I want my data to be displayed in a row.
Inside my database there are a lot iPhone pictures and some text associated to that particular picture.
I want that data to be shown left to right , I tried and it's working fine for picture NOT for text.
I would like the text to be displayed from left to right instead of top to bottom.
<h2 class="apple">Apple</h2>
<br>
<?php include 'config.php';
$sql="SELECT * FROM apple";
$result=mysqli_query($con, $sql);
if(mysqli_num_rows($result)>0){
while ($fetch=mysqli_fetch_assoc($result)) {
?>
<img src="<?php ECHO $fetch["url"];?>"width="100" height="100" alt="">
<h1> Hello</h1>
<?php
}
}
?>
You can try to display the data in a table with table rows and table data inside it.
<?php
include ('config.php');
echo '<h2 class="apple">Apple</h2>';
$sql = "SELECT * FROM apple";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0) {
echo '<table>';
while ($fetch = mysqli_fetch_all($result)) {
echo '<tr>';
foreach ($fetch as $values) {
echo '<td>'. $values['index of image'] . '</td>';
}
echo '</tr>';
echo '<tr>';
foreach ($fetch as $values) {
echo '<td>'. $values['index of names'] . '</td>';
}
echo '</tr>';
}
echo '</table>';
}
This should get the job done.
Related
I have a database and I am trying to display data from the table all in one box.
I am not sure if there is another way besides tables but I am trying to do something like this.
I am using roblox as an example.
Example:
Right now this is my code for the table.
<div class="row2">
<div class="column">
<?php
include_once("includes/config.php");
$sql = "SELECT * FROM communities";
$result = $conn->query($sql);
if ($result->num_rows > 1) {
while($row = $result->fetch_assoc()) {
echo '<hr />';
echo '<table>';
echo '<tr><td>Name: </td><td>'.$row["name"].'</td></tr>';
echo '<tr><td>Discription:</td><td>'.$row["description"].'</td></tr>';
echo '<tr><td></td><td><img src="'.$row["logo"].'" width="100px" /></td></tr>';
echo '</table>';
echo '<button name="button">Join</button>';
echo '<hr />';
}
}
?>
</div>
I have a database, and am trying to get a list using PHP with foreach, but the list are returning like this:
RiquelmeMacielLewBrMarcuus
But it like so:
RiquelmeMaciel
LewBr
Marcuus
My code:
<?php
include_once("conexao.php");
$select = "SELECT * FROM usuarios ORDER BY id";
$query = mysqli_query($conn, $select);
$rows = mysqli_fetch_assoc($query);
?>
<?php foreach($rows as $row){
echo '<td class="mdl-data-table__cell--non-numeric name">'.$row['nome'].'</td>';
} ?>
You need to insert table rows to create the rows:
<?php
//Incluindo a conexão com banco de dados
include_once("conexao.php");
$result_usuario = "SELECT * FROM usuarios ORDER BY id";
$resultado_usuario = mysqli_query($conn, $result_usuario);
$resultado = mysqli_fetch_assoc($resultado_usuario);
foreach($resultado_usuario as $teste){
echo '<tr>';
echo '<td class="mdl-data-table__cell--non-numeric name">'.$teste['nome'].'</td>';
echo '<td class="mdl-data-table__cell--non-numeric"></td>';
echo '<td class="mdl-data-table__cell--non-numeric"></td>';
echo '</tr>';
}
Now you just need to add in your variables for 'EMAIL' and 'SENHA'.
The problem in your foreach cycle - for eache element you output tag, but is a table cell tag.
If you want fill first column in your 3-column table, you must do something like this:
<?php foreach($resultado_usuario as $teste){
echo '<tr>';
echo '<td class="mdl-data-table__cell--non-numeric name">'.$teste['nome'].'</td>';
echo '<td>second column</td>';
echo '<td>third column</td>';
echo '</tr>';
} ?>
Your are displaying your data the wrong way, your <td> should be inside <tr> which should be inside a <table>:
<table>
<tr>
<th>Nome</th>
<th>Email</th>
<th>Senha</th>
</tr>
<?php
foreach ($resultado_usuario as $teste){
echo '<tr>';
echo '<td class="mdl-data-table__cell--non-numeric name">'.$teste['nome'].'</td>';
echo '<td class="mdl-data-table__cell--non-numeric email">'.$teste['email'].'</td>';
echo '<td class="mdl-data-table__cell--non-numeric senha">'.$teste['senha'].'</td>';
echo '</tr>';
}
?>
</table>
The data will then be displayed as you wanted it. Have a look at HTML - table.
If you want to change the order of your data from your SQL query, use the ORDER BY ... ASC|DESC.
I am bit new to php and sql.
I am simply reading from a database table and echoing images to a page. The images are then styled with a text aligned in the middle saying 'Play Video'.
In the table 'adcTable' some entries do not have a video stored.
I would like to have the rows/entries with video say 'Play Video' and the ones without just show the image.
Not to sure how bess to explain. Hope to get some assistance.
<php
$sql = "SELECT client_id, images, video FROM adcTable";
$result = $conn->query($sql);
$count = 1;
echo "<table border = '0' width='720'><tr>";
while($row = $result->fetch_assoc()) {
echo "<td><div class='ccontainer'>"; ?><img class="cimage" src= "<?php echo $row ["images"];?> " ><?php echo "
<div class='middle'>
<div class='text'>Play Video</div>
</div>
</div>
</td>";
if ($count++ % 2 == 0) {
echo "</tr><tr>";
}
echo "</tr></table>";
?>
Thanks guys, I was able to use the example provided by BusinessPlanQuickBuilder to solve.
$sql = "SELECT client_id, files, file FROM adcTable";
$result = $conn->query($sql);
$count = 1;
echo "<table border = '0' width='720'><tr>";
while($row = $result->fetch_assoc()) {
if ($row['file'] == "VidUploads/"){
echo "<td>"; ?><img class="cimage" src= "<?php echo $row ["files"];?> " ><?php echo "
</td>";
echo '<script type="text/javascript">',
'$( ".text" ).css( "border", "3px solid red" );',
'</script>';
} else{
echo "<td><div class='ccontainer'>"; ?><img class="cimage" src= "<?php echo $row ["files"];?> " ><?php echo "
<div class='middle'>
<div class='text'>Video</div>
</div>
</div>
</td>";
}
if ($count++ % 2 == 0) {
echo "</tr><tr>";
}
}
echo "</tr></table>";
?>
Use if empty condition on video column. This is the fundamental code, add your formatting as required.
<?php
while($row = $result->fetch_assoc()) {
if (empty ($row['video']) ) {
echo $row ["images"];
} else {
echo "Play Video";
}
}
?>
SO reference to related post
i used the crud delete method and it works for me, but when i tried it with a different database and table it keeps saying "Invalid argument supplied for foreach()"
this is my "vacature-verwijderen.php" where you should be able to delete it
<div>
<table id="tabel">
<thead>
<tr>
<th>Functie</th>
<th>Omschrijving</th>
<th>Salaris</th>
</tr>
</thead>
<tbody>
<?php
include 'database.php';
$pdo = Database::connect();
$sql = 'SELECT * FROM vacature ORDER BY id DESC';
foreach ($pdo->query($sql) as $row) {
echo '<tr>';
echo '<td>'. $row['functie'] . '</td>';
echo '<td>'. $row['omschrijving'] . '</td>';
echo '<td>'. $row['salaris'] . '</td>';
echo '<td width=250>';
echo '<a class="button " href="update.php?id='.$row['id'].'">Update</a>';
echo ' ';
echo '<a class="button" href="delete.php?id='.$row['id'].'">Delete</a>';
echo '</td>';
echo '</tr>';
}
Database::disconnect();
?>
</tbody>
</table>
</div>
</div>
and then when you click delete you go to "delete.php" which looks like this
<?php
require 'database.php';
$id = 0;
if ( !empty($_GET['id'])) {
$id = $_REQUEST['id'];
}
if ( !empty($_POST)) {
$id = $_POST['id'];
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "DELETE FROM vacature WHERE id = ?";
$q = $pdo->prepare($sql);
$q->execute(array($id));
Database::disconnect();
header("Location: vacature-verwijderen.php");
}
?>
i don't know what is wrong since it used to work, also my database table looks like this
foreach ($pdo->query($sql) as $row) {
That's what is wrong. $pdo->query($sql) already returns your $row.
Use a while instead so that it do the query and returns you the new row as long as there is data to fetch :
while ($row = $pdo->query($sql)) {
Also :
$sql = "DELETE FROM vacature WHERE id = ?";
The table you provided doesn't contain any field named id, although there is one named vacature_id. You might want to change that too :
$sql = "DELETE FROM vacature WHERE vacature_id = ?";
Don't hesitate to come back if it doesn't solve your issue.
hi i'm disaplyed images from mysql db table but it displays on by one means one row has one image. but i need 3 or 4 image per row. my coding is below. please give some idea.
<?php
include_once("config.php");
$result=mysql_query("SELECT * FROM merchant");
while($res=mysql_fetch_array($result))
{
?>
<?php echo $res['description'];?></p>
<img src="<?php echo $res['image'];?>" width="80" height="80"/>
<?php } ?>
Do it in table like this, You might need to fix it a little bit, but it way how it will work
<table>
<?php
include_once("config.php");
$result=mysql_query("SELECT * FROM merchant");
$count = 0;
while($res=mysql_fetch_array($result))
{
if($count==3) //three images per row
{
print "</tr>";
$count = 0;
}
if($count==0)
print "<tr>";
print "<td>";
?>
<?php echo $res['description'];?></p>
<img src="<?php echo $res['image'];?>" width="80" height="80"/>
<?php
$count++;
print "</td>";
}
if($count>0)
print "</tr>";
?>
</table>
use a <table> to display.
<?php
include_once("config.php");
$result=mysql_query("SELECT * FROM merchant");
$count = 0;
echo '<table>';
while($res = mysql_fetch_array($result))
{
if($count % 2 == 0) echo '<tr>';
?>
<td>
<p><?php echo $res['description'];?></p>
<img src="<?php echo $res['image']; ?>" width="80" height="80"/>
</td>
<?php
if($count % 2 == 0) echo '</tr>';
} ?>