Can I get a specific JSON value by Id? - php

Question

I would like to have the corresponding date of typeId: 11 output from the following JSON.
The order of the typeId's is always different, so it doesn't always work, for example, to always address the second value.
{
"page": 1,
"totalsCount": 1,
"isLastPage": true,
"lastPageNumber": 1,
"firstOnPage": 1,
"lastOnPage": 1,
"itemsPerPage": 50,
"entries": [
{
"id": 60132,
"statusName": "GIT",
"dates": [
{
"orderId": 60132,
"typeId": 7,
"date": "2021-06-03T00:00:00+02:00"
},
{
"orderId": 60132,
"typeId": 11,
"date": "2021-05-28T00:00:00+02:00"
},
{
"orderId": 60132,
"typeId": 16,
"date": "2021-05-27T20:20:28+02:00"
},
{
"orderId": 60132,
"typeId": 2,
"date": "2021-05-27T20:19:21+02:00"
},
{
"orderId": 60132,
"typeId": 4,
"date": "2021-06-03T15:16:14+02:00"
}
]
}
]
}
With my approach so far, I don't get any result:
$json = file_get_contents($orders);
$arr = json_decode($orders);
foreach($arr->entries as $order => $value) {
echo '<th scope="row">' . $value->dates->[typeId='11'].date . '</th>';
}
Where is my mistake here?

Answer 1

You could use array_map():
<?php
$arr = json_decode($json, true);
$result = array_filter(
array_map(
function ($record) {if($record['typeId'] == 11) return $record['date'];}, $arr['dates']
)
);
use array_filter() to remove empty values from the result-set.
working demo
EDIT
With updated json information, you could use:
$obj = json_decode($json);
foreach($obj->entries[0]->dates as $order => $value) {
if($value->typeId == 11) echo '<th scope="row">' . $value->date . '</th>';
}
working demo

Answer 2

For this kind of situation i usually write a simple function like this:
function getDate(array $dates, $typeId) {
foreach ($dates as $date) {
if ($date['typeId'] === $typeId) {
return $date;
}
}
return null;
}

Answer 3

Because the dates is an array you have to iterate over and filter out the proper elements by typeId.
Something like this:
dates.filter(({typeId}) => typeId === 11).shift().date