();
I would appreciate any help you can give me
Using ->managers() (with the brackets) doesn't actually return the associated managers, but rather a Builder instance (the "huge object"), which you can then chain with additional parameters before finally retrieving them with ->get() (or another closure, like ->first(), ->paginate(), etc)
Using ->managers (without the brackets), will attempt to access the associated managers, and execute any additional logic to retrieve them.
So, you have 2 options:
$company = Company::with(["managers"])->findOrFail($id);
$managers = $company->managers;
Or
$company = Company::findOrFail($id);
$managers = $company->managers()->get();
Both of those will perform the necessary logic to pull the managers. ->with() and no brackets is slightly more efficient, doing it all in a single query, so bear that in mind.
You just need to split out your code;
// this will find the company based on the id, or if it cannot find
// it will fail so will abort the application
$company = Company::findOrFail($id);
// this uses the active company record and gets the managers based
// on the current company
$managers = $company->managers;
Thank you for your help guys, I solved the issue fixing the relations in the models to this:
return $this->belongsToMany('App\Company', 'companies_managers', 'manager_id', 'company_id');
and this
return $this->belongsToMany('App\User', 'companies_managers', 'company_id', 'manager_id');
The IDs that I had set were not the correct ones for belongsToMany function
And this
$managers = Company::find($id)->managers();
was a problem too, was a dumb mistake of my part. I solved the return of Builder instance using just return instead of dd(), in that way I got the values I looking for. Thanks everyone!
I have four tables. User, Conversations, Message and Conversation_Participants.
(I hope you don't find a relationship error in this image )
I tried to add a function
public function conversations(){
return $this->belongsToMany(Conversation::class, 'conversation_participants', 'user_id', 'conversation_id');
}
to User::class but if i call User::with('conversations')->get() i only get all existing Users. What am I doing wrong? First i want to get all conversations the current user participates in and second I want to get all receivers of the conversations.
I also tried
public function participants()
{
return $this->belongsToMany(User::class, 'conversation_participants', 'user_id', 'conversation_id');
}
in the Conversation::class but Conversation::with('participants')->get() gets me all Conversation even those the user isn't participating in.
I'm really confused atm :/
Add the following in your User model:
public function conversations() {
return $this->belongsToMany(Conversation::class, 'conversation_participants', 'users_id', 'conversations_id');
}
And this to your Conversation model:
public function participants() {
return $this->belongsToMany(User::class, 'conversation_participants', 'conversation_id', 'users_id');
}
If you want to link your tables easier, read up on conventions.
To get all the conversations a user is participating in, run the following (assuming you've loaded the user): $user->conversations() to get all the conversations a user is in.
If you want all users, with all their conversations, with all the participants connected, do the following: $users = Users::with('conversations.participants')->get(). You can now loop through this as follows:
foreach($users as $user) {
foreach($user->conversations as $conversation) {
foreach($conversations->participants as $participant) {
// do fancy stuff here
}
}
}
Notice that the user from which you start is also a participant, so maybe you need to filter that one out again.
If you want to get even more fancy (but use more resources) you could even query all the messages a conversation has too!
User::with('conversations.participants', 'conversations.messages.user')->get()
But this only works when you set up a second set of relationships along the upper table in your image (conversations <-> messages <-> users)
Edit
In the comments, OP asked if it was possible to limit the amount of messages retrieved from the database, which is possible to my knowledge, but I don't now if this is the best way:
Remove the messages from the first eager loading part:
User::with('conversations.participants')
After that, when looping through the conversations, lazy load the messages:
$conversation->load(['messages' => function($query){
$query->take(5);
}, 'users']);
Access them after that with $conversation->messages.
Note
I think this could be done more easily in one go, but I don't have a setup right now to test this for you.
Edit 2
After Ronon added another comment, here's what I came up with:
Add a new relationship in the Conversation model:
public function last_messages() {
return $this->hasMany(Message::class, 'conversation_id', 'id')->latest()->limit(2);
}
Because of that, you now can do this:
User::with('conversations.participants', 'conversations.last_messages.users')->get()
If you still want all the messages, you can use the messages relationship. If you want less, use the last_messages one.
Calling User::with('conversations')->get() does not specify a User. I might be misreading but I think you are looking for something like the following:
$user = User::with('conversations')->find(1);
$userConversations = $user->conversations;
which will provide you with a user and their conversations.
I've found some query result really unexpected.
It's Laravel 5.2
We have following entity:
User with method:
public function roles() : BelongsToMany
{
return $this->belongsToMany(Role::class)->withPivot('timestamp');
}
Each User can have many roles, so we have also Role entity (but it doesn't matter much in my question) and pivot table user_role with timestamp field (and ids of course), because we hold information about time, when User achieved specific role.
I want to get all Users with theirs last assigned Role
When I create query (in User context in some repository):
$this->with(['roles' => function($query) {
$query->orderBy('timestamp', 'desc');
}])->all();
the result will contain Users with Roles entities inside itself ordered by timestamp - it's ok. But I want to retrieve only one last role inside each User entity not all ordered.
So...
$this->with(['roles' => function($query) {
$query->orderBy('timestamp', 'desc')->limit(1);
}])->all();
And then I retrieve Users but only User which achieved some Role for the very last time contains it! All the other Users have their roles field containing empty array.
Why ordering was performed on each Users relation separately, but when I added limit it behaved like a global limit for all.
It drives me crazy...
Thanks for advices.
EDIT
I've created lastRoles() method to get all Roles ordered desc. But all, retrieving one is impossible.
public function lastRoles() : BelongsToMany
{
return $this->BelongsToMany(Roles::class)->withPivot('timestamp')->latest('timestamp');
}
And for testing:
$users = (new User())->with('lastRoles')->get();
But now I must iterate over Users and invoke lastRoles() on each one:
foreach ($users as $user) {
var_dump($user->lastRoles()->get()->first()->name);
}
Then I retrieve names of latest Roles assigned to each User.
So... There is no way to do it in one query? This is the only way?
For this to work, you would need a helper function:
public function latestRole()
{
return $this->hasOne(Role::class)->withPivot('timestamp')->orderBy('timestamp', 'DESC');
}
And then:
$this->with('latestRole')->get();
Credits to this awesome article.
When you eager load a relationship with query constraint(s), the query will be run once to load all relationships, not each one individually. This is the expected behavior. Think about it, eager loading exists to turn many queries into one query in order to optimize performance. There is only one query executed, so your limit constraint will limit the entire result set, rather than on a per model basis.
To circumvent this, you could try creating another belongsToMany method that adds the desired limit constraint. The following code is untested:
public function lastRole() : BelongstoMany
{
return $this->belongsToMany(Role::class)
->withPivot('timestamp')
->orderBy('timestamp', 'desc')
->limit(1);
}
Assuming this works, you can then simply change the relationship method from roles to lastRole and remove your query constraint:
$this->with('lastRole')->all();
So far I was extracting the relation objects as arrays and then doing something like:
App\Model::find($id)
But however is there a way to do something like:
Auth::user()->group()->members()
It works until Auth::user()->group but no further chaining. Please help if you've done something. Or I'm just newbie.
You could use eager loading to load the user's group and then load all of the members of that group.
$user = User::with(['group', 'group.members'])->find(1);
// OR if you already have a user object (Like when using the Auth facade)
$user = Auth::user()->load(['group', 'group.members']);
foreach ($user->group->members as $member) {
// Do something with a member
}
However, if you essentially want to jump down the structure a level, and get all the members related to a user, you could use the hasManyThrough relationship, in that a user has many members, through a group.
// In your User model
public function members()
{
return $this->hasManyThrough(Member::class, Group::class);
}
That way you can simply access the members directly through the user:
$members = Auth::user()->members;
Instead of doing a query to access the user's group and then doing another query to access that group's members, Laravel would use a single query with a join to get you the members.
Take a look at the hasManyThrough relationship here
Try this
Auth::user()->group->members
I am trying to make a twitter like feed in an application, I have a database called connections where inside there's user and follow and another database called feed containing owner which would equal to the follow column in connections.
What I could do if had every id of a follower statically is to use where('owner', '=' $follow) on each follower and return it.
I tried this approach but it wasn't ideal:
Get each follower inside connections;
foreach(follower) {
Get 10 of the latest posts orderBy "created_at";
Push into array;
}
shuffle array;
limit array to 15;
return array;
That also ended with the returned array not being ordered by created date.
How would I use eloquent to get the feed item only if the user follows the owner in the best/simplest way?
Are there any specific Laravel tools that can be used?
Also the database layout isn't fixed as it is, it can be altered if needed to better suite this.
You need to create a many-to-many relationship between the user and itself. See the laravel eloquent documentation http://laravel.com/docs/eloquent#relationships. I didn't test this code but it should be enough to get you started down the right track.
Create a pivot table called "user_following" with:
(int) id, (int) user_id, (int) following_id
Then do something like this:
<?php
// Model
class User extends Eloquent {
public function following()
{
return $this->belongsToMany('User', 'user_following', 'user_id', 'following_id');
}
public function tweets()
{
return $this->hasMany('Tweet')->orderBy('created_at', 'desc');
}
}
// controller
$tweetsOfWhoImFollowing = User::find($id)->following->tweets;