Uploading a file (server to server) with PHP using cURL - php

Question

I have the following php code from my API console on RapidApi working correctly:
<?php
$curl = curl_init();
curl_setopt_array($curl, [
CURLOPT_URL => "https://webit-computer-vision.p.rapidapi.com/describe",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_ENCODING => "",
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 30,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "POST",
CURLOPT_POSTFIELDS => "-----011000010111000001101001\r\nContent-Disposition: form-data; name=\"image\"\r\n\r\n\r\n-----011000010111000001101001--\r\n\r\n",
CURLOPT_HTTPHEADER => [
"content-type: multipart/form-data; boundary=---011000010111000001101001",
"x-rapidapi-host: webit-computer-vision.p.rapidapi.com",
"x-rapidapi-key: XXXXXXXXXX"
],
]);
$response = curl_exec($curl);
$err = curl_error($curl);
curl_close($curl);
if ($err) {
echo "cURL Error #:" . $err;
} else {
echo $response;
}
The only problem is that it also includes a file which is sent to the endpoint. How can I upload file to the given endpoint? The content-type appears to already be set correctly. I believe I just need to send the content of file in addition.

Answer 1

for anyone wondering, I was able to get it working by modifying the header with this code:
CURLOPT_HTTPHEADER => [
"content-type: multipart/form-data",
"x-rapidapi-host: webit-computer-vision.p.rapidapi.com",
"x-rapidapi-key: VMssAjUwitmshMGT0yv1SbvOhkLVp1f3BaqjsnpKZ8t9yLcbxs"
]
and then had to change the following to get the image file to POST properly:
$fields = [
'image' => new \CurlFile("images/2021_04_01_Ied8W_Ex0P-meVoActjCQ.jpg", 'image/jpeg', 'filename.jpg')
];
...
CURLOPT_POSTFIELDS => $fields,
...
started working pretty quickly after that =)