How to dynamically get column value from csv file using php - php

Question

i have two columns in csv file Name and Phone . If i given phone number as a variable $searchStr = "6059574150"; it has to find number in csv file and i need that contact name to get access dynamicaly like this $data['Name'] instead of $data['0']
MY php code
$header = array();
$final_result = array();
$file = fopen('example.csv', 'r');
if($file){
$row = 1;
while ($data = fgetcsv($file, 10000, ",")){
if($row == 1){
$header = array_values($data);
}
else{
$final_result[] = array_combine($header, array_values($data));
}
$row++;
}
}
echo "<pre>";
print_r($final_result);
my output is like this
Array
(
[0] => Array
(
[Names] => MICHAEL
[Phone] => 6059342614
)
[1] => Array
(
[Names] => GLENN
[Phone] => 6056296061
)
)
how to directly access column ? like this $data['Name']

Answer 1

If phone numbers are unique, you could do something like this:
<?php
$final_result = array();
$file = fopen('example.csv', 'r');
if($file) {
$header = fgetcsv($file, 10000, ",");
while ($data = fgetcsv($file, 10000, ",")) {
$final_result[$data[1]] = $data[0];
}
}
?>
If you have more than one name (person) for each phone number, you can concatenate them $final_result[$data[1]] .= ',' . $data[0];.
Example result:
array (
phone1 => 'name1',
phone2 => 'name2',
phone3 => 'name3',
)
To search a name from a phone number you have to do: $final_result[phone_number] and you get the name.
In your output array "$final_result" you can look for a Name by phone number this way:
$foundKey = array_search('pone_number_to_search', array_column($final_result, "Phone"));
$foundNames = $final_result[$foundKey]["Names"];