I have a string containing multiple products orders which have been joined together without a delimiter.
I need to parse the input string and convert sets of three substrings into separate rows of data.
I tried splitting the string using split() and strstr() function, but could not generate the desired result.
How can I convert this statement into different columns?
RM is Malaysian Ringgit
From this statement:
"2 x Brew Coffeee Panas: RM7.42 x Tongkat Ali Ais: RM8.6"
Into seperate row:
2 x Brew Coffeee Panas: RM7.4
2 x Tongkat Ali Ais: RM8.6
And this 2 row into this table in DB:
Table: Products
Product Name
Quantity
Total Amount (RM)
Brew Coffeee Panas
2
7.4
Tongkat Ali Ais
2
8.6
*Note: the "total amount" substrings will reliably have a numeric value with precision to one decimal place.
You could use regex if your string format is consistent. Here's an expression that could do that:
(\d) x (.+?): RM(\d+\.\d)
Basic usage
$re = '/(\d) x (.+?): RM(\d+\.\d)/';
$str = '2 x Brew Coffeee Panas: RM7.42 x Tongkat Ali Ais: RM8.6';
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
var_export($matches);
Which gives
array (
0 =>
array (
0 => '2 x Brew Coffeee Panas: RM7.4',
1 => '2',
2 => 'Brew Coffeee Panas',
3 => '7.4',
),
1 =>
array (
0 => '2 x Tongkat Ali Ais: RM8.6',
1 => '2',
2 => 'Tongkat Ali Ais',
3 => '8.6',
),
)
Group 0 will always be the full match, after that the groups will be quantity, product and price.
Try it online
Capture one or more digits
Match the space, x, space
Capture one or more non-colon characters until the first occuring colon
Match the colon, space, then RM
Capture the float value that has a max decimal length of 1OP says in comment under question: it only take one decimal place for the amount
There are no "lazy quantifiers" in my pattern, so the regex can move most swiftly.
This regex pattern is as Accurate as the sample data and requirement explanation allows, as Efficient as it can be because it only contains greedy quantifiers, as Concise as it can be thanks to the negated character class, and as Readable as the pattern can be made because there are no superfluous characters.
Code: (Demo)
var_export(
preg_match_all('~(\d+) x ([^:]+): RM(\d+\.\d)~', $string, $m)
? array_slice($m, 1) // omit the fullstring matches
: [] // if there are no matches
);
Output:
array (
0 =>
array (
0 => '2',
1 => '2',
),
1 =>
array (
0 => 'Brew Coffeee Panas',
1 => 'Tongkat Ali Ais',
),
2 =>
array (
0 => '7.4',
1 => '8.6',
),
)
You can add the PREG_SET_ORDER argument to the preg_match_all() call to aid in iterating the matches as rows.
preg_match_all('~(\d+) x ([^:]+): RM(\d+\.\d)~', $string, $matches, PREG_SET_ORDER);
foreach ($matches as $match) {
echo '<tr><td>' . implode('</td><td>', array_slice($match, 1)) . '</td></tr>';
}
You can use a regex like this:
/(\d+)\sx\s([^:]+):\sRM(\d+\.?\d?)(?=\d|$)/
Explanation:
(\d+) captures one or more digits
\s matches a whitespace character
([^:]+): captures one or more non : characters that come before a : character (you can also use something like [a-zA-Z0-9\s]+): if you know exactly which characters can exist before the : character - in this case lower case and upper case letters, digits 0 through 9 and whitespace characters)
(\d+\.?\d?) captures one or more digits, followed by a . and another digit if they exist
(?=\d|$) is a positive lookahead which matches a digit after the main expression without including it in the result, or the end of the string
You can also add the PREG_SET_ORDER flag to preg_match_all() to group the results:
PREG_SET_ORDER
Orders results so that $matches[0] is an array of first set of matches, $matches[1] is an array of second set of matches, and so on.
Code example:
<?php
$txt = "2 x Brew Coffeee Panas: RM7.42 x Tongkat Ali Ais: RM8.62 x B026 Kopi Hainan Kecil: RM312 x B006 Kopi Hainan Besar: RM19.5";
$pattern = "/(\d+)\sx\s([^:]+):\sRM(\d+\.?\d?)(?=\d|$)/";
if(preg_match_all($pattern, $txt, $matches, PREG_SET_ORDER)) {
print_r($matches);
}
?>
Output:
Array
(
[0] => Array
(
[0] => 2 x Brew Coffeee Panas: RM7.4
[1] => 2
[2] => Brew Coffeee Panas
[3] => 7.4
)
[1] => Array
(
[0] => 2 x Tongkat Ali Ais: RM8.6
[1] => 2
[2] => Tongkat Ali Ais
[3] => 8.6
)
[2] => Array
(
[0] => 2 x B026 Kopi Hainan Kecil: RM31
[1] => 2
[2] => B026 Kopi Hainan Kecil
[3] => 31
)
[3] => Array
(
[0] => 2 x B006 Kopi Hainan Besar: RM19.5
[1] => 2
[2] => B006 Kopi Hainan Besar
[3] => 19.5
)
)
See it live here php live editor and here regex tester.
The first thing I would do would be to perform a simple replacement using preg_replace to insert, with the aid of a a back-reference to the captured item, based upon the known format of a single decimal point. Anything beyond that single decimal point forms part of the next item - the quantity in this case.
$str="2 x Brew Coffeee Panas: RM7.42 x Tongkat Ali Ais: RM8.625 x Koala Kebabs: RM15.23 x Fried Squirrel Fritters: RM32.4";
# qty price
# 2 7.4
# 2 8.6
# 25 15.2
# 3 32.4
/*
Our RegEx to find the decimal precision,
to split the string apart and the quantity
*/
$pttns=(object)array(
'repchar' => '#(RM\d{1,}\.\d{1})#',
'splitter' => '#(\|)#',
'combo' => '#^((\d{1,}) x)(.*): RM(\d{1,}\.\d{1})$#'
);
# create a new version of the string with our specified delimiter - the PIPE
$str = preg_replace( $pttns->repchar, '$1|', $str );
# split the string intp pieces - discard empty items
$a=array_filter( preg_split( $pttns->splitter, $str, null ) );
#iterate through matches - find the quantity,item & price
foreach($a as $str){
preg_match($pttns->combo,$str,$matches);
$qty=$matches[2];
$item=$matches[3];
$price=$matches[4];
printf('%s %d %d<br />',$item,$qty,$price);
}
Which yields:
Brew Coffeee Panas 2 7
Tongkat Ali Ais 2 8
Koala Kebabs 25 15
Fried Squirrel Fritters 3 32
Related
I have a database full of strings that I'd like to split into an array. Each string contains a list of directions that begin with a letter (U, D, L, R for Up, Down, Left, Right) and a number to tell how far to go in that direction.
Here is an example of one string.
$string = "U29R45U2L5D2L16";
My desired result:
['U29', 'R45', 'U2', 'L5', 'D2', 'L16']
I thought I could just loop through the string, but I don't know how to tell if the number is one or more spaces in length.
You can use preg_split to break up the string, splitting on something which looks like a U,L,D or R followed by numbers and using the PREG_SPLIT_DELIM_CAPTURE to keep the split text:
$string = "U29R45U2L5D2L16";
print_r(preg_split('/([UDLR]\d+)/', $string, -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY));
Output:
Array (
[0] => U29
[1] => R45
[2] => U2
[3] => L5
[4] => D2
[5] => L16
)
Demo on 3v4l.org
A regular expression should help you:
<?php
$string = "U29R45U2L5D2L16";
preg_match_all("/[A-Z]\d+/", $string, $matches);
var_dump($matches);
Because this task is about text extraction and not about text validation, you can merely split on the zer-width position after one or more digits. In other words, match one or more digits, then forget them with \K so that they are not consumed while splitting.
Code: (Demo)
$string = "U29R45U2L5D2L16";
var_export(
preg_split(
'/\d+\K/',
$string,
0,
PREG_SPLIT_NO_EMPTY
)
);
Output:
array (
0 => 'U29',
1 => 'R45',
2 => 'U2',
3 => 'L5',
4 => 'D2',
5 => 'L16',
)
I'm looking to extract GTIN codes from documents, they're 8, 12, 13 or 14 digit numbers. So I'm doing this:
$html = '8 digit 12345678 and now 12 digit 123456789012';
$extractGTIN = '/\d{7}$|^\d{11}$|^\d{12}$|^\d{13}/mi';
preg_match_all($extractGTIN, $html, $barcodes);
echo print_r ($barcodes, 1);
... but unexpectedly, it returns:
Array
(
[0] => Array
(
[0] => 6789012
)
)
You have not anchored the alternatives properly, use word boundaries. Instead of alternations, you may use an optional group here:
/\b\d{8}(?:\d{4,6})?\b/
See the regex demo.
Details:
\b - a leading word boundary
\d{8} - 8 digits
(?:\d{4,6})? - an optional sequence of 4, 5 or 6 digits (thus, matching all in all 8, 12, 13, 14 digits)
\b - trailing word boundary.
PHP demo:
$text = '8 digit 12345678 and now 12 digit 123456789012';
$extractGTIN = '/\b\d{8}(?:\d{4,6})?\b/';
preg_match_all($extractGTIN, $text, $barcodes);
print_r($barcodes[0]);
// => Array ( [0] => 12345678 [1] => 123456789012 )
I split this:
1 2 3 4/5/6 "7/8 9" 10
into this:
1
2
3
4
5
6
"7/8 9"
10
with preg_split()
So my question is, how do I split based on a delimiter, excluding delimiters inside a pair of quotes?
I kind of want to avoid capturing the things in quotes first and would ideally like it to be a one liner.
You can use the following.
$text = '1 2 3 4/5/6 "7/8 9" 10';
$results = preg_split('~"[^"]*"(*SKIP)(*F)|[ /]+~', $text);
print_r($results);
Explanation:
On the left side of the alternation operator we match anything in quotations making the subpattern fail, forcing the regular expression engine to not retry the substring using backtracking control with (*SKIP) and (*F). The right side of the alternation operator matches either a space character or a forward slash not in quotations.
Output
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => "7/8 9"
[7] => 10
)
You can use:
$s = '1 2 3 4/5/6 "7/8 9" 10';
$arr = preg_split('~("[^"]*")|[ /]+~', $s, -1, PREG_SPLIT_DELIM_CAPTURE|PREG_SPLIT_NO_EMPTY);
print_r( $arr );
OUTPUT:
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => "7/8 9"
[7] => 10
)
An other way with an optional group:
$arr = preg_split('~(?:"[^"]*")?\K[/\s]+~', $s);
The pattern "[^"]*"[/\s]+ matches a quoted part followed by one or more spaces and slashes. But since you don't want to remove quoted parts, you put a \K after it. The \K removes all that have been matched on the left from the match result. With this trick, when a quoted part is found the regex engine returns only spaces or slashes after and split on them.
Since there are not always a quoted part before a space or a slash, you only need to make it optional with a non-capturing group (?:...) and a question mark ?
I was wondering how can I create preg_match for catching:
id=4
4 being any number and how can I search for the above example in a string?
If this is could be correct /^id=[0-9]/, the reason why I'm asking is because I'm not really good with preg_match.
for 4 being any number, we must set the range for it:
/^id\=[0-9]+/
\escape the equal-sign, plus after the number means 1 or even more.
You should go with the the following:
/id=(\d+)/g
Explanations:
id= - Literal id=
(\d+) - Capturing group 0-9 a character range between 0 and 9; + - repeating infinite times
/g - modifier: global. All matches (don't return on first match)
Example online
If you want to grab all ids and its values in PHP you could go with:
$string = "There are three ids: id=10 and id=12 and id=100";
preg_match_all("/id=(\d+)/", $string, $matches);
print_r($matches);
Output:
Array
(
[0] => Array
(
[0] => id=10
[1] => id=12
[2] => id=100
)
[1] => Array
(
[0] => 10
[1] => 12
[2] => 100
)
)
Example online
Note: If you want to match all you must use /g modifier. PHP doesn't support it but has other function for that which is preg_match_all. All you need to do is remove the g from the regex.
For example I have the text
a1aabca2aa3adefa4a
I want to extract 2 and 3 with a regex between abc and def, so 1 and 4 should be not included in the result.
I tried this
if(preg_match_all('#abc(?:a(\d)a)+def#is', file_get_contents('test.txt'), $m, PREG_SET_ORDER))
print_r($m);
I get this
> Array
(
[0] => Array
(
[0] => abca1aa2adef
[1] => 3
)
)
But I want this
Array
(
[0] => Array
(
[0] => abca1aa2adef
[1] => 2
[2] => 3
)
)
Is this possible with one preg_match_all call? How can I do it?
Thanks
preg_match_all(
'/\d # match a digit
(?=.*def) # only if followed by <anything> + def
(?!.*abc) # and not followed by <anything> + abc
/x',
$subject, $result, PREG_PATTERN_ORDER);
$result = $result[0];
works on your example. It assumes that there is exactly one instance of abc and def per line in your string.
The reason why your attempt didn't work is that your capturing group (\d) that matches the digit is within another, repeated group (?:a(\d)a)+. With every repetition, the result of the capture is overwritten. This is how regular expressions work.
In other words - see what's happening during the match:
Current position Current part of regex Capturing group 1
--------------------------------------------------------------
a1a no match, advancing... undefined
abc abc undefined
a2a (?:a(\d)a) 2
a3a (?:a(\d)a) (repeated) 3 (overwrites 2)
def def 3
You ask if it is possible with a single preg_match_all.
Indeed it is.
This code outputs exactly what you want.
<?php
$subject='a1aabca2aa3adefa4a';
$pattern='/abc(?:a(\d)a+(\d)a)def/m';
preg_match_all($pattern, $subject, $all_matches,PREG_OFFSET_CAPTURE | PREG_PATTERN_ORDER);
$res[0]=$all_matches[0][0][0];
$res[1]=$all_matches[1][0][0];
$res[2]=$all_matches[2][0][0];
var_dump($res);
?>
Here is the output:
array
0 => string 'abca2aa3adef' (length=12)
1 => string '2' (length=1)
2 => string '3' (length=1)