Display table count in html - php

Question

I trying to create the backend for a booking system and need to show all booked appointments on each date for each location. My appointments table looks like this:
id, booked_date, location_id, customer_id
and I would like to display this in a html table like this:
Date 1
Date 2
Location 1 Name
Number of booked appointments
Number of booked appointments
Location 2 Name
Number of booked appointments
Number of booked appointments
I have a separate table of Locations that has full details like and and address.
I also have a table of event dates (id, start_date)
Im struggling to comprehend what I need to do here!
EDIT:
I just need some help putting everything together into the example table above.
Database tables : appointments, locations, event_dates
I have this query and the function below - SELECT t1.location_id, t1.start_datetime, t2.name, COUNT(*) AS count FROM appointment t1 INNER JOIN location t2 ON t1.location_id = t2.id GROUP BY t1.location_id, t1.start_datetime
function countAppointment() {
require 'config.php';
$sql = "SELECT t1.location_id, t1.start_datetime, t2.name, COUNT(*) AS count
FROM appointment t1
INNER JOIN location t2
ON t1.location_id = t2.id
GROUP BY t1.location_id, t1.start_datetime";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$a1 = $row['start_datetime'];
$a2 = $row['location_id'];
$a3 = $row['name'];
$a4 = $row['count'];
//echo "$a1 <br> $a2 <br> $a3 <br> $a4 <br><br>";
echo "<tr><th scope='row'>$a3</th>";
echo "<td><a href='#'>$a4</a></td>";
echo "<td>9</td><td>27</td><td>14</td></tr>";
}
} else {
return "0";
}
$conn->close();
}

Answer 1

try this code
<?php
$con = new mysqli("localhost","root","","test");
// Check connection
if ($con -> connect_errno) {
echo "Failed to connect to MySQL: " . $con -> connect_error;
exit();
}
$data = array();
$date_list= array();
$sql_date_list ="SELECT start_datetime from appointment GROUP BY start_datetime";
$result_date_list = mysqli_query($con, $sql_date_list);
$sql_loc_list = "SELECT `name` FROM `location` GROUP BY `name`";
$result_loc_list = mysqli_query($con, $sql_loc_list);
$k=0;
while ($row =mysqli_fetch_assoc($result_loc_list)){
$data +=[$row['name']=>array()];
if($k==0){
while($row2 =mysqli_fetch_assoc($result_date_list)){
array_push($date_list,$row2['start_datetime']);
$data[$row['name']]+=[$row2['start_datetime']=>0];
}
$k++;
}else{
foreach($date_list as $date){
$data[$row['name']]+=[$date=>0];
}
}
}
$sql_getdata = "SELECT t2.name as loc_name, t1.start_datetime, COUNT(t1.location_id) AS count FROM appointment t1 JOIN location t2 ON t1.location_id = t2.id GROUP BY t1.location_id,t1.start_datetime";
$result = mysqli_query($con, $sql_getdata);
while($row =mysqli_fetch_assoc($result)){
$data[$row['loc_name']][$row['start_datetime']]=$row['count'];
}
$table="<table border='1'>";
$table.="<tr>";
$table.="<th>location</th>";
foreach ($date_list as $date) {
$table.="<th>".$date."</th>";
}
$table.="</tr>";
foreach ($data as $key=>$date) {
$table.="<tr>";
$table.="<td>".$key."</td>";
foreach($date as $key2=>$count){
$table.="<td>".$count."</td>";
}
$table.="</tr>";
}
$table.="<table>";
echo $table;
?>
output